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    • pinuzzu99P
      pinuzzu99
      last edited by

      works well with (on reg ex):
      find what: (?-s)^(?!\h*\w+@).
      replace with:

      bt some mail is of the type:
      name.gress@mail.com
      and the first part of the email is deleted (in this specific case the term “name”)…
      how to leave full email address?

      1 Reply Last reply Reply Quote 0
      • pinuzzu99P
        pinuzzu99
        last edited by

        I have found this that serves my purpose:
        \S+?@\S+?.\S+
        this regex select all my address@mail.com:numberletters

        now i would like to add part of string to delete the rest of the text in my txt…

        1 Reply Last reply Reply Quote 0
        • guy038G
          guy038
          last edited by

          Hello, @pinuzzu99 and All,

          Well, it’s just up to you ! All your previous e-mail addresses did not contain any dot before the @ char. Thus, I supposed that there were only word characters !

          With , your last example name.gress@mail.com, of course, the regex S/R should become :

          SEARCH (?-s)^(?!\h*[\w.]+@).+\R

          REPLACE Leave EMPTY

          Then, you said :

          now i would like to add part of string to delete the rest of the text in my txt

          I’m sorry but it’s really not clear to my mind !

          Please, give us a sample of your input text, with various e-mail adresses and show us the output text you are expecting to, from your present input example !

          Just a hint : when replying, type your input and output text as code, using the symbol </> , as below :

          See you later,

          Cheers,

          guy038

          1 Reply Last reply Reply Quote 1
          • pinuzzu99P
            pinuzzu99
            last edited by

            you are very kind of you. this is little extract of my txt file

            .: data :.
=================================
asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
=================================
 
ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
.: data :.
=================================
asda cartgrtgrg@gfgbil.com:1r5yyr78115
Pry Statinf: Kree
=================================
 
ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
.: data :.
=================================
asda jatrhtrh@grthil.com:mrthhrhmm17
Pry Statinf: Kree
=================================
 
ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
.: data :.
=================================
asda lathmhjm@hhhjail.com:p456456inha
Pry Statinf: Kree

            i want delete all text and line except
            mail.address@mail.com:xxxxxxxx

            with your string not work for me.
            work with (?-s)^(?!\h*[\w.]+@).
            but i have this result:

            

 pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr





 cartgrtgrg@gfgbil.com:1r5yyr78115






 jatrhtrh@grthil.com:mrthhrhmm17






 lathmhjm@hhhjail.com:p456456inha

            empty line between emails and also one space before any mail address.
            I hope it helps me to complete the correct string!

            1 Reply Last reply Reply Quote 0
            • guy038G
              guy038
              last edited by guy038

              Hi, @pinuzzu99 and All,

              Ok ! So, assuming your short example, below :

              .: data :.
=================================
asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
=================================
 
ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
.: data :.
=================================
asda cartgrtgrg@gfgbil.com:1r5yyr78115
Pry Statinf: Kree
=================================
 
ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
.: data :.
=================================
asda jatrhtrh@grthil.com:mrthhrhmm17
Pry Statinf: Kree
=================================
 
ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
.: data :.
=================================
asda lathmhjm@hhhjail.com:p456456inha
Pry Statinf: Kree

              The following regex S/R :

              SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?

              REPLACE Leave EMPTY

              gives this output text :

              asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
asda cartgrtgrg@gfgbil.com:1r5yyr78115
asda jatrhtrh@grthil.com:mrthhrhmm17
asda lathmhjm@hhhjail.com:p456456inha

              Are you expecting this result ?

              I simply suppose that the non-null part of an e-mail address, located before the @ char, may contain :

              • Any word character

              • A dot symbol

              • A space character

              Best Regards,

              guy038

              1 Reply Last reply Reply Quote 1
              • pinuzzu99P
                pinuzzu99
                last edited by

                thank you very much. excellent result. I’d still like if you could also delete the first part of the text in front of the email from:
                asda address@mail.com: mrthhrhmm17
                until you get:
                address@mail.com: mrthhrhmm17
                this of course for all the email addresses listed …

                1 Reply Last reply Reply Quote 0
                • guy038G
                  guy038
                  last edited by guy038

                  Hi, @pinuzzu99 and All,

                  No problem ! If we assume that there are no space char in e-mail addressses ( generally the case ! ) and further on, in current scanned line, we just need to add an alternative which, implicitly, looks for lines with an e-mail address and deletes from beginning of current line till a non-null range of space characters. Thus, the following regex S/R :

                  SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+

                  REPLACE Leave EMPTY

                  And you’ll obtain your expected result :

                  pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
cartgrtgrg@gfgbil.com:1r5yyr78115
jatrhtrh@grthil.com:mrthhrhmm17
lathmhjm@hhhjail.com:p456456inha

                  Best Regards,

                  guy038

                  1 Reply Last reply Reply Quote 1
                  • pinuzzu99P
                    pinuzzu99
                    last edited by

                    oh yes! finally what i wanted!
                    thank you very much, dear guy038.

