<![CDATA[Simple replace / to hard for me]]>Hi, can anyone please help me with this simple problem?

in a file I need to search for numbers like this:

*1234567890

the numbers are always changing, but I need to get the Asterisk (*) removed.

the replacement dosen’t need to be the same number, just the Asterisk need to be removed.

so from this: *1234567890
to this : 0000000000

would be fine!

Thanks if anyone can help!

Regards, Sascha

]]>https://community.notepad-plus-plus.org/topic/11574/simple-replace-to-hard-for-meRSS for NodeFri, 17 Apr 2026 11:50:54 GMTTue, 05 Apr 2016 15:06:08 GMT60<![CDATA[Reply to Simple replace / to hard for me on Tue, 05 Apr 2016 16:21:09 GMT]]>worked! Thanks Claudia!

]]>https://community.notepad-plus-plus.org/post/15174https://community.notepad-plus-plus.org/post/15174Tue, 05 Apr 2016 16:21:09 GMT<![CDATA[Reply to Simple replace / to hard for me on Tue, 05 Apr 2016 15:37:26 GMT]]>In find what replace the + with {10}

\*(\d{10})

Cheers
Claudia

]]>https://community.notepad-plus-plus.org/post/15170https://community.notepad-plus-plus.org/post/15170Tue, 05 Apr 2016 15:37:26 GMT<![CDATA[Reply to Simple replace / to hard for me on Tue, 05 Apr 2016 15:30:43 GMT]]>Thanks, but it should only replace numbers with 10 digits… there are a lot of numbers in that file, only if the number has a leading * and is followed by 10 digits it should be replaced.

]]>https://community.notepad-plus-plus.org/post/15169https://community.notepad-plus-plus.org/post/15169Tue, 05 Apr 2016 15:30:43 GMT<![CDATA[Reply to Simple replace / to hard for me on Tue, 05 Apr 2016 15:25:38 GMT]]>Hello @Sascha-Holliger,

in replace dialog check regular expression.

Find what:\*(\d+)
Replace with:\1

as * is a known char in regex we need to escape with \
(\d+) = this matches any size of numbers and get stored in \1

Cheers
Claudia

]]>https://community.notepad-plus-plus.org/post/15168https://community.notepad-plus-plus.org/post/15168Tue, 05 Apr 2016 15:25:38 GMT