12-hour to 24-hour clock conversion
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I want to convert a 12-hour clock to 24-hour clock up to the ms.
Example: Today is 12:00:00:001 AM and it’s raining.
Output: Today is 00:00:00:001 and it’s raining. -
check regular expression in replace dialog and use
find what:(\d{1,2})(:\d{1,2}:\d{1,2}:\d{1,3}) AM
and replace with00\2
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@Ekopalypse thanks for the answer but what if it’s multiple numbers in AM and PM, and the separator will be from . to :? Regex won’t work for other numbers.
Example:
01.25.31.934 PM -> 13:25:31:934
04.02.28.421 AM -> 04:02:28:421
09.55.03.732 PM -> 21:55:03:732 -
would you mind clarifying the exact format of your data as this is essential for
regular expressions to work correctly. For example, in the previous request you used :
to separate time fields and now you are using a dot. -
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@Ekopalypse I’m sorry I wasn’t clear with my question. I’m really looking for an answer for my 2nd request. I posted the 1st one because I was still trying different regex which would answer my 2nd request and I was hoping I could formulate something with the answer that you provided.
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@Alan-Kilborn thank you for this link but I already tried the answers provided but I was only able to convert am up to minutes using . as a separator.
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It wasn’t for you, it was for future searchers of this site that may find this topic when what they are really looking for is the other way around. :)
BTW if Eko doesn’t solve your problem here in a reasonable amount of time, I’ll jump in. :)
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Alan, LOL, please feel free to do so - you are much more in this regex then I’m.
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This seems to do it:
Find:
^(?:(01)|(02)|(03)|(04)|(05)|(06)|(07)|(08)|(09)|(10)|(11)|(12))\.(\d\d)\.(\d\d)\.(\d{3}) (?:(A)|(P))M
Repl:(?{12}?{16}00:12)(?{1}?{17}13:01)(?{2}?{17}14:02)(?{3}?{17}15:03)(?{4}?{17}16:04)(?{5}?{17}17:05)(?{6}?{17}18:06)(?{7}?{17}19:07)(?{8}?{17}20:08)(?{9}?{17}21:09)(?{10}?{17}22:10)(?{11}?{17}23:11):$13:$14:$15
Search mode: Regular expressionI tried to be “fancy” and do the “AM” and “PM” part with “named groups” so that the replacement is more “readable”, but I ran into some trouble with that. If I get it working, and it truly is more readable, I may post that as well…
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I got it to work with named groups. The problem was, and it makes it less elegant, is that mixing numbered and named capture groups seems to mess things up. So I had to artificially name group # 1 as “one” instead of just using its number. I’ll let the reader decide if this version is more readable than the previous:
Find:
^(?:(?<one>01)|(?<two>02)|(?<three>03)|(?<four>04)|(?<five>05)|(?<six>06)|(?<seven>07)|(?<eight>08)|(?<nine>09)|(?<ten>10)|(?<eleven>11)|(?<twelve>12))\.(?<mins>\d\d)\.(?<secs>\d\d)\.(?<ms>\d{3}) (?:(?<am>A)|(?<pm>P))M
Repl:
(?{twelve}?{am}00:12)(?{one}?{pm}13:01)(?{two}?{pm}14:02)(?{three}?{pm}15:03)(?{four}?{pm}16:04)(?{five}?{pm}17:05)(?{six}?{pm}18:06)(?{seven}?{pm}19:07)(?{eight}?{pm}20:08)(?{nine}?{pm}21:09)(?{ten}?{pm}22:10)(?{eleven}?{pm}23:11):$+{mins}:$+{secs}:$+{ms}
Search mode: Regular expression
(And I fully expect a “holy cow batman!” from @Meta-Chuh on that one!)
(And yes, doing 12 differently from the others in the replace was intentional, as it is a little “out of place” in the conversion)
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LOL - if I could I would upvote it 12 times. :-D
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Sometimes things get upvoted too quickly for people to have tried it out to verify/duplicate results. This is somewhat bad as if something doesn’t work (and the thread dies right there) it looks to future readers like a good solution…
BTW I think the “replace” is very readable with the named groups, but the “find” suffers…slightly…
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:-D for me this looks like what we call - bohemian villages.
