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    • pinuzzu99P
      pinuzzu99
      last edited by

      I have found this that serves my purpose:
      \S+?@\S+?.\S+
      this regex select all my address@mail.com:numberletters

      now i would like to add part of string to delete the rest of the text in my txt…

      1 Reply Last reply Reply Quote 0
      • guy038G
        guy038
        last edited by

        Hello, @pinuzzu99 and All,

        Well, it’s just up to you ! All your previous e-mail addresses did not contain any dot before the @ char. Thus, I supposed that there were only word characters !

        With , your last example name.gress@mail.com, of course, the regex S/R should become :

        SEARCH (?-s)^(?!\h*[\w.]+@).+\R

        REPLACE Leave EMPTY

        Then, you said :

        now i would like to add part of string to delete the rest of the text in my txt

        I’m sorry but it’s really not clear to my mind !

        Please, give us a sample of your input text, with various e-mail adresses and show us the output text you are expecting to, from your present input example !

        Just a hint : when replying, type your input and output text as code, using the symbol </> , as below :

        See you later,

        Cheers,

        guy038

        1 Reply Last reply Reply Quote 1
        • pinuzzu99P
          pinuzzu99
          last edited by

          you are very kind of you. this is little extract of my txt file

          .: data :.
=================================
asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
=================================
 
ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
.: data :.
=================================
asda cartgrtgrg@gfgbil.com:1r5yyr78115
Pry Statinf: Kree
=================================
 
ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
.: data :.
=================================
asda jatrhtrh@grthil.com:mrthhrhmm17
Pry Statinf: Kree
=================================
 
ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
.: data :.
=================================
asda lathmhjm@hhhjail.com:p456456inha
Pry Statinf: Kree

          i want delete all text and line except
          mail.address@mail.com:xxxxxxxx

          with your string not work for me.
          work with (?-s)^(?!\h*[\w.]+@).
          but i have this result:

          

 pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr





 cartgrtgrg@gfgbil.com:1r5yyr78115






 jatrhtrh@grthil.com:mrthhrhmm17






 lathmhjm@hhhjail.com:p456456inha

          empty line between emails and also one space before any mail address.
          I hope it helps me to complete the correct string!

          1 Reply Last reply Reply Quote 0
          • guy038G
            guy038
            last edited by guy038

            Hi, @pinuzzu99 and All,

            Ok ! So, assuming your short example, below :

            .: data :.
=================================
asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
=================================
 
ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
.: data :.
=================================
asda cartgrtgrg@gfgbil.com:1r5yyr78115
Pry Statinf: Kree
=================================
 
ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
.: data :.
=================================
asda jatrhtrh@grthil.com:mrthhrhmm17
Pry Statinf: Kree
=================================
 
ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
.: data :.
=================================
asda lathmhjm@hhhjail.com:p456456inha
Pry Statinf: Kree

            The following regex S/R :

            SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?

            REPLACE Leave EMPTY

            gives this output text :

            asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
asda cartgrtgrg@gfgbil.com:1r5yyr78115
asda jatrhtrh@grthil.com:mrthhrhmm17
asda lathmhjm@hhhjail.com:p456456inha

            Are you expecting this result ?

            I simply suppose that the non-null part of an e-mail address, located before the @ char, may contain :

            • Any word character

            • A dot symbol

            • A space character

            Best Regards,

            guy038

            1 Reply Last reply Reply Quote 1
            • pinuzzu99P
              pinuzzu99
              last edited by

              thank you very much. excellent result. I’d still like if you could also delete the first part of the text in front of the email from:
              asda address@mail.com: mrthhrhmm17
              until you get:
              address@mail.com: mrthhrhmm17
              this of course for all the email addresses listed …

              1 Reply Last reply Reply Quote 0
              • guy038G
                guy038
                last edited by guy038

                Hi, @pinuzzu99 and All,

                No problem ! If we assume that there are no space char in e-mail addressses ( generally the case ! ) and further on, in current scanned line, we just need to add an alternative which, implicitly, looks for lines with an e-mail address and deletes from beginning of current line till a non-null range of space characters. Thus, the following regex S/R :

                SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+

                REPLACE Leave EMPTY

                And you’ll obtain your expected result :

                pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
cartgrtgrg@gfgbil.com:1r5yyr78115
jatrhtrh@grthil.com:mrthhrhmm17
lathmhjm@hhhjail.com:p456456inha

                Best Regards,

                guy038

                1 Reply Last reply Reply Quote 1
                • pinuzzu99P
                  pinuzzu99
                  last edited by

                  oh yes! finally what i wanted!
                  thank you very much, dear guy038.

