REGEX - Select everything before a particular word included the line with Word ?

[guy038]

Hello Neculai I. Fantanaru,

Not very difficult !

So let’s suppose you have the following text :

Line 1
Line 2
Line 3
Line 4
This expression WORD is contained in this line 5
Line 6
Line 7
Line 8
WORD begins that line 9
Line 10
Line 11
Line 12

I think that there are four possible versions of your initial question :

• How to delete any text from the beginning of the current file till the FIRST line, included, containing the string “WORD” ( A )
• How to delete any text from the beginning of the current file till the LAST line, included, containing the string “WORD” ( B )
• How to delete any text from the cursor location of the current file till the FIRST line, included, containing the string “WORD” ( C )
• How to delete any text from the cursor location of the current file till the LAST line, included, containing the string “WORD” ( D )

Remark : For cases C / D, in order to delete all the line, where the cursor is located, just move it at the very beginning of the current line, before running the S/R operation

No worry :-) For each case, of course, there’s a suitable regex to perform ! So :

• Open the Replace dialog ( CTRL + F )

• Check the Match case option, if necessary

• Check, preferably, the Wrap around option

• Select, of course, the Regular expression search mode

• In the Find what zone, type in, according to the wanted case :

  • \A(?s).*?WORD(?-s).*\R for case ( A )

  • \A(?s).*WORD(?-s).*\R for case ( B )

  • (?s).*?WORD(?-s).*\R for case ( C )

  • (?s).*WORD(?-s).*\R for case ( D )

• Leave the Replace with zone EMPTY

• Click, once, on the Find Next button, then click on the Replace button

Et voilà !

Notes :

• The \A matches the zero-length position at the very beginning of the file

• The (?s) modifier means that further dot symbol(s) will match, absolutely, any character ( Standard or EOL characters )

• The (?-s) modifier means that further dot symbol(s) will match, ONLY the standard characters, ( usual form )

• Note that when the . matches newline option is checked, it means that an invisible (?s) is supposed, in front of the whole regex. However, the use of the two modifiers, (?s) and (?-s), inside the regex, allow us enhanced regexes

• The \R syntax represents any kind of EOL characters ( \r\n in Windows* files, \n in Unix/OSX files or \r in old MAC files

• Remember, for instance, that :

  • The regex 0.*9 matches the longest string, beginning with a 0 digit and ending with a 9 digit

  • The regex 0.*?9 matches the shortest string, beginning with a 0 digit and ending with a 9 digit. That’s why there is NO other digit 9 inside that string

Best Regards,

guy038

[Neculai I. Fantanaru]

hello. Thanks, works fine.

And I did find another 2 solutions, just as good as yours:

[[\s\S]*.*(WORD).*[\s\S]]

or

((?s)((^.*)WORD))(.*$)

[Neculai I. Fantanaru]

Hello guy038. Can u help me? What will be the regex code, if I want to delete everything before a particular word?

suppose ex:

word
word
bla bla word_to_delete
word
word

I want to delete the line with “word_to_delete” and everything after that line. How can I do that?

[guy038]

Hi, Neculai,

Again, two interpretations, of your question, are possible, because your file may contain several lines, with that specific “word_to_delete”

So, let’s use the example text, below, where the simple string “ABC” stands for your expression “word_to_delete”

Line 1
Line 2
Line 3
Line 4 with the "ABC" string
Line 5
Line 6
Line 7 containing ABC, too
Line 8
Line 9
Line 10 is the last line, with the string ABC
Line 11
Line 12
Line 13

Then :

• Go back to the beginning of your file ( CTRL + Origin )

• Open the Replace dialog ( CTRL + H )

• Select the Regular expression search mode

• If you want to delete from the beginning of Line 4 ( FIRST line containing the string ABC, after the cursor locatiion ), till the end of the file, use the following S/R :

SEARCH : (?-s)^.*ABC(?s).*

REPLACE : Leave EMPTY

• If you want to delete from the beginning of Line 10 ( LAST line containing the string ABC ), till the end of the file, use the following S/R :

SEARCH : (?s).*\R\K.*ABC.*

REPLACE : Leave EMPTY

Notes :

• The in-line modifiers, (?s) and (?-s) as well as the \R syntax, were explained in my previous post

• The \K syntaxforces the regex engine to consider that any matched regex, before the \K form, is forgotten and that the final regex to match is, ONLY, the regex, located after the \K form

IMPORTANT :

Due to the \K feature, included in the second S/R, you must use the Replace All button, exclusively. In that case, the step by step replacement, with the Replace button, does NOT work !!

