How to automatically add space on both sides of the operator

成轩

How to automatically add spaces on both sides of the operator.
For example, a=a+1;
A = a + 1;

gwarah

You could try to use “find and replace” feature, set to consider regular expressions, and replace all no-space (x) char with x followed a space in a current selection.

Save it as a macro and apply in other parts of code.

gwarah

The workaround I ve suggested at the last post doesn t work in such cases

ab=ab+1;

But even so, I believe “find and replace” with a better regEx you will find out a solution.

guy038

Hello, @成轩 and All

Without additional information, it’s quite hard to plan anything ! Which language are you using ?

Anyway, I tried to find out a correct regex S/R, which :

Trims any trailing horizontal blank characters, before the End of Line
Keeps any leading indentation
Keeps the blank characters in any range "..........", too
Deletes any range of horizontal blank characters, before a comma
Normalizes to a single space character, any range of blank characters, even none, PRECEDING, either :
- Any consecutive range of symbols ! " # $ % & ' * + - / : ; = ? @ \ ^ | ~
- Any single symbol [ ] ( ) < > { }
- Any consecutive range of word characters or dot Letter Digit _ .

Of course, there are still few weird results ! For instance, the sentence “On the 10/27 of that year” would become “On the 10 / 27 of that year” but that other sentence “The value x=a*10/27+b” would produce the sentence “The value x = a * 10 / 27 + b” which is quite correct !

For example, the statement “x=(((a+5)/(z-7/b)-sin(30))*Log(6))” would be developed as “x = ( ( ( a + 5 ) / ( z - 7 / b ) - sin ( 30 ) ) * Log ( 6 ) )” with, certainly, too many space characters than necessary ;-))

A last example : here is, below, a simple Python script, regarding Unix Timestamp, with a very, very bad presentation ! You may select the option View > Show Symbol > Show All Characters to visualize all the blank characters

Day        =        28			
Month=3
Year		=			2018
Hours			=15                
Minutes=19
Seconds		=0
		                    
			# This small script get any Unix Timestamp
			#        with the different time variables above
			#        		defined with a correct numeric value

Leap=int(Year    %4==0)-int(     Year%100==0)+int(Year%400==0)                            # = 1 if a is a LEAP year, = 0 if NOT

Leap_Years=(Year      -1)//4-(Year-1)     //100+(Year-1)//400-477                           # = TOTAL of LEAP years, from 1970 to the year (Year-1)
			
Calendar_Day   =   round(30.57*(Month-1)-2*int(Month   >   2))+Day+int(Leap==1)		*		int(Month>2) # = TOTAL of days, from the 01/01 of Year, to Day, included

Total_Days=(Year-1970)*365+Leap_Years+Calendar_Day-1                             # = TOTAL of days, from 01/01/1970, till (Day-1) of Year
                                  
Unix_Time=Total_Days*86400+3600*Hours    +       60*Minutes+Seconds                          #  UNIX time, in seconds


print("And,    here are.... the     results  :  ",Leap       ,Leap_Years,          Calendar_Day,Total_Days,Unix_Time, "<     Good Bye     >")

        # The results are :
		
		# Leap=0
        #		Leap_Year		=		12
        # Calendar_Day = 87
        #            Total_Days = 17618
        # Unix_Time		=					1522250340

Open the Replace dialog ( Ctrl + H )
In the Find what: zone, type in the regex :

(?-s)(\h+\R)|(\h*,)|(^)?\h*(".*?"|[]()<>{}[]|[!"#$%&'*+/:;=?@\\^`|~-]+|[\w.]+)

In the Replace with: zone, type in the regex

(?1\r\n:(?2,:(?3$0:\x20\4)))

Tick the Wrap around option
Click, once, on the Replace All button ( or several times on the Replace button

Et voilà ! You should get the following new text :

Day = 28
Month = 3
Year = 2018
Hours = 15
Minutes = 19
Seconds = 0

			# This small script get any Unix Timestamp
			# with the different time variables above
			# defined with a correct numeric value

Leap = int ( Year % 4 == 0 ) - int ( Year % 100 == 0 ) + int ( Year % 400 == 0 ) # = 1 if a is a LEAP year, = 0 if NOT

Leap_Years = ( Year - 1 ) // 4 - ( Year - 1 ) // 100 + ( Year - 1 ) // 400 - 477 # = TOTAL of LEAP years, from 1970 to the year ( Year - 1 )

