sort file removing duplicates possible?



  • this should do it (the problem was in the removing of duplicates):
    ^(.?)$\s+?^(?=.^\1$)



  • @patrickdrd

    Your regular expression will not work as shown; I can tell some of the important characters in it are missing (due to being consumed by the Markdown syntax this website uses). If you need to write a * here, either escape it, like this: \* in which it will then appear like this: *…or put it inside backticks (also called grave accents), like this `*` in which case it will then appear like this: * (I find this second way of doing it easier/cleaner).

    So let’s assume you meant to post ^(.*?)$\s+?^(?=.*^\1$)

    That is clearly wrong as it introduces the notion of whitespace (with the \s+). That may work for exactly what YOU are doing, but in general; if we are sorting lines and then deleting duplicates then \s doesn’t belong.

    I retested the original test sort and del dupe lines macro definition I posted earlier, and it (still) works. So let’s try an example, here’s some random unsorted data with some duplicates:

    nonprehensile
    aeriferous
    calabrian
    estimating
    urethrostomy
    redigging
    estimating
    crystalling
    cynwulf
    fetor
    kali
    armada
    auspicate
    tusser
    fetor
    zoophyte
    ribless
    fetor
    deducibly
    calabrian
    estimating
    expressivity
    

    After running the macro, we obtain the desired result (sorted, duplicates removed), nothing more, nothing less:

    aeriferous
    armada
    auspicate
    calabrian
    crystalling
    cynwulf
    deducibly
    estimating
    expressivity
    fetor
    kali
    nonprehensile
    redigging
    ribless
    tusser
    urethrostomy
    zoophyte
    

    Earlier I presented the regular expression (in the macro) without explanation. Here’s what it is actually doing to find matches:

    (?-s)   ^   (.*)   (?:   \R   )   (?s)   (?=   .*   ^   \1   \R   )
    ^^^^^-----------------------------------------------------------------------------> after this . appearing will match any single character except a line-ending character
            ^-------------------------------------------------------------------------> match only at start of line
                ^  ^------------------------------------------------------------------> remember what matches the expression between `(` and `)`; call it "group #1"
                 ^^-------------------------------------------------------------------> match zero or more characters (in this case it will stop matching at the next line-ending character)
                       ^^^        ^---------------------------------------------------> the syntax `(?:` followed by something followed by `)` means to match what is inside but don't remember it
                             ^^-------------------------------------------------------> match a line-ending
                                      ^^^^--------------------------------------------> after this a . appearing will match any single character including a line-ending character
                                             ^^^                      ^---------------> the syntax `(?=` followed by something followed by `)` means whatever is inside needs to match for the overall expression to match, but it isn't consumed and isn't part of the match
                                                   ^^---------------------------------> match zero or more characters (ANY characters, including line-ending characters...this will match across lines)
                                                        ^-----------------------------> match at start of line
                                                            ^^------------------------> match what we remembered earlier as "group #1"
                                                                 ^^-------------------> match a line-ending character
    

    So that’s actually still pretty technical/confusing. Maybe this is better:

    • look at the complete contents of the current line
    • glance further down (any arbitrary amount of distance) in the file to see if there is an exact duplicate of the current line contents; if so, the current line is a MATCH
    • if there was a MATCH, do the REPLACEMENT (see below)
    • move beyond the current line (go down one line)
    • repeat these steps until the file is exhausted

    When there is a MATCH, perform the specified REPLACEMENT on the matched text. Since the matched text is the entire current line (with line-ending), and the replacement is NOTHING, this effectively deletes the current line. This is what is desired because our goal is to removed duplicate lines and we’ve already established that the matched line occurs again further down in the file.

    Dedicated regexers might catch that my regular expression is more-complicated than needed. The (?:\R) part could be changed to simply \R. (?: ) is normally used when some grouping without remembering is necessary. Here \R needs no grouping so the (?: ) is just extra fluff…does no harm except making the whole expression harder to read.