Cheers

guy038

[Neculai I. Fantanaru]

hi, works great.
And please , guy38, one single question. If I want to delete a particular fragment from a text file:

I want to delete everything before line 4 that contains the word “UNTIL THIS” (included line 4) , and in the same time to delete everything after line 10 that contain the word “AFTER THIS” (included the line 10)

Line 1
Line 2
Line 3
Line 4 UNTIL THIS
Line 5 -----
Line 6 -----
Line 7 -----
Line 8 -----
Line 9 -----
Line 10 AFTER THIS
Line 11
Line 12
Line 13

[guy038]

Hello Neculai,

As we need to grab several lines at the same time, we’ll use, again, the (?s) modifier, in order to allow the dot symbol to match, absolutely, any character. In addition, I just add the (?-i) modifier which ensures that the search will be performed in a non-insensitive way, that is identical to say, in a sensitive way to case !

The search regex is, simply, an alternative to two regexes, successively used ( one regex searching, firstly, for lines 1 to 4, included and the other one searching, secondly, for lines 10 to 13, included. So :

We start with the example text below :

Line 1
Line 2
Line 3
Line 4 UNTIL THIS end
Line 5 -----
Line 6 -----
Line 7 -----
Line 8 -----
Line 9 -----
Line 10 AFTER THIS end
Line 11
Line 12
Line 13

• Go back to the beginning of your file ( CTRL + Origin )

• Open the Replace dialog ( CTRL + H )

• Select the Regular expression search mode

• Preferably, uncheck the Wrap around option

SEARCH : (?s-i).*UNTIL THIS.*?\R|.*\R\K.*AFTER THIS.*

REPLACE : Leave EMPTY

• Click, one time, on the Replace All button

You should obtain the wanted result, below :

Line 5 -----
Line 6 -----
Line 7 -----
Line 8 -----
Line 9 -----

These two regexes are rather similar to those, described in my previous posts and don’t need any further explanation !

Best Regards,

guy038

BTW, concerning my previous post, I noticed a funny behaviour :

• Copy the text, below, in a new file :

  Line 1
  Line 2
  Line 3
  Line 4 with the “ABC” string
  Line 5
  Line 6
  Line 7 containing ABC, too
  Line 8
  Line 9
  Line 10 is the last line, with the string ABC
  Line 11
  Line 12
  Line 13

• Go back to the beginning of your file ( CTRL + Origin )

• Open the Replace dialog ( CTRL + H )

• Select the Regular expression search mode

• Check the Wrap around option

• Copy, in the Find what zone, the regex (?s-i).*\R\K.*ABC.*

• Click, a first time, on the Replace button ( NOT the Replace All button ! ) => The lines 10 to 13 included are selected

• Click, a second time, on the Replace button => The lines 10 to 13 included are deleted and, simultaneously, the lines 7 to 9 included are selected

• Click a third time, on the Replace button => The lines 7 to 9 included are deleted** and, simultaneously, the lines 4 to 6 included are selected

• Finally, a fourth click, on the Replace button, deletes the lines 4 to 6 included

Thus, contrary to what I had thought, up to now, although a \K form is used in the search regex, a mouse click on the Replace button ( step by step replacement ) still produces, in some cases, an action on the selected text !!

[Scott Sumner]

@guy038 , I trust you will not be satisfied until you dig deeper to characterize more fully this contrary \K behavior you have discovered.

I think you might find that having the “Wrap around” option enabled is key to the Replace button doing what it does here.

[Neculai I. Fantanaru]

hi, guy038. Works just fine !!

thank you very much !

[Ashton Watts]

Hi @guy038 ,

I’m hoping you can help as the bits above were really helpful but I still have a bit to do.

I want to delete everything between two points in 47000 html files.

I can insert the points using a simple find an replace so i would be left with;

Want to keep
Want to keep
Want to keep
START-DELETING
delete
delete
delete
delete
delete
STOP-DELETING
Want to keep
Want to keep
Want to keep
Want to keep
Want to keep

Hoping you have the answer.

regards,

[guy038]

Hello, ashton-watts, and All,

I suppose that all your .html files are in a specific directory. So :

• First, I strongly advice you to backup the directory containing all your .html files !

