Here is my very similar version :

SEARCH (?-s)(?:^.+(?:(\R)|\Z)){1,3}

[word]\1$0

Group \1 contains the current EOL char(s) of the file

Best Regards,

guy038

I would try searching for (?-s)^(?:.*\R){3} and replacing with [word]$0. Search mode = Regular expression

Thank you very much, it’s do the job for me :)

Ha, didn’t even notice that. Well, I guess the OP is most of the way there.

I would try searching for (?-s)^(?:.*\R){3} and replacing with [word]$0. Search mode = Regular expression

Something similar was my first thought, but that doesn’t get the [word] before the p and q lines, which was in the original spec. I guess, like my solution, @hasan123 could manually do one [word] insertion. :-)

This will get you most of the way there:

1. use Ctrl+Home to make sure you are at the start of the file
2. search/replace

• FIND = (?-s).+\R.+\R.+(\R|\Z)\K
• REPLACE = [word] or [word]\r\n
• disable ☐ wrap around
• mode = regular expression

3. Ctrl+Home then manually insert [word] at the start of the file.

I tried for some alternation, using \A^|... or similar to get it to also replace at the start of the file, but five minutes of experimenting wasn’t enough to get it to work. Maybe @guy038 will chime in with an all-in-one, but for me, the curiosity of knowing how to get it in one regex doesn’t outweigh the additional time beyond 5min for exploring the intricacies of regex, when a few seconds of typing will add in the missing [word] at the beginning of the file.