Both codes worked like a charm.

For anyone interested in these codes, @Ekopalypse 's code finds every space-separated pair of words starting with a capital letter , and @guy038 's code finds every space between words starting with a capital letter. Both were good for what I needed to do!

An alternate solution to @ekopalypse’s one could be :

SEARCH (?-i)\u\w+\K\h+(?=\u\w*+(?!'))

REPLACE =

Notes :

• First the (?-i) in-line modifier tells the regex engine to run the search in a NON-insensitive way

• Then the part \u\w+ looks a word with a first upper-case letter followed with a non-null range of word characters

• And the part \K resets the regex engine position of search and cancels the match, so far

• Therefore, it searches, now, for a non-null range of horizontal blank characters \h+ ( Tabs and/or Spaces ) …

• But ONLY IF  a double condition is true, due to the nested look-aheads structure :

  • It must be followed with an other word, of at least 1 upper-case letter, with possible subsequent word character(s), which…

  • Must not be followed with a single quote '. Thus, it eliminates cases of contractions such as “I’m, You’re, We’d,…”

• In order that the negative look-ahead (?!') works as expected, we need to place the + regex symbol, after the part \w*, to set this group of word char(s) as an atomic group and, therefore, prevent the regex engine from backtracking inside it !

• Note, also, that all text matched by the regexes, in look-arounds, are never part of the overall match

• In replacement, the blank character(s) matched is/are replaced with one equal sign =

Best Regards,

guy038

I assume this might work

find what:([A-Z]\w+)(\h+)([A-Z]\w+)
replace with:\1=\3
make sure match case has been checked