REGEX: Mark/Delete the 2 second line after some word

[Vasile Caraus]

hello everyone. I need to mark/delete the 2 second line after some word. For exemple:

1.line
2.line
3.bla bla bla WORD_1 bla bla
4.line
5.line
6.line ETC

So, I want to delete the line that contains WORD_1 and the next 2 lines (but without line 6). Can anyone help me?

I try this regex, this will delete the line with WORD_1, but will not delete line 4 and 5. But will insert another line 4 instead delete.

Search:
^.*WORD_1.*$
Replace by:
\n\n

[guy038]

Hello, Vasile,

Not difficult, indeed !

The general regex S/R, which deletes ANY line, containing a SPECIFIC word, with generic name = WORD, along with the N lines, following this line, is :

SEARCH (?-s)^.*WORD.*\R(.*\R){N}

REPLACE EMPTY

So, in your case, the search regex should be (?-s)^.*WORD_1.*\R(.*\R){2}

---

In the same way, the general regex S/R, below, which would delete ANY line, containing the word WORD and the N lines located BEFORE this line, is :

SEARCH (?-s)(.*\R){N}.*WORD.*\R

REPLACE EMPTY

---

Notes :

• Due to the (?-s) modifier, the dot, ., stands for a single standard character, only

• As usual, the \R syntax matches any kind of Line Break ( \r\n in Windows files, \n in Unix files or \r in old Mac files )

• The part .*\R represents a complete line, even empty, with its EOL character(s)

• So the syntax (.*\R){N}, where N is an integer, stands N complete lines

Best Regards

guy038

[Vasile Caraus]

well, guy38, nice present for me.

thanks a lot !

This is for you !

https://www.youtube.com/watch?v=nPW5nfoIYf8