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    • pinuzzu99P
      pinuzzu99
      last edited by

      first method work but it remains only one address… everything else is deleted!
      i want keep ALL address mail and passw like xxx@xx.xxx:dddd

      second method it relates only to a specific email address, instead I have several, all different…

      Alan KilbornA 1 Reply Last reply Reply Quote 0
      • Alan KilbornA
        Alan Kilborn @pinuzzu99
        last edited by

        @pinuzzu99

        Hmm. This forum doesn’t exist for someone else to do your work for you. Some hints about how a feature of Notepad++ works, yes, but really, don’t expect to say “I need this very specific thing” and expect someone to hand it to you.

        You’re expected to try things on your own, and present your (failed) results here and then you’ll probably receive help on just that aspect.

        But wholesale problem statement and solution provided…nope.

        1 Reply Last reply Reply Quote 1
        • pinuzzu99P
          pinuzzu99
          last edited by

          works well with (on reg ex):
          find what: (?-s)^(?!\h*\w+@).
          replace with:

          bt some mail is of the type:
          name.gress@mail.com
          and the first part of the email is deleted (in this specific case the term “name”)…
          how to leave full email address?

          1 Reply Last reply Reply Quote 0
          • pinuzzu99P
            pinuzzu99
            last edited by

            I have found this that serves my purpose:
            \S+?@\S+?.\S+
            this regex select all my address@mail.com:numberletters

            now i would like to add part of string to delete the rest of the text in my txt…

            1 Reply Last reply Reply Quote 0
            • guy038G
              guy038
              last edited by

              Hello, @pinuzzu99 and All,

              Well, it’s just up to you ! All your previous e-mail addresses did not contain any dot before the @ char. Thus, I supposed that there were only word characters !

              With , your last example name.gress@mail.com, of course, the regex S/R should become :

              SEARCH (?-s)^(?!\h*[\w.]+@).+\R

              REPLACE Leave EMPTY


              Then, you said :

              now i would like to add part of string to delete the rest of the text in my txt

              I’m sorry but it’s really not clear to my mind !

              Please, give us a sample of your input text, with various e-mail adresses and show us the output text you are expecting to, from your present input example !


              Just a hint : when replying, type your input and output text as code, using the symbol </> , as below :

              See you later,

              Cheers,

              guy038

              1 Reply Last reply Reply Quote 1
              • pinuzzu99P
                pinuzzu99
                last edited by

                you are very kind of you. this is little extract of my txt file

                .: data :.
                =================================
                asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
                =================================
                 
                ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
                .: data :.
                =================================
                asda cartgrtgrg@gfgbil.com:1r5yyr78115
                Pry Statinf: Kree
                =================================
                 
                ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
                .: data :.
                =================================
                asda jatrhtrh@grthil.com:mrthhrhmm17
                Pry Statinf: Kree
                =================================
                 
                ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
                .: data :.
                =================================
                asda lathmhjm@hhhjail.com:p456456inha
                Pry Statinf: Kree
                

                i want delete all text and line except
                mail.address@mail.com:xxxxxxxx

                with your string not work for me.
                work with (?-s)^(?!\h*[\w.]+@).
                but i have this result:

                
                
                 pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
                
                
                
                
                
                 cartgrtgrg@gfgbil.com:1r5yyr78115
                
                
                
                
                
                
                 jatrhtrh@grthil.com:mrthhrhmm17
                
                
                
                
                
                
                 lathmhjm@hhhjail.com:p456456inha
                
                

                empty line between emails and also one space before any mail address.
                I hope it helps me to complete the correct string!

