(?s)^(?:[^\r\n;];){N}.{0,3996}\r\n|^((?:[^\r\n;];){N}.{0,3996}).?\r\n|^(?:[^\r\n;]?)\r\n

Unfortunately, your regular expression was corrupted because you didn’t post it correctly.
Probably a moderator will come along and examine your “raw” original post and correct it.

(?s)^(?:[^\r\n;]*;){N}.{0,3996}\r\n|^((?:[^\r\n;]*;){N}.{0,3996}).*?\r\n|^(?:[^\r\n;]*?)\r\n

N normal fields + 1 memo-field that contains linefeeds in the text.

In Oracle i created an external file based on the CSV-file with truncated memo field.
It proofed impossible to read 4000 characters because the \r\n is taken into the fieldvalue.
Once in Oracle the linefeeds are counted as single characters, but i think that is based on codeset-settings. When counting the length of the oracle CHAR(4000 CHAR) field i found a max length of 3970 instead of 3996 as my truncate position.
Keep this in mind otherwise you will get problems with reject limits.

-–

moderator added code markdown around text; please don’t forget to use the </> button to mark example text as “code” so that characters don’t get changed by the forum

My latest testfile was like this:

My search pattern is now:
(?s)^(?:[^\r\n;];){3}.{0,24}\r\n|^((?:[^\r\n;];){3}.{0,24}).?\r\n|^(?:[^\r\n;]?)\r\n

The replace statement is still yours:
?1$1\r\n:$0

Result was:

I tried to figure out the replace string, but i don’t get it.
(tried selfstudy on it with Regex0101 tool bit by bit but since it is not 100% compatible i couldn’t figure it out myself.) Really no lazyness on my part here when i ask my question.
So i hope you can explain it step by step for me.

Thanks!

Amen. Don’t change posts after posting them, unless you are 100% sure you aren’t changing any meaning. That is, only change an obvious typo (but NOT one in an “expression”). Otherwise, follow Peter’s excellent advice.

It appears that Guy is uber-editing his earlier response

@Mike-Albers said,

Changed the reply asap

In general, my preference is that posts not get edited after there’s a reply, because that breaks the flow of the conversation. In extreme circumstances, if there is an edit after a reply, I highly encourage marking it like “edit: xyz” or similar, or, if there’s a bunch of information that turns out to be wrong, using the ~~~ to strikethrough, like, “old incorrect information [edited: see my reply below]” . This allows people to be able to see what was being responded to in the immediate replies, but informs them that something has been updated.

It should be noted that even changing a post before there are any replies is dangerous, because someone may have read your original, and maybe even replying with quoting your original text, and having your text now be different makes it look like the person is misquoting you, which they are not actually doing.

(This discussion has a case in point: Alan quoted the regex101 line, and now it’s been edited away.)

As said in another forum where I spend a lot of time, “It is uncool to update a [post] in a way that renders replies confusing or meaningless”.

I agree that I edited my previous post a lot of times.

But it’s just because if you just paste the INPUT text in a new tab, you get all the sentences with a final line-break = \r\n

And, of course, the regex S/R would not work in this case :-((

BR

guy038

This post has 7 revisions

As I typed my reply, I kept seeing screen flashes, so I investigated.
It appears that Guy is uber-editing his earlier response.
Hopefully, he’s not changing history, and and is always making harmless edits.
Otherwise, how is @Mike-Albers to “keep up” with the advice being provided?

EDIT: Now:

This post has 8 revisions

I tried out your solution with the online regex tool at regex101 site but it is not working.

Some of these regexes are quite “involved”. The more involved they are, the less likely they are to work in both regex101 and Notepad++; the reason for this is that they use different regular expression engines and all engines have nuanced processing when the regexes are not simple. It may not be the case here, but you should try all advice provided in Notepad++'s replace before coming to a conclusion.

So far so good.

Thanks!

Will not make the same mistake again.

Keep up the good work!

