add text to even lines

cisco779k

hi everybody, i have a long txt and i need to add some text only to even lines. how to?

example:
#summer
0000-gold
#summer
0001-gold
#summer
0002-gold

i need to have:
#summer
text/0000-gold
#summer
text/0001-gold
#summer
text/0002-gold

Lycan Thrope

Find: (#summer\n)(.+)
Replace: $1text/$2

Alan Kilborn

@lycan-thrope

Oooh, that’s not great. :-(

Why?

summer was not in the requirements (much better would have been a requirement – of the solution – to move the caret to top of file before running, and thus the solution could take care of the “even lines” requirement)
\n is not good – if this file has windows line-endings, it isn’t going to work – use \R instead
there’s no specification to use regular expression search mode
there’s no specification to make sure that . matches newline is unticked (and no usage of a leading (?-s) on the find expression)

cisco779k

@lycan-thrope said in add text to even lines:

Find: (#summer\n)(.+)
Replace: $1text/$2

yes, this command does not work

Terry R

@lycan-thrope

I would change the \n for \R as we don’t know the format of the text file in terms of CR (carriage returns) and/or LF (line feeds) for line endings. This covers both bases.

But; as in most cases; I suspect the example provided isn’t actually a good representation.

When using a regular expression and selecting “Replace All” AND “Wrap around” the expression WILL start at line 1. So a regex that captures 2 lines will do so in the same manner requested. This was explained in a series of posts here provides a link to those.

For example (?-s)^(.+\R)(.+\R?) will capture line 1 & 2. Then the next iteration will capture 3 & 4 and so on. The \R? is so the last line which will not have a CR and/or LF will still be captured.

There is another method of determining the even numbered lines which involves some steps including adding numbers to the start of each line, as this would require placing the caret in the first position of the file we guarantee correct line placement. Each number would be repeated, so it shows twice, like 1 1 2 2 3 3 4 4… . Then a regex would remove the first one of the pair. The next regex could then identify the added number which references the “even” numbered line and use that as a key to edit the correct line. Lastly the added numbers could be removed. This is a much more involved process and I think unneeded as the “Replace All” and “Wrap around” option will work as intended.

Terry

PS my example regex assumes data on each line

cisco779k

thank you to all for replies

anyway, thank to suggestion by Alan Kilborn, the string by Lycan Thrope work fine with simply replace:

find what: (#summer\R)(.+)
replace: $1text/$2

cisco779k

another question: from my long txt file, i have found some different value. sometime i have:

#summer:4,
0000-gold
#summer:4,
0001-gold
#summer:5.625,
0002-gold
#summer:4,
0003-gold
#summer:7.2,
0004-gold

and i need to have:

#summer:4,
text/0000-gold
#summer:4,
text/0001-gold
#summer:5.625,
text/0002-gold
#summer:4,
text/0003-gold
#summer:7.2,
text/0004-gold

only the first part are the same #summer:
so, i have try with:

(#summer:\R)(.+)
replace: $1text/$2

but this command does not work. how to?

cisco779k

if this question it’s hard to get, another solution could be to look on my txt all the values that do not correspond to #summer:4, (as in the case of #summer:5.625,)

this would be enough for me

guy038

Hello, @cisco779k, @lycan-thrope, @alan-kilborn, @terry-r and All,

The correct regex, in this case, is :

SEARCH (?-s)^(#summer:.*\R)(.+)

REPLACE: $1text/$2

This search syntax will work, either, with lines #summer:.... and lines #summer !

Best Regards,

guy038

cisco779k

guy, thank you so much for your string. it work like a charm

all the best