    Super-dedicated regexers would also say that the regular expression is more-complicated than needed because at the point it is run (inside the macro above) the file is already sorted! Very true. The regular expression above works for sorted or unsorted duplicate line detection/removal. Here’s the simpler one that will only work on the sorted lines situation: (?-s)^(.*)\R(?=^\1\R)

    One more thing worth mentioning is that if you want to delete duplicate lines but ignore/leave blank/(empty!) lines, simply change (.*) in the regular expression to (.+). Instead of “match ZERO or more characters”, this change will “match ONE or more characters”, effectively failing to match truly empty lines so they won’t be removed.



  • I had problem with a file today, I don’t know why,
    is there any way I can send you the file to take a look?



  • @patrickdrd said:

    send you the file to take a look

    Post its contents on http://textuploader.com/ and reply here with the link to it. Also indicate exactly what problem you are seeing if it isn’t obvious. No guarantees about how deeply I can get involved, but I’ll take a quick look… :-)



  • ok, it’s here:
    http://textuploader.com/d4dkr

    removing duplicates results contain a duplicate result



  • remove duplicates without sorting produces the result:
    DBServerIP=10.1.249.215
    DBServerIP=10.12.77.185
    DBServerIP=10.1.249.215

    (1st and 3rd exact duplicates)

    and sorting first and then removing dups results in:
    DBServerIP=10.12.22.129
    DBServerIP=10.12.77.185
    DBServerIP=10.12.77.185

    last 2 duplicated

    (using your regular expression in both cases of course)



  • @patrickdrd

    Okay, so a quick look told me what is happening. It’s interesting. :-)

    If you run only the sort on this data, you’ll get this at the end of the file:

    Imgur

    You’d think that the removal of duplicate lines after this would result in only a single occurrence of DBServerIP=10.12.77.185. However, if we look closer at what is really left after the duplicate removal (turning on visibility of line-endings!), we see:

    Imgur

    We see that the two lines with that IP address truly are different–one has a line-ending and one doesn’t–and because these two lines are not the same, the regular-expression replacement is working correctly by leaving both of these lines after it does its work.

    All of the original lines that ended in .185 had line-endings (in other words, were exactly the same), so I’d say this is an artifact resulting from the sort operation (in my mind this is a sort BUG!).

    But we can work around it. There could be a regular expression solution, but maybe the regex that removes duplicates is complicated enough. What I’d suggest here is to modify the original macro, after the sort but before the find+replace, to:

    • move caret position to the end of file (the sort operation leaves it at the beginning of file)
    • insert a (Windows style) line-ending
    • move caret position back to beginning of file (in preparation for the find+replace)

    Thus:

    <Macro name="test sort and del dupe lines 2" Ctrl="no" Alt="no" Shift="no" Key="0">
        <Action type="2" message="0" wParam="42059" lParam="0" sParam="" />
        <Action type="0" message="2318" wParam="0" lParam="0" sParam="" />
        <Action type="1" message="2170" wParam="0" lParam="0" sParam="&#x000D;" />
        <Action type="1" message="2170" wParam="0" lParam="0" sParam="&#x000A;" />
        <Action type="0" message="2316" wParam="0" lParam="0" sParam="" />
        <Action type="3" message="1700" wParam="0" lParam="0" sParam="" />
        <Action type="3" message="1601" wParam="0" lParam="0" sParam="(?-s)^(.*)(?:\R)(?s)(?=.*^\1\R)" />
        <Action type="3" message="1625" wParam="0" lParam="2" sParam="" />
        <Action type="3" message="1602" wParam="0" lParam="0" sParam="" />
        <Action type="3" message="1702" wParam="0" lParam="512" sParam="" />
        <Action type="3" message="1701" wParam="0" lParam="1609" sParam="" />
    </Macro>
    

    Compare that with the earlier version much earlier in this thread.

    Running this new macro on your data results in:

    Imgur

    which is the desired result.



