Insert a string after each number of words with conditions

guy038

Oh ! Sorry. I, initially, thought that you wrote the string [NEW LINE], as a notation for a Line Break ! But, you did mean the litteral string [NEW LINE] ;-))

Cheers,

guy038

hu ma

Ummm…
Back again, there is one more thing I need to do.
Continuing with example#2 result which was

Greetings My Liege! As your personal advisor[NEWLINE], I am qualified to assist you in all[NEWLINE] matters related to ruling our civilization.[NEWLINE] I am at your service.

Seeked arrangement
I am at your service. [NEWLINE] matters related to ruling our civilization.[NEWLINE], I am qualified to assist you in all[NEWLINE]Greetings My Liege! As your personal advisor

To put an understanding to it, I want to capture the text before, between, and after the string [NEWLINE] and change their order from \1\2\3\4 to \4\3\2\1.
I can achieve this by first replacing the string [NEWLINE] to say ✓✓✓, then capture them by this regex
search: (.+[\x{0000}-\x{9faf}])✓✓✓(.+[\x{0000}\x{9faf}])✓✓✓(.+[\x{0000}\x{9faf}])✓✓✓(.+[\x{0000}\x{9faf}])
Replace : \4[NEWLINE]\3[NEWLINE]\2[NEWLINE]\1

That can be happened, but I know this method can only work up to 9 captured groups, and I had some of them excceding 9 groups.

Scott Sumner

@hu-ma said:

but I know this method can only work up to 9 captured groups

If you use the \number syntax, your statement is true.
If you switch to the $number syntax, you can go higher than 9.

For example, if you search for this regex: (a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m)(n)
And replace it with $10
On this text: abcdefghijklmnopqrstuvwxyz
You will obtain: jopqrstuvwxyz

Contrast with this example:
search for this regex: (a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m)(n)
And replace it with \10
On this text: abcdefghijklmnopqrstuvwxyz
You will obtain: a0opqrstuvwxyz

Alan Kilborn

@guy038

I was playing around with this idea and I’m not sure I see the importance of introducing the complication of the “longest word in English” stuff. For example, if I experiment with a variant of the regex that ignores this, I still get nice results:

Find: (?-s)(.{1,43})\W
Replace: $1\r\n

…gives me nice text wrapping after the desired amount of columns.

guy038

Hi, @abuali-huma, @scott-sumner and @alan-kilborn,

Alan, looking again to my previous post, you’re absolutely right about it. Can’t understand why I thought that the length of words was so important ! I should have been excessively tired, two days ago ;-))

So , I’ve just completely updated my previous post, mentioning your contribution to that nicer regex. Thanks for that !

As for your own S/R, below :

SEARCH (?-s)(.{1,43})\W

REPLACE $1\r\n

It just differs from my last S/R, of my previous post, as it does not take, in account, the final NON-word character, at position 44, in the replacement part !

Therefore, starting, again, from this part of the license.txt file, below :

5. You are not required to accept this License, since you have not signed it. However, nothing else grants you permission to modify or distribute the Program or its derivative works. These actions are prohibited by law if you do not accept this License. Therefore, by modifying or distributing the Program (or any work based on the Program), you indicate your acceptance of this License to do so, and all its terms and conditions for copying, distributing or modifying the Program or works based on it.

It would give the same text, without the space character, at the end of all the lines generated :

5. You are not required to accept this
License, since you have not signed it.
However, nothing else grants you permission
to modify or distribute the Program or its
derivative works. These actions are
prohibited by law if you do not accept this
License. Therefore, by modifying or
distributing the Program (or any work based
on the Program), you indicate your
acceptance of this License to do so, and
all its terms and conditions for copying,
distributing or modifying the Program or
works based on it.

Cheers,

guy038

Alan Kilborn

@guy038

Yes, in playing around with your original regex, I didn’t worry about the resulting space at the end of the line, as I have my “save” shortcut mapped to “trim trailing spaces” + “save”. The ONLY way files should be saved (for me!).

Alan Kilborn

@guy038

And it is great that you have Admin rights here and can edit old posts, but I’m neutral on this. I think that old posts should not be edited and clarifying posts should just be added on. It is difficult to follow sometimes when history is CHANGED rather than simply CORRECTED/CLARIFIED later. :-D

guy038

Hi, Alan,

Yes, you’re right about it : I should have created a new post with the corrections, for a better history ! It’s just that my updated post was, still, quite long and I thought it would be more clear to, simply, change my initial post. But, I do understand your point of view !

