Find and Replace with Regular Expressions (Regex): Software error or inadequate user? :-)

Danilo Schembri

Hi,

I have this text:
FIELD ONE
FIELD TWO
FIELD THREE

I want to replace “spaces” with “underscores”, but only when the “space” is only one and between words.

I use this Regex:
Find: ([A-Z]) ([A-Z])
Replace: \1_\2

If I use buttons with the sequence
Find, Repl&FAgain (1), Repl&FAgain (1), Repl&FAgain (1)
I obtain a strange substitution
FIELD_ONE
FIEL_WO
FIEL_HREE

Instead of
FIELD_ONE
FIELD_TWO
FIELD_THREE

It works with button sequence
Find, Replace Rest
or
Find, Repl&FAgain (3)

Is it a bug or I misunderstood anything?

Danilo

guy038

Hello, @Danilo Schembri and All,

Ah, you spoke of the TextFX plugin behavior ! Seemingly, when doing a step by step replacement, it does not update the values of group 1 and group 2, leaving them empty :-((

But, why don’t you perform the native N++ replacement, instead ?

Open the Replace dialog ( CTRL + H )
SEARCH ([A-Z])\x20([A-Z])
REPLACE \1_\2
Select the Regular expression` search mode
Tick , if necessary, the Wrap around option
Click, once, on the Replace All OR several times on the Replace button

You may use a simple space character, instead of the \x20 syntax

Best Regards

guy038

Meta Chuh

@Danilo-Schembri

your regex works for me

Find: ([A-Z]) ([A-Z])
Replace: \1_\2
`Search Mode: Regular Expression

gives me

FIELD_ONE
FIELD_TWO
FIELD_THREE

if i press replace all (or repeatedly press replace)

@guy038
i think you ment:
REPLACE \1\x5F\2 instead of REPLACE \1\x20\2