Regex to change numbers to a value 1 step lower

Pablo Martinez

i have a regex that i use that changes numbers and increases the value, so if theres a 1 in my txt i turns it into 2, a 0 to 1 and so. Ive been trying to make a new regex that decreases value by 1, so it would turn a 4 into a 3, a 9 into an 8 and so on. But im stuck i cant figure it out, ill post the current regex i use and some examples
find
(0)|(1)|(2)|(3)|(4)|(5)|(6)|(7)|(8)|(9)

replace with
(?{1}1)(?{2}2)(?{3}3)(?{4}4)(?{5}5)(?{6}6)(?{7}7)(?{8}8)(?{9}9)(?{10}0)

Now im wondering if its possible to use this same formula but to decrease the numbers

examples

james66

fire1

dog 2

lier9

to

james55

fire0

dog1

lier8

guy038

Hello, @pablo-martinez,

I’ve just missed your post, till now ! Really easy, indeed !

The search regex is unchanged (0)|(1)|(2)|(3)|(4)|(5)|(6)|(7)|(8)|(9)

The replacement regex becomes (?{1}9)(?{2}0)(?{3}1)(?{4}2)(?{5}3)(?{6}4)(?{7}5)(?{8}6)(?{9}7)(?{10}8)

Remark : I noticed that, in your previous regex, when you add 1 to digit 9, you get the 0 digit ( part (?{10}0), at the end of your previous replacement regex ).

So, to stay coherent, with that method, now, if you subtract 1 from 0, you’ll get the number 9 ( part (?{1}9), at the beginning of the new replacement regex ! )

Best Regards,

guy038