Cheers,

guy038

hu ma

@Scott-Sumner
Thanks for the info!

guy038

Hello, @hu-ma and All

To complete the @scott-sumner post, about the two syntaxes of the searched groups, in replacement :

\N, with 0 < N < 10
$N, with 0 <= N < 2,147,483,648

There is the other practical syntax, below :

${N}, with 0 <= N < 2,147,483,648

Indeed, let’s imagine the original text:

abcd
1234
WXYZ

and the first S/R :

SEARCH ^.(..).

REPLACE $100|

You obtain the simple text :

|
|
|

Why ?! Just because, in replacement, the regex engine is looking for the group $100, which, obviously, does not exist ! So, the regex engine rewrites a zero-length string, for the non-existent group 100, followed by the literal character | !

Now, compare, with the second S/R, below :

SEARCH ^.(..).

REPLACE ${1}00|

This time, you, correctly, get the text, below :

bc00|
2300|
XY00|

=> All the changed lines begin by the second and third characters of the original lines of text ( $1 ), and are, simply, followed by the string 00|

Best Regards,

guy038

abuali huma

Sorry for pumping up old thread, but my issue is related to this one.

Cutting to the thread…
Look at Result#2 with desired arrangement

-Example# 2
Greetings My Liege! As your personal advisor [NEWLINE] , I am qualified to assist you in all[NEWLINE] matters related to ruling our civilization.[NEWLINE] I am at your service.

--------
+Seeked arrangement
I am at your service. [NEWLINE] matters related to ruling our civilization.[NEWLINE], I am qualified to assist you in all[NEWLINE]Greetings My Liege! As your personal advisor

I asked before for a way to rearrange the groups between [NEWLINE] to be backward… Now I’m asking for the same but in more automated way…

Because not all lines have the same amount of Groups, I want to arrange all the lines that contains Groups between [NEWLINE] to be backward arrangement.

-Example#3 Contains SIX groups
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six

-------
+Seeked arrangement
 six[NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE]One

While using the same regex or python script

-Example#4 Contains 4 groups 
I want [NEWLINE] this [NEWLINE] to be  [NEWLINE] last

------
+Seeked arrangement
 last[NEWLINE] to be [NEWLINE] this [NEWLINE]I want

guy038

Hi, @abuali-huma,

I found a general method, which uses three consecutive S/R. We’ll need two dummy characters, NOT used in the current file. I, personally, chose the # and @ characters, but any other may be used !

The first S/R :
- Changes any string [NEWLINE], possibly preceded and/or followed with a space character, by the dummy character #
- Adds, also, a # character at the end of any non-blank line
The second S/R is the main S/R, which rewrites the different parts, between the # character, in reverse order.
- Note that this S/R will have to be performed as many times, till the message Replace All: 0 occurrences were replaced occurs, in the Replace dialog
- The general idea, about this S/R, is to switch the beginning and ending parts of the found text, adding a @ character, at the end of the exchanged parts, in order that the next run of this S/R, will avoid these moved parts of text ! Hence, the decreasing number of occurrences found, till zero :-))
The Third S/R :
- Changes the # character, possibly preceded by a @ character, inside text, by the string [NEXLINE], preceded and followed with a space character
- Deletes the # character, possibly preceded by a @ character, when located at the end of the lines

All these S/R will use the Regular expression search mode, the Wrap around option and the Replace All button, of the Replace dialog

So, let’s start with the original text, below :

One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six [NEWLINE] seven [NEWLINE] eight [NEWLINE] nine [NEWLINE] ten [NEWLINE] eleven [NEWLINE] twelve
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six [NEWLINE] seven [NEWLINE] eight [NEWLINE] nine [NEWLINE] ten [NEWLINE] eleven
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six [NEWLINE] seven [NEWLINE] eight [NEWLINE] nine [NEWLINE] ten
Other text NOT concerned
by this Search Replacement
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six [NEWLINE] seven [NEWLINE] eight [NEWLINE] nine
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six [NEWLINE] seven [NEWLINE] eight
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six [NEWLINE] seven
Bla bla blah
Bla bla blah
Bla bla blah
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five [NEWLINE] six
One [NEWLINE] two [NEWLINE] three [NEWLINE] four [NEWLINE] five
One [NEWLINE] two [NEWLINE] three [NEWLINE] four
Dummy text
inserted, in between !
One [NEWLINE] two [NEWLINE] three
One [NEWLINE] two
One
I want [NEWLINE] this [NEWLINE] to be  [NEWLINE] last

After running the following S/R , once :

SEARCH (?-s)\x20?\[NEWLINE\]\x20?|(?<=.)$

REPLACE #

You should get the text, below :

