@hans-dampf, I strongly advice you to study the regexes’s world , beginning with the excellent tutorial of the Regular-Expressions.info site, below :

https://www.regular-expressions.info/tutorialcnt.html

It will certainly take you a few weeks to get an overview of the syntax of regular expressions, but it’s really worth it. ;-))

If you are in a hurry, see this part :

https://www.regular-expressions.info/shorthand.html

Moreover, regarding your second regex construction (?<=text":")*(","), this syntax seems incorrect as the quantifier *, meaning repeated 0 or more times should be, either, preceded with a character, like s*, an expression embedded with parentheses like (123)*, a character class, like [abc]* or a shorthand class, like \h*. But, it should not follow a look-behind construction !

However, I was really surprised that our Boost regex engine does not consider it as invalid !?

To explain this behavior, let us, first, consider the simple regex (?<=abc)def which searches for the string def only if  preceded with the string abc. If you add the same look-behind, giving the regex (?<=abc)(?<=abc)def it will do the same search, because look-arounds are just zero-length assertions and because they both refer about the same condition !

You could add as many identical look-behind to get the same result ( For instance (?<=abc)(?<=abc)(?<=abc)(?<=abc)(?<=abc)def would match any string def, if preceded with the string abc ! )

Indeed, the *, right after the look-behind, is taken as a real quantifier. As consecutive values are useless, the unique interesting case seems to be (?<=abc)?def which would search for the string def OR for the string def only if  preceded with the string abc. Of course, due to Boole algebra, this regex could just be simplified as the search of def ;-))

To be convinced you of that fact, consider the text, below :

1 ","
2 text":"","
3 ABCD":"","

• The regexes "," or (?<=text":")*"," or (?<=text":")?"," would find the string ",", in the three lines

• The regexes (?<=text":")"," or (?<=text":")+"," or (?<=text":"){1}"," or (?<=text":"){10}"," would find the string "," in line 2 only

Best Regards,

guy038

I read that “\ D” stands for letters

No \D stands for a non-digit. \d stands for a digit, and is the same as [0-9]. Thus \D would match anything but 0123456789.

I’m not sure what to make of your expression, except to say that “You tried!” :-)

I try to learn and understand what I’m doing … ;-)

The oddest part of your expression might be \D which means “match anything except a digit”.

I read that “\ D” stands for letters …
With the flag \ D, I got this output:

Without \ D only this:

\K is kind of a “start again” flag. What comes to the left has to match, but it isn’t part of the match. The matched text is only what appears to the right of the final \K in an expression.

I’m not sure what to make of your expression, except to say that “You tried!” :-)

The oddest part of your expression might be \D which means “match anything except a digit”.

We have more info about regular expressions by following this link:
https://community.notepad-plus-plus.org/topic/15765/faq-desk-where-to-find-regex-documentation

(?-is)text":“\K.+?(?=”)

Oh wow!
It works!
Many, many thanks and a Merry Christmas time!

I have a question about the \ K. +? flag …
If they were kind enough to explain it briefly so that I can understand it better.
I had already found a partial solution myself, but in the end it was “.” selected with.
(? <= Text “:”) \ D * (")

You expressed yourself well.

How about trying to search for (?-is)text":"\K.+?(?=")