                  1 Reply Last reply Reply Quote 0
                  • pinuzzu99P
                    pinuzzu99
                    last edited by

                    another little help:
                    i have another txt with text like this:

                    ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                    i need have like this:

                    code_text
ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                    i want delete all :number:number

                    Alan KilbornA 1 Reply Last reply Reply Quote -1
                    • Alan KilbornA
                      Alan Kilborn @pinuzzu99
                      last edited by

                      @pinuzzu99

                      What have you tried?
                      What did you get?
                      What didn’t work about it?

                      1 Reply Last reply Reply Quote 1
                      • pinuzzu99P
                        pinuzzu99
                        last edited by

                        which regex is needed to eliminate :number:number at the end of each line

                        1 Reply Last reply Reply Quote -1
                        • guy038G
                          guy038
                          last edited by guy038

                          Hi, @pinuzzu99 and All,

                          Nice ! I even succeded to merge your two kinds of text, by adding a third alternative in the search regex !

                          So, starting with the input text, below, where the e-mail adresses may be :

                          • Preceded with any chars ( asda, 12345 …), followed with, at least, one space char OR beginning the line

                          • Followed with, at least, one field, determined by a colon separator char

                          bla bla blah
bla bla blah
bla bla blah
asda ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
bla bla blah
bla bla blah
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
bla bla blah
bla bla blah
12345      ghyfm36@rocgfhmmail.com:mintgg18509:0000000000000:1111111111:55555555555555:777777777777777777:99999999999
bla bla blah
bla bla blah
bla bla blah
asda           v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                          Use the following regex S/R :

                          • SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+|.+?:.+?\K:.+

                          • REPLACE Leave EMPTY

                          • Of course, the Regular expression search mode is selected and the Wrap around option is ticked

                          • You must use the Replace All button, exclusively ( Not the Replace button ! )

                          We get the following output text :

                          ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                          Notes :

                          This regular expression is composed of 3 alternatives :

                          • The first part (?-s)^(?!\h*[\w.\x20]+@).*\R?, which have been explained previouly. If deletes any entire line, which does not contain a @ char, after a non-null range of words chars and possible dot and/or space chars

                          • The second part ^.*?\x20+ which deletes all text between beginning of line and a non-null range of space characters, if that line contains an e-mail address, further on

                          • The third part .+?:.+?\K:.+ deletes, after the e-mail adress, from the second : char found till the last standard char of the current scanned line

                          • Note, in this last part, the use of the lazy quantifier +? to identify all standard chars between the first and the second : chars and the \K syntax before the second : char, which resets the overall search and just grabs all the remaining chars of current line, from the second :, included

                          Remark :

                          I strongly advice you to learn the regular expresions world ! Of course, you’ll have to study for 1/2 months, but it’s really worth it ;-)). To begin with, consult this FAQ :

                          https://community.notepad-plus-plus.org/topic/15765/faq-desk-where-to-find-regex-documentation

                          Best Regards,

                          guy038

                          1 Reply Last reply Reply Quote 1
                          • pinuzzu99P
                            pinuzzu99
                            last edited by

                            ohhhhh very great! many thanks for your help! very very thanks.
                            and you’re right when you say you have to study. and usually I do. but in the case of np ++ using little, it did not occur to me to search and learn reg ex expressions. but I will take your suggestion into account.

                            for my question: this is ANOTHER txt, then different. but anyway you code work great, my intent was that! very very many thanks for your help!
                            Regards

                            1 Reply Last reply Reply Quote 0
                            • guy038G
                              guy038
                              last edited by

                              Hi, @pinuzzu99,

                              Ah, OK ! So, if we consider that there were 2 separate tasks and starting with your exact input text, below :

                              ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                              The following regex S/R :

                              • SEARCH (?-s)^.+?:.+?\K:.+

                              • REPLACE Leave EMPTY

                              • Click on the Replace All button, exclusively

                              should leave you with your expected result :

                              ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                              Cheers,

                              guy038

                              1 Reply Last reply Reply Quote 0
                              • pinuzzu99P
                                pinuzzu99
                                last edited by

                                thanks you so much, again! cheers

                                1 Reply Last reply Reply Quote 0
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