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    12-hour to 24-hour clock conversion

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    • Alan KilbornA Offline
      Alan Kilborn @Sophia Cruz
      last edited by

      @Sophia-Cruz

      It wasn’t for you, it was for future searchers of this site that may find this topic when what they are really looking for is the other way around. :)

      BTW if Eko doesn’t solve your problem here in a reasonable amount of time, I’ll jump in. :)

      EkopalypseE 1 Reply Last reply Reply Quote 4
      • EkopalypseE Offline
        Ekopalypse @Alan Kilborn
        last edited by

        @Alan-Kilborn

        Alan, LOL, please feel free to do so - you are much more in this regex then I’m.

        1 Reply Last reply Reply Quote 1
        • Alan KilbornA Offline
          Alan Kilborn @Sophia Cruz
          last edited by

          @Sophia-Cruz

          This seems to do it:

          Find: ^(?:(01)|(02)|(03)|(04)|(05)|(06)|(07)|(08)|(09)|(10)|(11)|(12))\.(\d\d)\.(\d\d)\.(\d{3}) (?:(A)|(P))M
          Repl: (?{12}?{16}00:12)(?{1}?{17}13:01)(?{2}?{17}14:02)(?{3}?{17}15:03)(?{4}?{17}16:04)(?{5}?{17}17:05)(?{6}?{17}18:06)(?{7}?{17}19:07)(?{8}?{17}20:08)(?{9}?{17}21:09)(?{10}?{17}22:10)(?{11}?{17}23:11):$13:$14:$15
          Search mode: Regular expression

          I tried to be “fancy” and do the “AM” and “PM” part with “named groups” so that the replacement is more “readable”, but I ran into some trouble with that. If I get it working, and it truly is more readable, I may post that as well…

          Alan KilbornA Sophia CruzS 2 Replies Last reply Reply Quote 5
          • Alan KilbornA Offline
            Alan Kilborn @Alan Kilborn
            last edited by Alan Kilborn

            I got it to work with named groups. The problem was, and it makes it less elegant, is that mixing numbered and named capture groups seems to mess things up. So I had to artificially name group # 1 as “one” instead of just using its number. I’ll let the reader decide if this version is more readable than the previous:

            Find: ^(?:(?<one>01)|(?<two>02)|(?<three>03)|(?<four>04)|(?<five>05)|(?<six>06)|(?<seven>07)|(?<eight>08)|(?<nine>09)|(?<ten>10)|(?<eleven>11)|(?<twelve>12))\.(?<mins>\d\d)\.(?<secs>\d\d)\.(?<ms>\d{3}) (?:(?<am>A)|(?<pm>P))M

            Repl: (?{twelve}?{am}00:12)(?{one}?{pm}13:01)(?{two}?{pm}14:02)(?{three}?{pm}15:03)(?{four}?{pm}16:04)(?{five}?{pm}17:05)(?{six}?{pm}18:06)(?{seven}?{pm}19:07)(?{eight}?{pm}20:08)(?{nine}?{pm}21:09)(?{ten}?{pm}22:10)(?{eleven}?{pm}23:11):$+{mins}:$+{secs}:$+{ms}

            Search mode: Regular expression

            (And I fully expect a “holy cow batman!” from @Meta-Chuh on that one!)

            (And yes, doing 12 differently from the others in the replace was intentional, as it is a little “out of place” in the conversion)

            EkopalypseE Meta ChuhM 2 Replies Last reply Reply Quote 5
            • EkopalypseE Offline
              Ekopalypse @Alan Kilborn
              last edited by

              @Alan-Kilborn

              LOL - if I could I would upvote it 12 times. :-D

              Alan KilbornA 1 Reply Last reply Reply Quote 2
              • Alan KilbornA Offline
                Alan Kilborn @Ekopalypse
                last edited by Alan Kilborn

                @Ekopalypse

                Sometimes things get upvoted too quickly for people to have tried it out to verify/duplicate results. This is somewhat bad as if something doesn’t work (and the thread dies right there) it looks to future readers like a good solution…

                BTW I think the “replace” is very readable with the named groups, but the “find” suffers…slightly…

                EkopalypseE 1 Reply Last reply Reply Quote 1
                • EkopalypseE Offline
                  Ekopalypse @Alan Kilborn
                  last edited by

                  @Alan-Kilborn

                  :-D for me this looks like what we call - bohemian villages.
                  But I can participate on that thread now - I’ve tested it, and it looks good to me :-)
                  Let’s see what the OP thinks about it.

