Help converting Notepad++ format to Pythonscript

Andrew Clark

@Andrew-Clark

Not sure if you are directing that response to @Claudia-Frank or to me…but I’ll say this about the regex approach: I never understood how your regex worked live with Notepad++ – maybe the markdown syntax on this site was “stealing” some parts of it.

If I try it as I see it above I get this as the AFTER text, which is clearly not right:
OO11223344
((EEXXAAMMPPLLEE  PPRROOGGRRAAMM))
((TTHHIISS  IISS  AA  CCNNCC  CCOOMMMMEENNTT))
((II  WWAANNTT  TTHHEESSEE  LLIINNEESS  TTOO  RREETTAAIINN  SSPPAACCEESS))
(())
GG2288  GG9911  ZZ00
TT11  MM66  ((EEXXAAMMPPLLEE  TTOOOOLL))
MM33  SS1100000000
GG9900  GG00  GG9955  GG5544  XX11..00  YY22..00
GG4433  ZZ00..2255  HH11  DD11  MM88
GG11  ZZ--11..00  FF00..000066
XX--11..00  YY--22..00
YY22..00
XX11..00
GG00  ZZ11..00  MM55
GG2288  GG9911  ZZ00  MM99
MM0011  ((CCHHEECCKK  PPAARRTT))
What gives? Shouldn’t I see some \( and \) sequences in the regex?

My response was directed at Claudia. And you’re right, the code I posted above does not result in the proper result in Notepad++. Something must have been lost. I could go back and find it, but at this point my question has been answered so I am going to call this topic closed. Thank you all for the responses!

Claudia Frank

@Andrew-Clark

sorry, didn’t understand that you want a python script solution with regular expression replacement.

regex = r'(\(.*?\))|(\w+)\s'  
editor.rereplace(regex, lambda m: '{}{}'.format(*m.groups()))

Cheers
Claudia

Scott Sumner

I am most-curious about why the OP (@Andrew-Clark) could get his regex replacement working in interactive N++ and not with Pythonscript, but perhaps that is a question that isn’t going to get answered…my guess would be not using raw string notation (the leading r in r'regex') in the PS…

Claudia Frank

or maybe it was about how to get the match groups returned as replacement … ??

Cheers
Claudia

guy038

Hello @andrew-clark, @scott-sumner, @claudia-frank and All,

I was away this weekend, to hike in the Cevennes mountains and my feet still remember theses rides ! As you can imagine, just sitting, comfortably, in front of your laptop and discussing Notepad++ matters is a real treat ;-))

So, Andrew, as for me, I would use, with native N++, the regex S/R, below :

SEARCH (?-s)(\(.+?\))|\x20

REPLACE ?1\1

Notes :

As usual , the (?-s) modifier means that any regex dot character ( . ) will match a single standard char., only.
Then, this regex would match :
- First, any shortest range of chars, between parentheses, stores it as group1 and rewrites this group as it is. ( Note that the ( and ) characters have to be escaped, with a \ symbol, to be considered as literals ! )
- Secondly, any space character, just ignored in replacement.

Cheers,

guy038

Claudia Frank

@guy038

Hi Guy, nice shortening but one question - it seems that ?1 is, for the posted example data, not needed in the replacement - what is the idea behind it?

Thank you and cheers
Claudia

Claudia Frank

Just in case someone wants to add this into a python script it would now look like this

regex = r'(?-s)(\(.+?\))|\x20'  
editor.rereplace(regex, lambda m: '{}'.format(m.groups()[0]))

Cheers
Claudia

Scott Sumner

@Claudia-Frank said:

or maybe it was about how to get the match groups returned as replacement … ??

I don’t know…the Pythonscript docs for editor.rereplace() seem to have an adequate example of this…but considering it now maybe it could be made better?

Claudia Frank

@Scott-Sumner

there is always room to improve something - so, yeah - go for it. :-D

Cheers
Claudia

guy038

Hi, @andrew-clark, @scott-sumner, @claudia-frank and All

Sorry, for my late answer as I was elaborating a regex, for the tricky case, below :

https://notepad-plus-plus.org/community/topic/16053/how-to-ascend-numbers/3

Ah, how silly am I ! Of course, when the regex finds a space character ( the second alternative ), the group1 is not defined. Thus, in replacement, it simply rewrites…nothing, as group1 represents a zero-length string ;-))

Clever deduction, Claudia. So a possible regex is :

SEARCH (?s)(\(.+?\))|\x20

REPLACE \1

Note : I also changed the (?-s) modifier into (?s), which allows possible multi-lines ranges of text, between parentheses !

Best Regards,

guy038

guy038

Hi, @andrew-clark, @scott-sumner, @claudia-frank and All

Ah :-(( I should have tested my idea of changing (?-s) into (?s), before posting. Actually, in case of multi-lines range of characters, between parentheses, the suitable regex S/R is , rather :

SEARCH (\([^()]+?\))|\x20

REPLACE \1

Hope it’s the right one, this time :-D

Cheers

guy038