• Start Notepad++

• Now, open the Replace in Files dialog ( Ctrl + Shift + F )

• Type, in the Find what: zone, the regex (?s-i).*\R\KSTART-DELETING.*STOP-DELETING\R

• Leave the Replace with: zone EMPTY

• Insert *.html in the Filters: zone

• Fill the Directory : zone with the absolute path of your specific folder

• Finally, click on the Replace in Files button

• Click on the Yes button, to confirm replacement

Et voilà :-))

So from the initial text, below :

Want to keep
Want to keep
Want to keep
START-DELETING
delete
delete
delete
delete
delete
STOP-DELETING
Want to keep
Want to keep
Want to keep
Want to keep
Want to keep

you’ll get :

Want to keep
Want to keep
Want to keep
Want to keep
Want to keep
Want to keep
Want to keep
Want to keep

Important :

It could be useless to insert marks, in order to determine the starting and ending boundary of the range of lines to be deleted. Two possibilities :

• The boundaries are easy to isolate, among text around and are unique. In that case, it could replace the generic START-DELETING and STOP-DELETING lines

• The boundaries may be literally different but follow a same template. In that case, they can be found with a regex, which would be mixed with my regex above !

So, if it’s not confidential information and if you don’t mind, give us an example of the START-DELETING and STOP-DELETING lines of your .html files ! You could also join one of your files, or part of it, as an attached file, with your mail at my e-mail address :

Thanks, for this additional information !

See you later,

Best Regards

guy038

[Ashton Watts]

@guy038 Hi goy038,

You are a legend. the regex search string above worked perfectly. I had already inserted the start and stop points so it wasn’t an issue.

Thanks very much for your help.

regards,

[blackburn1489]

@guy038 Hello! Can u help me, please?

I need to get WORD between another word and part of the WORD word
example

title = WORD_name

After I get WORD, I need to find all WORD in the document

and rename them in WORD_lttz
//
After that I need to repeat all operations. but with another WORD1, WORD2, WORD3 and so on
that placed between “title =” and “_name”

title = WORD1_name

find them in entire document and rename them in WORD1_lttz , WORD2_lttz , WORD3_lttz and so on

[guy038]

Hello, @blackburn1489, and All,

I took some time to figure out what you exactly wanted to do and I hope that my solution will be close enough to what you need !

OK, let’s suppose that we start with the sample text below :

title = ABC_name
title = DEF_name
title = YZ_name
title = GHI_name
title = JKL_name
title = MNO_name
title = YZ_name
title = ABC_name
title = MNO_name
title = MNO_name
title = PQR_name
title = MNO_name
title = STU_name
title = VWX_name
title = ABC_name
title = YZ_name
title = GHI_name

Note that it contains 3 lines with the string ABC, 2 lines with the string GHI, 4 lines with the string MNO and 3 lines with the string YZ !

Now, let’s imagine that you would change each string ABC, DEF… into new strings, according to the table below :

ABC    ->    ABC111
DEF    ->    DEF-22222
GHI    ->    GHI_GHI
JKL    ->    J
MNO    ->    mno
PQR    ->    000PQR
STU    ->    Test
VWX    ->    99
YZ     ->    Y-Z

Then, using the following regex S/R :

SEARCH (?-i)title\x20=\x20(?:(ABC)|(DEF)|(GHI)|(JKL)|(MNO)|(PQR)|(STU)|(VWX)|(YZ))(?=_name)

REPLACE title = (?1\1111)(?2\2-22222)(?3\3_\3)(?4J)(?5\L\5)(?{6}000\6)(?7Test)(?{8}99)(?9Y-Z)_lttz

would, simultaneously, change any occurrence of these 9 strings, into the new ones, defined in the table above ;-))

So, after clicking on the Replace All button, you would get, at once, the following text :

title = ABC111_lttz_name
title = DEF-22222_lttz_name
title = Y-Z_lttz_name
title = GHI_GHI_lttz_name
title = J_lttz_name
title = mno_lttz_name
title = Y-Z_lttz_name
title = ABC111_lttz_name
title = mno_lttz_name
title = mno_lttz_name
title = 000PQR_lttz_name
title = mno_lttz_name
title = Test_lttz_name
title = 99_lttz_name
title = ABC111_lttz_name
title = Y-Z_lttz_name
title = GHI_GHI_lttz_name

Et voilà !