                  1 Reply Last reply Reply Quote 2
                  • Sophia CruzS Offline
                    Sophia Cruz @Alan Kilborn
                    last edited by

                    @Alan-Kilborn it works perfectly. Thank you so much!

                    1 Reply Last reply Reply Quote 3
                    • Sophia CruzS Offline
                      Sophia Cruz
                      last edited by

                      2nd solution is less confusing but both still produces the desired output. :D

                      1 Reply Last reply Reply Quote 1
                      • Meta ChuhM Offline
                        Meta Chuh moderator @Alan Kilborn
                        last edited by

                        @Alan-Kilborn

                        holy cow batman! 😄👍

                        Sometimes things get upvoted too quickly for people to have tried it out to verify/duplicate results.

                        i guess sometimes your writing style is so worth an upvote, that people give you one, even if they have tested it’s content to fail.

                        greetings,
                        robin

                        Alan KilbornA 1 Reply Last reply Reply Quote 1
                        • Alan KilbornA Offline
                          Alan Kilborn @Meta Chuh
                          last edited by Alan Kilborn

                          @Meta-Chuh said:

                          your writing style…worth an upvote…

                          My writing style? Nah. I don’t have the flowery prose of a @PeterJones or the diplomatic panache of a @Meta-Chuh . [Basically I don’t wanna put that kind of effort in–to the typing part–obviously with the above regexes staring us in the face I’ll put a little time/effort into THAT aspect. Trying to provide some hopefully accurate help, maybe without the greatest english composition accompanying.]

                          1 Reply Last reply Reply Quote 2
                          • guy038G Offline
                            guy038
                            last edited by guy038

                            Hi, @sophia-cruz, @alan-kilborn, @eko-palypse, @meta-chuh and All,

                            Here is a variant of the Alan’s solution, which is less restrictive :

                            • It just needs that the hour should be located after a non-word, instead of the beginning of line, due to the \b syntax

                            • It does not care of the synbol between the different parts of the hour ( just changing the \. syntax by . ! )

                            • It allows the milliseconds part to be absent ( .MMM ), in the hour, with the (?:.(\d{3}))? syntax

                            • It allows the AM or PM part to come next to the digits, with \x20?

                            • It does not care of the case , allowing the four syntaxes am, pm, AM and PM with the regex (?i:(AM)|PM)

                            Note :
                            In the remplacement regex, when group 17 exists ( AM ), I just rewrite the hour part ( \1 ), except when hour = 12, where the logic is reversed !


                            So, assuming this sample text :

                            12.00.47 AM
                            	12.58.18.387 am
                            01 07 28 421 AM
                            03:17:31:934am
                            05.43.26.582 AM
                                    07:23:03.732 am
                            09.31.08AM
                            11.57.59,003 am
                            ~~~~~~~~~~~~~~~~~~~~
                            12.00.45 PM
                            	12.56.49.203 pm
                            01 04 51 387 PM
                            03:15:33:632pm
                            05.22.00.814 PM
                                    07:33:55.548 pm
                            09.45.26PM
                            11.59.11,247 pm
                            

                            With the regex S/R below :

                            SEARCH :    \b(0(?:(1)|(2)|(3)|(4)|(5)|(6)|(7)|(8)|(9))|(10)|(11)|(12)).(\d\d).(\d\d)(?:.(\d{3}))?\x20?(?i:(AM)|PM)
                                          │    │   │   │   │   │   │   │   │   │    │    │    │     │      │         │                │
                                          1    2   3   4    5   6   7   8   9   10   11   12    13    14     15        16               17   <-- Groups
                            
