why does this parsing not work? Replace the content of html tags between comments section

Reply to why does this parsing not work? Replace the content of html tags between comments section on Tue, 15 Jun 2021 08:35:42 GMT

Robin Cruise — Tue, 15 Jun 2021 08:35:42 GMT

I found a solution that works with PowerShell, that will replace all lines with the canonical link tag:

$sourcedir = "C:\Folder1\"
$resultsdir = "C:\Folder1\"

Get-ChildItem -Path $sourcedir -Filter *.html | ForEach-Object {
    $content = Get-Content -Path $_.FullName -Raw
    $replaceValue = (Select-String -InputObject $content -Pattern '(?<=)').Matches.Value
    $content = $content -replace 'https:\/\/.+.html',$replaceValue
    Set-Content -Path $resultsdir\$($_.name) $content
}

Reply to why does this parsing not work? Replace the content of html tags between comments section on Wed, 02 Jun 2021 03:06:57 GMT

Robin Cruise — Wed, 02 Jun 2021 03:06:57 GMT

thanks @guy038

Reply to why does this parsing not work? Replace the content of html tags between comments section on Tue, 01 Jun 2021 15:25:12 GMT

guy038 — Tue, 01 Jun 2021 15:25:12 GMT

Hi, @robin-cruise and All,

The general problem is how to modify some lines with an expression ( https://website.com/en/camera.html ), located before these lines ? Somehow, we need to rewrite the address, in the tag somewhere, after the lines to modify !

So I propose to decompose the problem in two smaller ones :

Firstly, we store in a comment, at the very end of each HTML file, the address located in the tag with this regex S/R :

SEARCH (?-is)


REPLACE \r\n


Secondly :


We replace the address, in each We delete this temporary comment, as well





With this regex S/R :
SEARCH (?-is)REPLACE ?1\1

Best Regards,
guy038

Reply to why does this parsing not work? Replace the content of html tags between comments section on Tue, 01 Jun 2021 14:24:16 GMT guy038 — Tue, 01 Jun 2021 14:24:16 GMT Hello @robin-cruise , Sorry, I spent a lot of time with the @xaviermdq’s problem ! Refer here ! I won’t be long. I’ve already imagined something which should work ! BR guy038 Reply to why does this parsing not work? Replace the content of html tags between comments section on Tue, 01 Jun 2021 14:17:34 GMT Robin Cruise — Tue, 01 Jun 2021 14:17:34 GMT can you help me @guy038 ? Reply to why does this parsing not work? Replace the content of html tags between comments section on Tue, 01 Jun 2021 03:00:42 GMT Robin Cruise — Tue, 01 Jun 2021 03:00:42 GMT hello @guy038 yes, occurs only once, in each HTML file. and yes, that line come always before the different canonical line is at about the beginning of the file all those Hi @robin-cruise, Can you specify if the line occurs only once, in each HTML file ? Does this line come always before the different TIA, Cheers guy038 Reply to why does this parsing not work? Replace the content of html tags between comments section on Mon, 31 May 2021 16:16:40 GMT Robin Cruise — Mon, 31 May 2021 16:16:40 GMT thank you. also, maybe @guy038 can help me with a similar problem: I have this 4 lines: and I want to copy https://website.com/en/camera.html from canonical tag, and copy/replace those 3 links on other line with it. My regex change only the first of the first three, don’t know why :( Search: (?s).*?The pattern I follow is: FIND: (?s)PART-A(.*?)PART-B.*?SECOND-A\K.*?(?=SECOND-2) REPLACE BY: \1 The output: Reply to why does this parsing not work? Replace the content of html tags between comments section on Mon, 31 May 2021 11:41:56 GMT guy038 — Mon, 31 May 2021 11:41:56 GMT Hello, @robin-cruise and All, Firstly, I just cannot understand your last regex S/R : SEARCH (?:.*?|\G).*?\K (.*?)(?= .*?) 1 REPLACE \2\1\3 Indeed, in replacement, you have three groups 1, 2 and 3 but your search regex contains only one group (.*?) !? I verified that, after each replace operation, the groups 2 and 3 are always empty ! Secondly, you should have expressed your initial goal as : " I have some Some Text zones and I would like to change them into SAME Text " It’s a little bit clearer ! Thirdly : You could had added the (?s) modifier, at beginning of your regex, in order to not care about the . matches newline option ! You could had used used the more accurate ^\h* syntax, instead of .*?, at beginning of the non-capturing group You could had added the negative look-around (?!\A), right before the \G assertion. Indeed, as the Wrap around option is set, the regex engine starts the replacement process from the very beginning of file, whatever the current caret location, and the (?!\A) syntax ensures that the regex engine will not used the second alternative \G but will look, instead, for a line, first ! Fourthly, your regex cannot work with, for instance, the text below, where I duplicated your initial example and, in between, I inserted the same section, without the boundaries and United Romaketh Marcus 33 Can you tell me? I am here My text here I am here my dauther loves me Love Me tender United Romaketh Marcus 33 Can you tell me? I am here My text here I am here my dauther loves me Love Me tender United Romaketh Marcus 33 Can you tell me? I am here My text here I am here my dauther loves me Love Me tender Finally, we should use, from this post, the generic regex S/R, below : SEARCH (?-i:BSR|(?!\A)\G)(?s-i:(?!ESR).)*?\K(?-i:FR) REPLACE RR with : BSR ( Begin Search-region Regex ) = ^\h* ESR ( End Search-region Regex ) = ^\h* FR ( Find Regex ) = FR ( Find Regex ) = This leads to the effective regex : SEARCH (?-i:^\h*|(?!\A)\G)(?s-i:(?!^\h*).)*?\K(?-i: ) REPLACE But, as the -i modifier is used everywhere and as the (?s) dot is used for a single ., only, we can even simplify the S/R as : SEARCH (?s-i)(?:^\h*|(?!\A)\G)(?:(?!^\h*).)*?\K REPLACE which correctly matches 6 occurrences in my above example ( = 3 x 2 zones ••••• ) ! Best Regards, guy038 Reply to why does this parsing not work? Replace the content of html tags between comments section on Mon, 31 May 2021 08:57:33 GMT Robin Cruise — Mon, 31 May 2021 08:57:33 GMT @Robin-Cruise said in why does this parsing not work? Replace the content of html tags between comments section: (?:.?|\G).?\K( ).?(?= .?) I find the answer, thanks: FIND: (?:.*?|\G).*?\K (.*?)(?= .*?) Replace by: \2\1\3 CHECK Wrap around CHECK Regular expression CHECK . matches newline