Calendar_Day = round ( 30.57 * ( Month - 1 ) - 2 * int ( Month > 2 ) ) + Day + int ( Leap == 1 ) * int ( Month > 2 ) # = TOTAL of days, from the 01 / 01 of Year, to Day, included

Total_Days = ( Year - 1970 ) * 365 + Leap_Years + Calendar_Day - 1 # = TOTAL of days, from 01 / 01 / 1970, till ( Day - 1 ) of Year

Unix_Time = Total_Days * 86400 + 3600 * Hours + 60 * Minutes + Seconds # UNIX time, in seconds


print ( "And,    here are.... the     results  :  ", Leap, Leap_Years, Calendar_Day, Total_Days, Unix_Time, "<     Good Bye     >" )

        # The results are :

		# Leap = 0
        # Leap_Year = 12
        # Calendar_Day = 87
        # Total_Days = 17618
        # Unix_Time = 1522250340

Of course, the trailing comments and, generally, the possible lists are not aligned, too :-( Anyway, I just ran that Python3 script, after the S/R modifications, without any trouble !

You may use this Unix Timestamp Converter to verify my calculus !

Cheers,

guy038

P.S. :

This Python example is quite raw and simple ! My initial program, about conversions Date <–> Unix Timestamp, was written in the old Qbasic language and some months ago, I simply translated the main part, as an Python3 exercise , about mathematics ;-))
About 00h30, in France ! So, I’m a bit lazy to explain how this regex S/R works ! May be next time, if you offer me… some beer ;-))

Gogo Neatza

@成轩 : Spend less than ten seconds to write your own Macro !

Scott Sumner

@Gogo-Neatza said:

Spend less than ten seconds to write your own Macro !

I’m not sure how THAT is helpful in any way…please explain if you can…

@guy038 said:

…the statement “x=(((a+5)/(z-7/b)-sin(30))*Log(6))” would be … “x = ( ( ( a + 5 ) / ( z - 7 / b ) - sin ( 30 ) ) * Log ( 6 ) )” with…too many space characters

It is very subjective (i.e., everybody likes it their own way), but I definitely agree that this is too spacey:

x = ( ( ( a + 5 ) / ( z - 7 / b ) - sin ( 30 ) ) * Log ( 6 ) )

but I like this version, which doesn’t add space adjacent to ( or ) :

x = (((a + 5) / (z - 7 / b) - sin(30)) * Log(6))

The original is just visually painful …ouch! :

x=(((a+5)/(z-7/b)-sin(30))*Log(6))

I think I will make the modification to the regex to avoid the “too spacey” condition and then record it as a Replace All, In Selection macro, for handy use when I get a short snippet of code from (e.g.) stackoverflow and don’t like the original whitespacing of an equation. (Is this what @Gogo-Neatza meant?!)

BTW, @guy038, I like this site for timestamp conversion.

vtech7

Hi, in order to convert the following sample of code:

x=(((a+5)/(z-7/b)-sin(30))*Log(6))

to this one: (without double spacing)

x = ( ( ( a + 5 ) / ( z - 7 / b ) - sin ( 30 ) ) * Log ( 6 ) )

find:

(([\w])([^\w|\s]))|(([^\w|\s])([\w]))|(([^\w|\s])([^\w|\s]))

replace:

(?1\2 \3)(?4\5 \6)(?7\8 \9)

vtech7

I just forgot to mention that the above find and replace must apply 2 times (for the given sample code).

Scott Sumner

@vtech7

Hmmm…or just put the spaces in by this process:

position the caret appropriately
press the space bar once
REPEAT above steps until desired effect is achieved

gwarah

Maybe this issue would be a case to new feature request (or plugin suggestion) in a way to put spaces between chars of current line, and the user lists in a field the sequences that wouldn’t applied (ex. ++, —,…). There would be a general sequence list and others to each language.

成轩

I also hope that such a plugin can be selected for different languages. I hope it can automatically determine the operator I entered and then automatically add spaces. Although regular expression processing can achieve the above operations, I think it is not too friendly and convenient

成轩

Thank you all for answering questions

Fahim Anwer

You could try to use “find and replace” feature, set to consider regular expressions, and replace all no-space (x) char with x followed a space in a current selection.

Save it as a macro and apply in other parts of code.
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