                            REPLACE :   (?2(?17\1:13))(?3(?17\1:14))(?4(?17\1:15))(?5(?17\1:16))(?6(?17\1:17))(?7(?17\1:18))(?8(?17\1:19))(?9(?17\1:20))(?10(?17\1:21))(?11(?17\1:22))(?12(?17\1:23))(?13(?{17}00:\1)):$14:$15(?16\:$16)
                            

                            We would obtain :

                            00:00:47
                            	00:58:18:387
                            01:07:28:421
                            03:17:31:934
                            05:43:26:582
                                    07:23:03:732
                            09:31:08
                            11:57:59:003
                            ~~~~~~~~~~~~~~~~~~~~
                            12:00:45
                            	12:56:49:203
                            13:04:51:387
                            15:15:33:632
                            17:22:00:814
                                    19:33:55:548
                            21:45:26
                            23:59:11:247
                            

                            Best Regards,

                            guy038

                            1 Reply Last reply Reply Quote 3
                            • guy038G Offline
                              guy038
                              last edited by guy038

                              Hi, All,

                              When I woke up this morning, I immediately saw a simplification ( in length ! ) of the replacement regex ;-))

                              So, my last version is :

                              SEARCH \b(0(?:(1)|(2)|(3)|(4)|(5)|(6)|(7)|(8)|(9))|(10)|(11)|(12)).(\d\d).(\d\d)(?:.(\d{3}))?\x20?(?i:(AM)|PM)

                              REPLACE (?13(?{17}00:\1):(?17\1:(?{2}13)(?{3}14)(?{4}15)(?{5}16)(?{6}17)(?{7}18)(?{8}19)(?{9}20)(?{10}21)(?{11}22)(?{12}23))):$14:$15(?16\:$16)

                              BR

                              guy038

                              1 Reply Last reply Reply Quote 3
                              • guy038G Offline
                                guy038
                                last edited by

                                Hi, all,

                                As the (?...:....) regex structure, of the Boost regex library is not so common, you may feel a bit lost about the replacement regex syntax !

                                So, here is, below, the algorithmic translation of the replacement regex, of my previous post :

                                If group 13 exists    #  Case hour = '12'
                                
                                    then
                                
                                        If group 17 exists    #  String 'AM' or 'am', after the digits
                                  
                                            then
                                
                                                Write the string '00'
                                
                                            else
                                
                                                Rewrite the group 1 contents    #  Actually, the hour '12'
                                
                                    else
                                
                                        If group 17 exists    #  String 'AM' or 'am', after the digits
                                
                                            then
                                
                                                Rewrite the group 1 contents    #  The 'hour' digits, so the values  '01'  or  '02'  or  ...... '11'
                                
                                            else    #  The 'hour' digits, when followed with the string 'PM' or 'pm'
                                
                                                If group  2 exists then write the string '13'    #  Case hour = '01'
                                
                                                If group  3 exists then write the string '14'    #  Case hour = '02'
                                
                                                If group  4 exists then write the string '15'    #  Case hour = '03'
                                
                                                If group  5 exists then write the string '16'    #  Case hour = '04'
                                
                                                If group  6 exists then write the string '17'    #  Case hour = '05'
                                
                                                If group  7 exists then write the string '18'    #  Case hour = '06'
                                
                                                If group  8 exists then write the string '19'    #  Case hour = '07'
                                
                                                If group  9 exists then write the string '20'    #  Case hour = '08'
                                
                                                If group 10 exists then write the string '21'    #  Case hour = '09'
                                
                                                If group 11 exists then write the string '22'    #  Case hour = '10'
                                
                                                If group 12 exists then write the string '23'    #  Case hour = '11'
                                
                                       endif
                                
                                endif
                                
                                Write the string ':'
                                
                                Rewrite the group 14    #  Minutes digits
                                
                                Write the string ':'
                                
                                Rewrite the group 15    #  Seconds digits
                                
                                if group 16 exits       #  Milleseconds digits
                                
                                    then
                                
                                        write the string ':'
                                
                                        write the group 16 contents    # Milleseconds digits
                                endif
                                

                                BR

                                guy038

                                1 Reply Last reply Reply Quote 3

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