Indeed, as noticed, below, in the Special characters section :

https://www.regular-expressions.info/characters.html

There are only 12 special regex characters and, both, the closing square bracket ] and the closing curly bracket } are not part of this set !

Cheers,

guy038

(?-s)^\h*“north”: {“uv”: [.+], “texture”: “#missing”},\R

(?-s)^\h*"north": \{"uv": \[.+], "texture": "#missing"},\R
                              ^                       ^

Interesting to note that the characters indicated above don’t need to be escaped, but only a true regex god would remember this, and mere mortals would probably escape them thusly:

(?-s)^\h*"north": \{"uv": \[.+\], "texture": "#missing"\},\R
                              ^^                       ^^

Just use the following regex S/R :

SEARCH (?-s)^\h*"north": \{"uv": \\[.+], "texture": "#missing"},\R

REPlACE Leave EMPTY

Notes :

• First, the in-line modifier (?-s) forces the regex engine to consider any regex dot symbol ( . ) to match a single standard char only and not any EOL char

• Then, from beginning of line ( ^ ), possibly followed with horizontal blanks chars, as Tab, Space ( \h* ),

• It tries to match the string “north”: {“uv”: [, with the regex part "north": \{"uv": \\[.

• Note that the special opening regex symbols {, beginning a quantifier and [, beginning a character class, must be escaped, as \{ and \\[, to be interpreted as literals !

• It also tries to match the string ], “texture”: “#missing”}, and its line-break, with the final regex part ], "texture": "#missing"},\R

• With any non-null range of characters .+ between these two strings

• As the replacement zone is empty , any current line matched, with its line-break, is then deleted

Best Regards,

guy038