But I can participate on that thread now - I’ve tested it, and it looks good to me :-)
Let’s see what the OP thinks about it. -
@Alan-Kilborn it works perfectly. Thank you so much!
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2nd solution is less confusing but both still produces the desired output. :D
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holy cow batman! 😄👍
Sometimes things get upvoted too quickly for people to have tried it out to verify/duplicate results.
i guess sometimes your writing style is so worth an upvote, that people give you one, even if they have tested it’s content to fail.
greetings,
robin -
@Meta-Chuh said:
your writing style…worth an upvote…
My writing style? Nah. I don’t have the flowery prose of a @PeterJones or the diplomatic panache of a @Meta-Chuh . [Basically I don’t wanna put that kind of effort in–to the typing part–obviously with the above regexes staring us in the face I’ll put a little time/effort into THAT aspect. Trying to provide some hopefully accurate help, maybe without the greatest english composition accompanying.]
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Hi, @sophia-cruz, @alan-kilborn, @eko-palypse, @meta-chuh and All,
Here is a variant of the Alan’s solution, which is less restrictive :
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It just needs that the hour should be located after a non-word, instead of the beginning of line, due to the
\b
syntax -
It does not care of the synbol between the different parts of the hour ( just changing the
\.
syntax by.
! ) -
It allows the milliseconds part to be absent (
.MMM
), in the hour, with the(?:.(\d{3}))?
syntax -
It allows the
AM
orPM
part to come next to the digits, with\x20?
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It does not care of the case , allowing the four syntaxes
am
,pm
,AM
andPM
with the regex(?i:(AM)|PM)
Note :
In the remplacement regex, when group17
exists (AM
), I just rewrite the hour part (\1
), except when hour =12
, where the logic is reversed !
So, assuming this sample text :
12.00.47 AM 12.58.18.387 am 01 07 28 421 AM 03:17:31:934am 05.43.26.582 AM 07:23:03.732 am 09.31.08AM 11.57.59,003 am ~~~~~~~~~~~~~~~~~~~~ 12.00.45 PM 12.56.49.203 pm 01 04 51 387 PM 03:15:33:632pm 05.22.00.814 PM 07:33:55.548 pm 09.45.26PM 11.59.11,247 pm
With the regex S/R below :
SEARCH : \b(0(?:(1)|(2)|(3)|(4)|(5)|(6)|(7)|(8)|(9))|(10)|(11)|(12)).(\d\d).(\d\d)(?:.(\d{3}))?\x20?(?i:(AM)|PM) │ │ │ │ │ │ │ │ │ │ │ │ │ │ │ │ │ 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 <-- Groups REPLACE : (?2(?17\1:13))(?3(?17\1:14))(?4(?17\1:15))(?5(?17\1:16))(?6(?17\1:17))(?7(?17\1:18))(?8(?17\1:19))(?9(?17\1:20))(?10(?17\1:21))(?11(?17\1:22))(?12(?17\1:23))(?13(?{17}00:\1)):$14:$15(?16\:$16)
We would obtain :
00:00:47 00:58:18:387 01:07:28:421 03:17:31:934 05:43:26:582 07:23:03:732 09:31:08 11:57:59:003 ~~~~~~~~~~~~~~~~~~~~ 12:00:45 12:56:49:203 13:04:51:387 15:15:33:632 17:22:00:814 19:33:55:548 21:45:26 23:59:11:247
Best Regards,
guy038
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Hi, All,
When I woke up this morning, I immediately saw a simplification ( in length ! ) of the replacement regex ;-))
So, my last version is :
SEARCH
\b(0(?:(1)|(2)|(3)|(4)|(5)|(6)|(7)|(8)|(9))|(10)|(11)|(12)).(\d\d).(\d\d)(?:.(\d{3}))?\x20?(?i:(AM)|PM)
REPLACE
(?13(?{17}00:\1):(?17\1:(?{2}13)(?{3}14)(?{4}15)(?{5}16)(?{6}17)(?{7}18)(?{8}19)(?{9}20)(?{10}21)(?{11}22)(?{12}23))):$14:$15(?16\:$16)
BR
guy038