Notes :

• Regarding the search regex :

  • First, the (?-i) syntax forces the search to be processed, in a sensitive way ( NON-insensitive )

  • Now, the part title\x20=\x20 tries to match the string title =, with a space character, before and after the equal sign

  • Then, the (?: syntax starts a non-capturing group

  • The part (ABC)|(DEF)|(GHI)|(JKL)|(MNO)|(PQR)|(STU)|(VWX)|(YZ) are, simply, 9 alternatives, corresponding to our 9 strings to be changed. Thus, each of them, between parentheses, is stored as group 1, 2, 3…

  • The final part )(?=_name) corresponds to the closing parenthesis of the non-capturing group, followed with a look-ahead structure or condition ( Is there the string _name afterABC, DEF… ? ) which must be true for an overall match

• Regarding the replacement regex :

  • First, it rewrites the string title = , followed with a space character

  • Then any (?#....) syntax, where # represents a digit, is a conditional replacement and all the regex after the #, till the closing parenthesis, is evaluated, if the matched string is stored in group #

  • Note that the 9 conditional replacement structures (?1\1111)(?2\2-22222)(?3\3_\3)(?4J)(?5\L\5)(?{6}000\6)(?7Test)(?{8}99)(?9Y-Z) could be placed in any order

  • In some of them, we rewrite the searched string, stored in group # , due to the \# escape sequence

  • In the conditional replacement (?5\L\5) we, simply, rewrite the upper-case string MNO, in lower-case, because of the \L replacement escape sequence

  • Be aware, too, that concerning the groups 6 and 8, their conditional replacements are build with the alternate form (?{#}....). Indeed, we must distinguish between the group number # and the digits, which follows it !. If the braces would have been absent, the regex engine would think that groups 6000 and 899 were concerned :-((

  • And finally, of course, it rewrites, in all cases, your ending part, the string _lttz !

Best Regards,

guy038

[And Boja]

Hi,

I have some E-mails

100km@laufwunder.at
100km@tus-ahrweiler.de
100kmbelves@free.fr
12ahewitt@royalschoolcavan.ie
12lfuller@royalschoolcavan.ie
12oakinlabi@royalschoolcavan.ie
12vkells@royalschoolcavan.ie
13@123.com
13362880852@zj165.com
1573364@mail.ru
1matoo@zoznam.sk
2008.lizhigang@163.com

I Want to delete all words till the @ sorry for my english i have 1 milion e-mails so i want to remove all words till the domain start example:

i want to split them into this:

@laufwunder.at
@tus-ahrweiler.de
@free.fr
@royalschoolcavan.ie
@royalschoolcavan.ie
@royalschoolcavan.ie
@royalschoolcavan.ie
@123.com
@zj165.com
@mail.ru
@zoznam.sk
@163.com

Hope someone understand me what i am trying to say :S

[Claudia Frank]

@And-Boja

if your real data looks like your posted data then something like

find what:^.*?(?=@)

will do the job. Replace with is empty.
See FAQ for more info on regex.

Cheers
Claudia

[Md Abdullah Al Noman]

I want to delete everything between two points with 36000 line xml files.
which portion is repeated in files.
I can insert the points using a simple find an replace so i would be left with…
<Middle></Middle>
<WebsiteList></WebsiteList>
<EventList></EventList>
<Note></Note>
<LastName></LastName>
START-DELETING… <Photo>data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAANsAAADbCAIAAABr4XMXAAAAA3NCSVQICAjb4U/gAAAKBklEQVR4
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WlAk0IIigRYUCbSgSKAFRQItKBJoQZFAC4oEWlAk0IIigRYUCbSgSKAFRQItKBJoQZFAC4oEWlAk
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+IjmkgAAAABJRU5ErkJggg==
</Photo>
END-DELETING
<GroupList></GroupList>
<Job></Job>

Hoping you have the answer.

[Terry R]

Given the example you provided the following would remove all text between and including the START and END-DELETING lines.
Find: (START-DELETING.+\R)(.+\R)+(END-DELETING\R)
Replace: empty string here

So the assumption is that there must be at least 1 line between the 2 identifying lines (START and END), that’s the (.+\R)+ portion of the regex. Also note that the first group (START-DELETING.+\R) includes the .+ as your example also has 3 period characters after it. I’ve included brackets around each sub-portion just so as it makes it a bit easier to segment out and identify what each group is doing. Only the middle group brackets are absolutely necessary, i.e.(.+\R)+.

You say you can/have replaced using a simple find and replace to get the START and END lines in there. With my regex you could replace those portions with the original string you used to find. That would save you 1 or 2 additional steps.

Hope this helps.

