How to Replace a Matching Parenthetical up to the First Closing Parenthesis
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(Foo,1234567890) (bar)
where the numerical string after Foo, can be any set of numbers, and where this sequence is repeated an indefinite quantity of times in a long list with or without including (bar) on each line.
Task: You must replace (Foo,1234567890) without replacing any instance of (bar).
The regular expressions on http://docs.notepad-plus-plus.org/index.php/Regular_Expressions are not functioning, or else poorly explained in human language.
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Your request is kinda vague, at least to me, but let’s get the ball rolling:
Find:
\(\w+,\d+\)<----note the trailing space
Search mode: (obviously) Reg expProbably not what you want, but to me it works the way I understand the “spec” that has been presented.
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I’m unable to edit the topic post for undisclosed reasons. The set of numbers after (Foo, can be in hexadecimal. I can’t possibly imagine what else you thought was “vague”.
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Posts are only editable for 3 minutes.
With the new spec, I would try:
Find:
(?i)\(\w+,[0-9A-F]+\) -
Thank you very much for your assistance. This issue is now resolved.
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@zetawilk, @alan-kilborn and All,
@zetawilk, in your initial post, you said :
Task: You must replace (Foo,1234567890) without replacing any instance of (bar)
You’re not asking, here, for any commercial demand. Personally, I would have written, preferably :
Request : replace (Foo,1234567890) without replacing any instance of (bar)
and thanked, in advance, possible repliers, for their [free] help !
Just remember it, in your next posts ;-))
Best regards,
guy038
P.S. :
I just forgot your last post. So, let me temper my criticism because you did thank Alan for his answers !