                1 Reply Last reply Reply Quote 0
                • guy038G
                  guy038
                  last edited by guy038

                  Hi, @pinuzzu99 and All,

                  Ok ! So, assuming your short example, below :

                  .: data :.
                  =================================
                  asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
                  =================================
                   
                  ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
                  .: data :.
                  =================================
                  asda cartgrtgrg@gfgbil.com:1r5yyr78115
                  Pry Statinf: Kree
                  =================================
                   
                  ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
                  .: data :.
                  =================================
                  asda jatrhtrh@grthil.com:mrthhrhmm17
                  Pry Statinf: Kree
                  =================================
                   
                  ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
                  .: data :.
                  =================================
                  asda lathmhjm@hhhjail.com:p456456inha
                  Pry Statinf: Kree
                  

                  The following regex S/R :

                  SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?

                  REPLACE Leave EMPTY

                  gives this output text :

                  asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
                  asda cartgrtgrg@gfgbil.com:1r5yyr78115
                  asda jatrhtrh@grthil.com:mrthhrhmm17
                  asda lathmhjm@hhhjail.com:p456456inha
                  

                  Are you expecting this result ?

                  I simply suppose that the non-null part of an e-mail address, located before the @ char, may contain :

                  • Any word character

                  • A dot symbol

                  • A space character

                  Best Regards,

                  guy038

                  1 Reply Last reply Reply Quote 1
                  • pinuzzu99P
                    pinuzzu99
                    last edited by

                    thank you very much. excellent result. I’d still like if you could also delete the first part of the text in front of the email from:
                    asda address@mail.com: mrthhrhmm17
                    until you get:
                    address@mail.com: mrthhrhmm17
                    this of course for all the email addresses listed …

                    1 Reply Last reply Reply Quote 0
                    • guy038G
                      guy038
                      last edited by guy038

                      Hi, @pinuzzu99 and All,

                      No problem ! If we assume that there are no space char in e-mail addressses ( generally the case ! ) and further on, in current scanned line, we just need to add an alternative which, implicitly, looks for lines with an e-mail address and deletes from beginning of current line till a non-null range of space characters. Thus, the following regex S/R :

                      SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+

                      REPLACE Leave EMPTY

                      And you’ll obtain your expected result :

                      pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
                      cartgrtgrg@gfgbil.com:1r5yyr78115
                      jatrhtrh@grthil.com:mrthhrhmm17
                      lathmhjm@hhhjail.com:p456456inha
                      

                      Best Regards,

                      guy038

                      1 Reply Last reply Reply Quote 1
                      • pinuzzu99P
                        pinuzzu99
                        last edited by

                        oh yes! finally what i wanted!
                        thank you very much, dear guy038.

                        1 Reply Last reply Reply Quote 0
                        • pinuzzu99P
                          pinuzzu99
                          last edited by

                          another little help:
                          i have another txt with text like this:

                          ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
                          jegfa@nkcore.com:jeryr55673:1757810123:53687091200
                          ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
                          v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200
                          

                          i need have like this:

                          code_text
                          ladgdfg_jfdggs@yertynno.com.vn:1234556
                          jegfa@nkcore.com:jeryr55673
                          ghyfm36@rocgfhmmail.com:mintgg18509
                          v7cifgthhy@yasbco.com.tw:512454215
                          

                          i want delete all :number:number

                          Alan KilbornA 1 Reply Last reply Reply Quote -1
                          • Alan KilbornA
                            Alan Kilborn @pinuzzu99
                            last edited by

                            @pinuzzu99

                            What have you tried?
                            What did you get?
                            What didn’t work about it?

                            1 Reply Last reply Reply Quote 1
                            • pinuzzu99P
                              pinuzzu99
                              last edited by

                              which regex is needed to eliminate :number:number at the end of each line

                              1 Reply Last reply Reply Quote -1
                              • guy038G
                                guy038
                                last edited by guy038

                                Hi, @pinuzzu99 and All,

                                Nice ! I even succeded to merge your two kinds of text, by adding a third alternative in the search regex !