Terry

[guy038]

Hello, @md-abdullah-al-noman, @terry-r and All,

I think, that the following regex S/R, could be used, too :

SEARCH (?s-i)^\h*START-DELETING.+?END-DELETING\R

REPLACE Leave EMPTY

Notes :

• First, the (?s-i) modifiers, means that, from now on :

  • Any regex dot symbol ( .) will match, absolutely, any single character ( standard ones and EOL ones )

  • The search will be processed in a sensitive way ( Non-insensitive ! )

• Then, the part ^\h*START-DELETING looks, from beginning of line ( ^ ), for the upper-case string START-DELETING, possibly preceded with some horizontal space characters ( Usual space or tabulation )

• At end, the part END-DELETING\R searches for the upper-case string END-DELETING, followed with its line-break character(s)

• And the middle part .+? represents the shortest range, of any character, between the two strings START-DELETING and END-DELETING

• Finally, as the replacement regex is empty, all the overall match is, simply, deleted

Best regards,

guy038

[David Bennett]

@guy038 you truly are a legend, I agree with the other poster. You are so deep into notepad++ regex, impressive!
I believe you may also know this - IMHO quite common - case, although I can’t find it described anywhere:

Suppose you have just one large file (wordpress sql database in fact, opened in my favorite editor notepad++) and STRING A and STRING B should always belong together:
FIND ALL INSTANCES OF ANY TEXT across lines
WHERE STRING A sometime later
IS FOLLOWED BY ANOTHER STRING A
INSTEAD OF THE “CLOSING” STRING B

Example: Find all instances where, across lines, there’s the literal string [/social]
and after any kind and number of characters there’s another literal string [/social]
BUT in between the two is nowhere a literal string [social] although it should be because [social] and [/social] belong together.

So basically in the example case, string A and string B always belong together, there must never follow two A’s or two B’s. Always the A string, then the B string. Then again the A string, then the B string. Etc. And so you need to find any “fault”: where A is followed sometime later by another A, instead of first a B string.

Did I explain this well enough?

I am sure none of the above, nor anything else I have found, works because I’ve tried them all. Would you have an idea how to go about this?

[guy038]

Hello @david-bennett, and All,

Thanks, David You explained your problem very well. So you’re looking for ranges [social].......[/social], where, unfortunately, one boundary;, either [social] or [/social] is missing, aren’t you ?

As a sample, in the text, below, I indicated where the boundary is missing :

...[social].......[/social]..............[/social]........[social]............[social]..........[/social]...
                                 ^                                     ^
                          [social] missing			            [/social] missing

BTW, I, also, assume that your database does NOT contain nested blocks [social].......[/social] as, for instance :

[social]....[social].....[social].....[social].....[/social]....[/social].....[/social]......[social].....[/social]....[/social]...

---

In that case, a possible regex could be :

SEARCH (?-s)(?<=\[/social\])((?!\[social\]).)+?(?=\[/social\])|(?<=\[social\])((?!\[/social\]).)+?(?=\[social\])

If you apply this regex against the text, below, it select all the zones where a boundary is missing !

...[social].......[/social]..............[/social]........[social]............[social]..........[/social]...
                          >              <                       >            <

Note that :

• If the selection is surrounded with two boundaries [social], then, this selection should contain a [/social] ending boundary

• If the selection is surrounded with two boundaries [/social], then, this selection should contain a [social] starting boundary

---

If your text may be split on several lines, use, preferably, this regex, almost identical, which is, also, correct for ONE-line blocks [social].......[/social] !

SEARCH (?s)(?<=\[/social\])((?!\[social\]).)+?(?=\[/social\])|(?<=\[social\])((?!\[/social\]).)+?(?=\[social\])

...[social].......[/social]....
                          >
.....
.....[/social].....
     <
.......
...[social].......[/social]..............[/social]........[social]............[social]..........[/social]...
                          >              <                       >            <
......
...[social]...
          >
....
.....[social]...
     <
.......[/social]...

Notes :

• The square brackets need to be escaped with the \ character, as they have a special meaning, in regular expressions

• At the beginning, the (?-s) or (?s) modifier determines if the dot meta-character ( . ) represents a single standard character only, or any character

• Then the regex engine tries to match one of the two alternatives :

  • (?<=\[/social\])((?!\[social\]).)+?(?=\[/social\])

  • (?<=\[social\])((?!\[/social\]).)+?(?=\[social\])

• The first alternative matches the smallest range of characters ( (....)+? ), surrounded by two strings [/social], due to the look-behind (?<=\[/social\]) and the look-ahead (?=\[/social\])

• The second alternative matches the smallest range of characters ( (....)+? ), surrounded by two strings [social], due to the look-behind (?<=\[social\]) and the look-ahead (?=\[social\])

• In the first alternative, this range must not contain, at any position, the string [social], due to the negative look-ahead, in the construction (?!\[social\]).

• In the second alternative, this range must not contain, at any position, the string [/social], due to the negative look-ahead, in the construction (?!\[/social\]).

Best Regards,

guy038