Regular expression - delete last character on line
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I would be really grateful if someone could help me with a regular expression issue.
I want to find every line that starts ‘//’ (easy enough) and then delete the last character on that line, which will be a ‘}’.
I have looked through the documentation and I can’t work out how to do it. What I assume that one has to do is output the whole line bar the last character, but I can’t work out how to do it.
Any suggestion would be really appreciated.
Many thanks
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In regex ^ is the start and $ the end anchor.
In per line mode (default mode in npp) you would search for^(//.*)\}$you need to escape the } as this has also a special meaning in regex sytanx
In replace you would use\1For more information see here.
Cheers
Claudia -
@Claudia-Frank Thanks. Sorted.
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