  • @patrickdrd

    For the DBServerIP=10.1.249.215 case you mentioned, if you don’t do the sort first, then a .215 line is the last line of the data you turn over to the regular expression replace operation. Thus it lacks the trailing line-ending that the earlier occurrence of a similar line has. Same issue as the .185 case…



  • thanks a ton!

    I’d a like a more “generic” approach, so I called trim 42056 to clear empty lines first,
    because sorting puts an empty line at the top if is finds one,
    then going on as you suggested



  • @patrickdrd

    I’m glad you have a solution. Yeah, the empty line thing with sorting is rather bad, but the end-user can’t control this behavior of the sorting. I think I’ve changed my mind and it is probably best to alter the regular expression a bit in order to handle the situation where there is a duplicate-but-without-line-ending at the end of the file. So I’d suggest changing it to:

    (?-s)^(.*)\R(?s)(?=.*^\1(?:\R|\z))

    I’ve done two things to this regex:

    • I removed the (?: and ) around the first \R (a simplification discussed earlier so no need to say any more here)
    • The final \R was changed to (?:\R|\z) (see discussion below)

    The \R|\z part is what allows an almost-duplicate at the end-of-file-without-line-ending to be detected. The new part to this is the \z which roughly means “match only at the very end of the data”.

    The (?: and ) was added so that the | only affects the \R that precedes it and the \z that follows it



  • Hello @patrickdrd, @scott-sumner and All,

    Generally speaking, when you want to remove duplicate lines, from a PREVIOUSLY SORTED list, just use this simple regex S/R, below :

    SEARCH (?-s)(.*\R)\1+

    REPLACE \1

    This regex is quite fast, because, in case of numerous duplicates, the part \1+ grabs all the duplicates ( with their EOL characters ), at once and just rewrites the first item of each block :-))

    IMPORTANT : the last item of your sorted list must be followed by EOL character(s) !

    Cheers,

    guy038



  • after trying both the macro and the textfx solution for a long time,
    I’ve seen that still ultraedit’s sorting works much better than both of them,
    I first rejected the macro for textfx’s favor but I found out lately that neither the latter does a good job, at least I prefer the sorting done by ultraedit ,sorry,
    I don’t have an example at the moment, I’ll post again when I do



  • @patrickdrd

    sorry, did not read the whole thread but what about a python one liner?

    editor.setText('\r\n'.join(list(set(editor.getText().splitlines()))))
    

    Cheers
    Claudia



  • @patrickdrd

    forgot sorting

    editor.setText('\r\n'.join(sorted(list(set(editor.getText().splitlines())))))
    

    Cheers
    Claudia



  • thanks, I’m keeping that too and I’ll let you know



  • ok, I tested, this doesn’t work either somehow, at least doesn’t work like ue’s one, i.e.

    I tested with easylist from: https://easylist.to/easylist/easylist.txt (69883 lines),
    ue’s function cuts it to: 69238

    npp results:
    python scipt: 69818
    macro (scott) is a bit slow and results in 19610 lines (!) and
    textfx results in 69818 as well

    guy038 regular expression results in 28109 lines,
    according to my experience, I bet that ue’s result is the correct one,
    at least to my taste



  • @patrickdrd

    could you, by any chance, upload the ue cutted list?
    To see the differences.

    Cheers
    Claudia



  • yes, of course, please tell me where, pastebin doesn’t work, it’s blocked here (at work),
    any other suggestions?



  • actually pastebin is my first choice as well and haven’t used others for quite some time now.

    Heard about

    https://www.zippyshare.com/
    https://www.sendspace.com/

    should be good and anonymous but haven’t tried it so far.

    Cheers
    Claudia



  • Yea, I used to be a fan of regular expression replacement when doing this, but with “larger” datasets there always seems like there is so much tweaking and experimentation needed to get it right (for a particular dataset) that it is hardly worth it, unless you like playing with regular expressions all day instead of solving a particular problem and moving on quickly.

    A Pythonscript solution such as @Claudia-Frank 's seems fine…


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