Ah, I now understand that \n may occur in the first 4,000 characters of the last field !

A completely different goal to reach !

If I still assume that no line-break occurs in the first 3 fields

And given the INPUT file :

xxxxxxxxxxxx;yyyy;zzzzzzzzzz;12
34
5678901234567890
xxx;yyyyyyyy;zzzzzz;12345
xxx;yyyyyyyy;zzzzzz;
xxxxxx;yyy;zzzzzzzzzzzzzzzzzzz;1
2
3456789012345678901234567890
xxxxxx;yyyyy;zzzzzzzzzzzzzzzzzzzzz;1234567890

IMPORTANT : After pasting the INPUT code text above in a new tab, you must change, at the end, the current \r\n line-break by \n in lines 1, 2, 6 and 7, as shown below, BEFORE you apply the regex S/R !

The following regex S/R should work :

• FIND (?s)^(?:[^\r\n;]+;){3}.{0,10}\r\n|^((?:[^\r\n;]+;){3}.{10}).+?\r\n

• REPLACE ?1$1\r\n:$0

And produce this OUTPUT text :

xxxxxxxxxxxx;yyyy;zzzzzzzzzz;12
34
5678
xxx;yyyyyyyy;zzzzzz;12345
xxx;yyyyyyyy;zzzzzz;
xxxxxx;yyy;zzzzzzzzzzzzzzzzzzz;1
2
345678
xxxxxx;yyyyy;zzzzzzzzzzzzzzzzzzzzz;1234567890

As you can see, after the last ; of each record :

• The string 12\n34\n5678, in lines 1, 2 and 3, correctly contains 10 characters and the final \r\n

• The line 4 contains the string 12345 and the final \r\n

• The line 5 contains an empty string and the final \r\n

• The string 1\n2\n345678, in lines 6, 7 and 8, correctly contains 10 characters and the final \r\n

• The line 9 contains the string 1234567890 and the final \r\n

Now, as you said :

In fact there are more fields, but my issue is with the last field.

I suppose that you must change the numbers 3 of the regex by the exact number of fields before the last one, which size is over 4,000 characters

Thus, the general regex S/R is :

• FIND (?s)^(?:[^\r\n;]+;){N}.{0,4000}\r\n|^((?:[^\r\n;]+;){N}.{4000}).+?\r\n

• REPLACE ?1$1\r\n:$0

Where N is the number of fields before the last one !

If, in addition, the number of fields is variable, you could change the two [3} syntaxes by the {x,y} syntax, where x and y represent integers

Best regards,

guy038

I think the expression you want is this:

^((?:(?:[^";\r\n]*+|\h*+"(?:[^"]|"")*+"\h*+);){3})(?:([^";\r\n]{0,4000}+)[^";\r\n]*+|(\h*+"(?:[^"]|""){0,4000}+)(?:[^"]|"")*+("\h*+))$

with replacement:

$1$2$3$4

In your example, you have values containing new line characters that are not quoted; that’s normally invalid in a CSV. If you really have that in your file, change the [^";\r\n] sequences to [^";\r].

My immediate thought was to “undelete” your deleted post. I am a (recent new) moderator and I consider you deleting that post after others have posted replies to it to be “bad form”. You probably had the best of intentions but anyone coming along some time in the future will attempt to read that thread and it won’t make sense.

That was your first mistake, the second was to start a new thread. It would have been preferable to just append this post to the original thread. We often have first time posters adding additional relevant information after prodding by the other members.

Since this is just my opinion I won’t “undelete” nor “move” this to the original thread. I will leave that to a more senior moderator to consider.

While I’m telling you what you should have done, here’s another one. When showing examples, please include them in a code box. That helps to prevent the posting engine from mangling the data.

All of this information is in the FAQ and also pinned at the start of each category. Unfortunately you, like many new posters, don’t read them. Yet you post here in the hope to get answers, so I guess my question is why didn’t you read the FAQ and pinned posts?

Terry