                    1 Reply Last reply Reply Quote 0
                    • pinuzzu99P
                      pinuzzu99
                      last edited by

                      another little help:
                      i have another txt with text like this:

                      ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                      i need have like this:

                      code_text
ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                      i want delete all :number:number

                      Alan KilbornA 1 Reply Last reply Reply Quote -1
                      • Alan KilbornA
                        Alan Kilborn @pinuzzu99
                        last edited by

                        @pinuzzu99

                        What have you tried?
                        What did you get?
                        What didn’t work about it?

                        1 Reply Last reply Reply Quote 1
                        • pinuzzu99P
                          pinuzzu99
                          last edited by

                          which regex is needed to eliminate :number:number at the end of each line

                          1 Reply Last reply Reply Quote -1
                          • guy038G
                            guy038
                            last edited by guy038

                            Hi, @pinuzzu99 and All,

                            Nice ! I even succeded to merge your two kinds of text, by adding a third alternative in the search regex !

                            So, starting with the input text, below, where the e-mail adresses may be :

                            • Preceded with any chars ( asda, 12345 …), followed with, at least, one space char OR beginning the line

                            • Followed with, at least, one field, determined by a colon separator char

                            bla bla blah
bla bla blah
bla bla blah
asda ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
bla bla blah
bla bla blah
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
bla bla blah
bla bla blah
12345      ghyfm36@rocgfhmmail.com:mintgg18509:0000000000000:1111111111:55555555555555:777777777777777777:99999999999
bla bla blah
bla bla blah
bla bla blah
asda           v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                            Use the following regex S/R :

                            • SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+|.+?:.+?\K:.+

                            • REPLACE Leave EMPTY

                            • Of course, the Regular expression search mode is selected and the Wrap around option is ticked

                            • You must use the Replace All button, exclusively ( Not the Replace button ! )

                            We get the following output text :

                            ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                            Notes :

                            This regular expression is composed of 3 alternatives :

                            • The first part (?-s)^(?!\h*[\w.\x20]+@).*\R?, which have been explained previouly. If deletes any entire line, which does not contain a @ char, after a non-null range of words chars and possible dot and/or space chars

                            • The second part ^.*?\x20+ which deletes all text between beginning of line and a non-null range of space characters, if that line contains an e-mail address, further on

                            • The third part .+?:.+?\K:.+ deletes, after the e-mail adress, from the second : char found till the last standard char of the current scanned line

                            • Note, in this last part, the use of the lazy quantifier +? to identify all standard chars between the first and the second : chars and the \K syntax before the second : char, which resets the overall search and just grabs all the remaining chars of current line, from the second :, included

                            Remark :

                            I strongly advice you to learn the regular expresions world ! Of course, you’ll have to study for 1/2 months, but it’s really worth it ;-)). To begin with, consult this FAQ :

                            https://community.notepad-plus-plus.org/topic/15765/faq-desk-where-to-find-regex-documentation

                            Best Regards,

                            guy038

                            1 Reply Last reply Reply Quote 1
                            • pinuzzu99P
                              pinuzzu99
                              last edited by

                              ohhhhh very great! many thanks for your help! very very thanks.
                              and you’re right when you say you have to study. and usually I do. but in the case of np ++ using little, it did not occur to me to search and learn reg ex expressions. but I will take your suggestion into account.

                              for my question: this is ANOTHER txt, then different. but anyway you code work great, my intent was that! very very many thanks for your help!
                              Regards

                              1 Reply Last reply Reply Quote 0
                              • guy038G
                                guy038
                                last edited by

                                Hi, @pinuzzu99,

                                Ah, OK ! So, if we consider that there were 2 separate tasks and starting with your exact input text, below :

                                ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                                The following regex S/R :

                                • SEARCH (?-s)^.+?:.+?\K:.+

                                • REPLACE Leave EMPTY

                                • Click on the Replace All button, exclusively

                                should leave you with your expected result :

                                ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                                Cheers,

                                guy038

                                1 Reply Last reply Reply Quote 0
                                • pinuzzu99P
                                  pinuzzu99
                                  last edited by

                                  thanks you so much, again! cheers

                                  1 Reply Last reply Reply Quote 0
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