                                So, starting with the input text, below, where the e-mail adresses may be :

                                • Preceded with any chars ( asda, 12345 …), followed with, at least, one space char OR beginning the line

                                • Followed with, at least, one field, determined by a colon separator char

                                bla bla blah
                                bla bla blah
                                bla bla blah
                                asda ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
                                bla bla blah
                                bla bla blah
                                jegfa@nkcore.com:jeryr55673:1757810123:53687091200
                                bla bla blah
                                bla bla blah
                                12345      ghyfm36@rocgfhmmail.com:mintgg18509:0000000000000:1111111111:55555555555555:777777777777777777:99999999999
                                bla bla blah
                                bla bla blah
                                bla bla blah
                                asda           v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200
                                

                                Use the following regex S/R :

                                • SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+|.+?:.+?\K:.+

                                • REPLACE Leave EMPTY

                                • Of course, the Regular expression search mode is selected and the Wrap around option is ticked

                                • You must use the Replace All button, exclusively ( Not the Replace button ! )

                                We get the following output text :

                                ladgdfg_jfdggs@yertynno.com.vn:1234556
                                jegfa@nkcore.com:jeryr55673
                                ghyfm36@rocgfhmmail.com:mintgg18509
                                v7cifgthhy@yasbco.com.tw:512454215
                                

                                Notes :

                                This regular expression is composed of 3 alternatives :

                                • The first part (?-s)^(?!\h*[\w.\x20]+@).*\R?, which have been explained previouly. If deletes any entire line, which does not contain a @ char, after a non-null range of words chars and possible dot and/or space chars

                                • The second part ^.*?\x20+ which deletes all text between beginning of line and a non-null range of space characters, if that line contains an e-mail address, further on

                                • The third part .+?:.+?\K:.+ deletes, after the e-mail adress, from the second : char found till the last standard char of the current scanned line

                                • Note, in this last part, the use of the lazy quantifier +? to identify all standard chars between the first and the second : chars and the \K syntax before the second : char, which resets the overall search and just grabs all the remaining chars of current line, from the second :, included


                                Remark :

                                I strongly advice you to learn the regular expresions world ! Of course, you’ll have to study for 1/2 months, but it’s really worth it ;-)). To begin with, consult this FAQ :

                                https://community.notepad-plus-plus.org/topic/15765/faq-desk-where-to-find-regex-documentation

                                Best Regards,

                                guy038

                                1 Reply Last reply Reply Quote 1
                                • pinuzzu99P
                                  pinuzzu99
                                  last edited by

                                  ohhhhh very great! many thanks for your help! very very thanks.
                                  and you’re right when you say you have to study. and usually I do. but in the case of np ++ using little, it did not occur to me to search and learn reg ex expressions. but I will take your suggestion into account.

                                  for my question: this is ANOTHER txt, then different. but anyway you code work great, my intent was that! very very many thanks for your help!
                                  Regards

                                  1 Reply Last reply Reply Quote 0
                                  • guy038G
                                    guy038
                                    last edited by

                                    Hi, @pinuzzu99,

                                    Ah, OK ! So, if we consider that there were 2 separate tasks and starting with your exact input text, below :

                                    ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
                                    jegfa@nkcore.com:jeryr55673:1757810123:53687091200
                                    ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
                                    v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200
                                    

                                    The following regex S/R :

                                    • SEARCH (?-s)^.+?:.+?\K:.+

                                    • REPLACE Leave EMPTY

                                    • Click on the Replace All button, exclusively

                                    should leave you with your expected result :

                                    ladgdfg_jfdggs@yertynno.com.vn:1234556
                                    jegfa@nkcore.com:jeryr55673
                                    ghyfm36@rocgfhmmail.com:mintgg18509
                                    v7cifgthhy@yasbco.com.tw:512454215
                                    

                                    Cheers,

                                    guy038

                                    1 Reply Last reply Reply Quote 0
                                    • pinuzzu99P
                                      pinuzzu99
                                      last edited by

                                      thanks you so much, again! cheers

                                      1 Reply Last reply Reply Quote 0
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