In the search regex (?s)(https://xxx.com/en/)([^"]+)".+?\1(?!\2").+?" :

• The regex part https://xxx.com/en/ looks for the literal string https://xxx.com/en/, stored as group 1

• The regex part ([^"]+)" represents the remainder of the internet address ( for instance the string page-AAA.html ), followed with a double-quote, because [^"]+ is a non-null range of consecutive chars, all different from ", stored as group 2

• Now, the part .+? stands for the shortest range of any char till…

  • The group 1 ( \1 ). So an other string https://xxx.com/en/

  • Which must be followed by .+?", which represents the shortest non-null range of any char before a double-quote…

  • But ONLY IF this range is different from \2 ( i.e. different, for instance, from the string page-AAA.html and a " char )

Note also that the [^"]+" syntax, without the parentheses, is more restrictive than .+?" and must be preferred because of the negative look-ahead (?!\2")

Besst Regards,

guy038

\1(?!\2")

Let’s suppose you have, at least, two links of the form https://xxx.com/en/••••••••••.••••, where the part ••••••••••.•••• is different.

Then, the regex (?s)(https://xxx.com/en/)([^"]+)".+?\1(?!\2").+?" will match the range between these two links, included !

Thus, the regex does not match anything if all the https://xxx.com/en/••••••••••.•••• , of current file, have the same ••••••••••.•••• part.

Best Regards,

guy038