One#two#three#four#five#six#seven#eight#nine#ten#eleven#twelve#
One#two#three#four#five#six#seven#eight#nine#ten#eleven#
One#two#three#four#five#six#seven#eight#nine#ten#
Other text NOT concerned#
by this Search Replacement#
One#two#three#four#five#six#seven#eight#nine#
One#two#three#four#five#six#seven#eight#
One#two#three#four#five#six#seven#
Bla bla blah#
Bla bla blah#
Bla bla blah#
One#two#three#four#five#six#
One#two#three#four#five#
One#two#three#four#
Dummy text#
inserted, in between !#
One#two#three#
One#two#
One#
I want#this#to be #last#

After running the following S/R, SEVEN times, one after another :

SEARCH (?-s)([^@#\r\n]+?)#(.+#)?([^@#\r\n]+)#

REPLACE \3@#\2\1@#

The modified text is, now :

twelve@#eleven@#ten@#nine@#eight@#seven@#six@#five@#four@#three@#two@#One@#
eleven@#ten@#nine@#eight@#seven@#six#five@#four@#three@#two@#One@#
ten@#nine@#eight@#seven@#six@#five@#four@#three@#two@#One@#
Other text NOT concerned#
by this Search Replacement#
nine@#eight@#seven@#six@#five#four@#three@#two@#One@#
eight@#seven@#six@#five@#four@#three@#two@#One@#
seven@#six@#five@#four#three@#two@#One@#
Bla bla blah#
Bla bla blah#
Bla bla blah#
six@#five@#four@#three@#two@#One@#
five@#four@#three#two@#One@#
four@#three@#two@#One@#
Dummy text#
inserted, in between !#
three@#two#One@#
two@#One@#
One#
last@#to be @#this@#I want@#

Seven consecutive runs of that regex S/R are required, to get the sought text :

Run 1 : 12 occurrences replaced
Run 2 : 10 occurrences replaced
Run 3 : 7 occurrences replaced
Run 4 : 5 occurrences replaced
Run 5 : 3 occurrences replaced
Run 6 : 1 occurrences replaced
Run 7 : 0 occurrences replaced

Note : After each run, you may hit the Find Next button, before hitting the Replace All button, to guess the general process !

The part [^@#\r\n], in the searched regex, represents any single character, different from @, #, \n and \r

Then, after running the last S/R, once :

SEARCH (?-s)(@?#)(?=.)|@?#

REPLACE ?1\x20[NEWLINE]\x20

We obtain our final text :

twelve [NEWLINE] eleven [NEWLINE] ten [NEWLINE] nine [NEWLINE] eight [NEWLINE] seven [NEWLINE] six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
eleven [NEWLINE] ten [NEWLINE] nine [NEWLINE] eight [NEWLINE] seven [NEWLINE] six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
ten [NEWLINE] nine [NEWLINE] eight [NEWLINE] seven [NEWLINE] six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
Other text NOT concerned
by this Search Replacement
nine [NEWLINE] eight [NEWLINE] seven [NEWLINE] six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
eight [NEWLINE] seven [NEWLINE] six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
seven [NEWLINE] six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
Bla bla blah
Bla bla blah
Bla bla blah
six [NEWLINE] five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
five [NEWLINE] four [NEWLINE] three [NEWLINE] two [NEWLINE] One
four [NEWLINE] three [NEWLINE] two [NEWLINE] One
Dummy text
inserted, in between !
three [NEWLINE] two [NEWLINE] One
two [NEWLINE] One
One
last [NEWLINE] to be  [NEWLINE] this [NEWLINE] I want

The search part looks for the regex @?#, either, inside the lines ( case group 1 defined ) or at end of lines ( case NO group 1 )

The replacement part means that, IF group 1 exists, the searched text is replaced by the string [NEWLINE], surrounded by space characters, ELSE NO replacement occurs

Et voilà !

Best Regards,

guy038

abuali huma

Thanks very much!
But just to be clear, in the first regex

SEARCH (?-s)\x20?[NEWLINE]\x20?|(?<=.)$

REPLACE #

Removing the value ** \x20 ** will result this
SEARCH (?-s)?[NEWLINE]?|(?<=.)$

Which will result capturing the space “if available” before and after [NEWLINE] string in first and last group?

abuali huma

I found out the removing the \x20 does what I described… Thanks again

abuali huma

I modified the original Search regex, as it catches some Unicode characters with will break the line in a middle of a word. So in the modified regex I replace \W with \x20 (space character)… so far no word breaking issues
Here is the modified one
(?-s).{1,44}(?=\x20)