Very easily, indeed ! No need for a script language to achieve that simple task. Just use a regular expression search/replacement.

• Open the Replace dialog

• Type in (?-s)^.+ in the Find what: zone

• Type in $0\x20$0 in the Replace with: zone

• Select the wrap around ( or the In selection option if you restrict replacement to a previous selection )

• Click on the Replace All option

That regex replaces any text, of a line, with two copies of that text, separated by a space character, in the same line !

So, from the initial text :

This is
a test
12345
1.txt
2.txt
3.txt
*--*

You obtain, after replacement,

This is This is
a test a test
12345 12345
1.txt 1.txt
2.txt 2.txt
3.txt 3.txt
*--* *--*

Notes :

• The (?-s) modifier ensures that the special . character will match a single standard character, only, and not the End of Line characters

• Then, the part .+ represents any non-empty range of standard characters , of each line, starting at beginning of line ( ^ )

• In replacement, we rewrite the overall match ( $0 ), followed with a space character ( \x20 ), and, finally, followed again with the overall match ( $0 )

Remarks :

• In replacement, you may insert a simple space character ( or more, if necessary ) , instead of the \x20 syntax

• You may, also, write multiple copies, of each initial line, in the same line. For instance, with the initial text, above, the regex S/R :

SEARCH (?-s)^.+

REPLACE Line repeated 3 times : | $0 | $0 | $0 |

would product the following test :

Line repeated 3 times : | This is | This is | This is |
Line repeated 3 times : | a test | a test | a test |
Line repeated 3 times : | 12345 | 12345 | 12345 |
Line repeated 3 times : | 1.txt | 1.txt | 1.txt |
Line repeated 3 times : | 2.txt | 2.txt | 2.txt |
Line repeated 3 times : | 3.txt | 3.txt | 3.txt |
Line repeated 3 times : | *--* | *--* | *--* |

Best Regards,

guy038