Regular expression - delete last character on line

[lazarusr]

I would be really grateful if someone could help me with a regular expression issue.

I want to find every line that starts ‘//’ (easy enough) and then delete the last character on that line, which will be a ‘}’.

I have looked through the documentation and I can’t work out how to do it. What I assume that one has to do is output the whole line bar the last character, but I can’t work out how to do it.

Any suggestion would be really appreciated.

Many thanks

[Claudia Frank]

@lazarusr

In regex ^ is the start and $ the end anchor.
In per line mode (default mode in npp) you would search for

^(//.*)\}$

you need to escape the } as this has also a special meaning in regex sytanx
In replace you would use

\1

For more information see here .

Cheers
Claudia

[lazarusr]

@Claudia-Frank Thanks. Sorted.