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    • guy038G
      guy038
      last edited by guy038

      Hi, @pinuzzu99 and All,

      Ok ! So, assuming your short example, below :

      .: data :.
=================================
asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
=================================
 
ubba:/my-wallets.zip                               379912     2019-08-07T02:52:11+02:00
.: data :.
=================================
asda cartgrtgrg@gfgbil.com:1r5yyr78115
Pry Statinf: Kree
=================================
 
ubba:/crypto.zip                                   380547     2019-08-07T02:50:07+02:00
.: data :.
=================================
asda jatrhtrh@grthil.com:mrthhrhmm17
Pry Statinf: Kree
=================================
 
ubba:/wallets.zip                                  379807     2019-08-07T02:58:33+02:00
.: data :.
=================================
asda lathmhjm@hhhjail.com:p456456inha
Pry Statinf: Kree

      The following regex S/R :

      SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?

      REPLACE Leave EMPTY

      gives this output text :

      asda pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
asda cartgrtgrg@gfgbil.com:1r5yyr78115
asda jatrhtrh@grthil.com:mrthhrhmm17
asda lathmhjm@hhhjail.com:p456456inha

      Are you expecting this result ?

      I simply suppose that the non-null part of an e-mail address, located before the @ char, may contain :

      • Any word character

      • A dot symbol

      • A space character

      Best Regards,

      guy038

      1 Reply Last reply Reply Quote 1
      • pinuzzu99P
        pinuzzu99
        last edited by

        thank you very much. excellent result. I’d still like if you could also delete the first part of the text in front of the email from:
        asda address@mail.com: mrthhrhmm17
        until you get:
        address@mail.com: mrthhrhmm17
        this of course for all the email addresses listed …

        1 Reply Last reply Reply Quote 0
        • guy038G
          guy038
          last edited by guy038

          Hi, @pinuzzu99 and All,

          No problem ! If we assume that there are no space char in e-mail addressses ( generally the case ! ) and further on, in current scanned line, we just need to add an alternative which, implicitly, looks for lines with an e-mail address and deletes from beginning of current line till a non-null range of space characters. Thus, the following regex S/R :

          SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+

          REPLACE Leave EMPTY

          And you’ll obtain your expected result :

          pamfhdjosa.mardedyly@ydefgo.com:cloggr4trr
cartgrtgrg@gfgbil.com:1r5yyr78115
jatrhtrh@grthil.com:mrthhrhmm17
lathmhjm@hhhjail.com:p456456inha

          Best Regards,

          guy038

          1 Reply Last reply Reply Quote 1
          • pinuzzu99P
            pinuzzu99
            last edited by

            oh yes! finally what i wanted!
            thank you very much, dear guy038.

            1 Reply Last reply Reply Quote 0
            • pinuzzu99P
              pinuzzu99
              last edited by

              another little help:
              i have another txt with text like this:

              ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

              i need have like this:

              code_text
ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

              i want delete all :number:number

              Alan KilbornA 1 Reply Last reply Reply Quote -1
              • Alan KilbornA
                Alan Kilborn @pinuzzu99
                last edited by

                @pinuzzu99

                What have you tried?
                What did you get?
                What didn’t work about it?

                1 Reply Last reply Reply Quote 1
                • pinuzzu99P
                  pinuzzu99
                  last edited by

                  which regex is needed to eliminate :number:number at the end of each line

                  1 Reply Last reply Reply Quote -1
                  • guy038G
                    guy038
                    last edited by guy038

                    Hi, @pinuzzu99 and All,

                    Nice ! I even succeded to merge your two kinds of text, by adding a third alternative in the search regex !

                    So, starting with the input text, below, where the e-mail adresses may be :

                    • Preceded with any chars ( asda, 12345 …), followed with, at least, one space char OR beginning the line

                    • Followed with, at least, one field, determined by a colon separator char

                    bla bla blah
bla bla blah
bla bla blah
asda ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
bla bla blah
bla bla blah
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
bla bla blah
bla bla blah
12345      ghyfm36@rocgfhmmail.com:mintgg18509:0000000000000:1111111111:55555555555555:777777777777777777:99999999999
bla bla blah
bla bla blah
bla bla blah
asda           v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                    Use the following regex S/R :

                    • SEARCH (?-s)^(?!\h*[\w.\x20]+@).*\R?|^.*?\x20+|.+?:.+?\K:.+

                    • REPLACE Leave EMPTY

                    • Of course, the Regular expression search mode is selected and the Wrap around option is ticked

                    • You must use the Replace All button, exclusively ( Not the Replace button ! )

                    We get the following output text :

                    ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                    Notes :

                    This regular expression is composed of 3 alternatives :

                    • The first part (?-s)^(?!\h*[\w.\x20]+@).*\R?, which have been explained previouly. If deletes any entire line, which does not contain a @ char, after a non-null range of words chars and possible dot and/or space chars

                    • The second part ^.*?\x20+ which deletes all text between beginning of line and a non-null range of space characters, if that line contains an e-mail address, further on

                    • The third part .+?:.+?\K:.+ deletes, after the e-mail adress, from the second : char found till the last standard char of the current scanned line

                    • Note, in this last part, the use of the lazy quantifier +? to identify all standard chars between the first and the second : chars and the \K syntax before the second : char, which resets the overall search and just grabs all the remaining chars of current line, from the second :, included

                    Remark :

                    I strongly advice you to learn the regular expresions world ! Of course, you’ll have to study for 1/2 months, but it’s really worth it ;-)). To begin with, consult this FAQ :

                    https://community.notepad-plus-plus.org/topic/15765/faq-desk-where-to-find-regex-documentation

                    Best Regards,

                    guy038

                    1 Reply Last reply Reply Quote 1
                    • pinuzzu99P
                      pinuzzu99
                      last edited by

                      ohhhhh very great! many thanks for your help! very very thanks.
                      and you’re right when you say you have to study. and usually I do. but in the case of np ++ using little, it did not occur to me to search and learn reg ex expressions. but I will take your suggestion into account.

                      for my question: this is ANOTHER txt, then different. but anyway you code work great, my intent was that! very very many thanks for your help!
                      Regards

                      1 Reply Last reply Reply Quote 0
                      • guy038G
                        guy038
                        last edited by

                        Hi, @pinuzzu99,

                        Ah, OK ! So, if we consider that there were 2 separate tasks and starting with your exact input text, below :

                        ladgdfg_jfdggs@yertynno.com.vn:1234556:1654473467:53687091200
jegfa@nkcore.com:jeryr55673:1757810123:53687091200
ghyfm36@rocgfhmmail.com:mintgg18509:11767409268:53687091200
v7cifgthhy@yasbco.com.tw:512454215:380488:53687091200

                        The following regex S/R :

                        • SEARCH (?-s)^.+?:.+?\K:.+

                        • REPLACE Leave EMPTY

                        • Click on the Replace All button, exclusively

                        should leave you with your expected result :

                        ladgdfg_jfdggs@yertynno.com.vn:1234556
jegfa@nkcore.com:jeryr55673
ghyfm36@rocgfhmmail.com:mintgg18509
v7cifgthhy@yasbco.com.tw:512454215

                        Cheers,

                        guy038

                        1 Reply Last reply Reply Quote 0
                        • pinuzzu99P
                          pinuzzu99
                          last edited by

                          thanks you so much, again! cheers

                          1 Reply Last reply Reply Quote 0
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