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    Perl language syntax highlighting troubles (bug or limitation ?)

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    • EkopalypseE
      Ekopalypse
      last edited by Ekopalypse

      (?s) is a modifier telling the engine that the dot matches line endings
      and yes, the engine uses \1 and $1

      Here the link to the documentation - maybe easier for you.

      1 Reply Last reply Reply Quote 0
      • EkopalypseE
        Ekopalypse
        last edited by

        ooppps

        (?s)((<<)\h+(["|'])(\w+?)\3\h*;.*?\3)

        :-D

        Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
        • Gilles MaisonneuveG
          Gilles Maisonneuve @Ekopalypse
          last edited by

          This post is deleted!
          1 Reply Last reply Reply Quote 0
          • Gilles MaisonneuveG
            Gilles Maisonneuve @Ekopalypse
            last edited by

            @Ekopalypse

            Ok
            another one: in Python you must say ["|'] instead of Perl ["'] (‘either one of the set’) ? Is that what it means ?

            EkopalypseE 1 Reply Last reply Reply Quote 0
            • EkopalypseE
              Ekopalypse
              last edited by

              No, afaik non-capturing group is (?:pattern)
              This, (?s), just tells the engine that the dot . is matching
              EOLs like \r\n - if I’m right.

              1 Reply Last reply Reply Quote 1
              • EkopalypseE
                Ekopalypse
                last edited by Ekopalypse

                Just for clarification, the python script does NOT use the python regex engine instead
                it uses the one notepad++ offers, the boost::regex.
                Yes, you can use the enumeration without the pipe but makes it more visible for me with
                the pipe sign. Or is there a difference if used with pipe sign or without?

                1 Reply Last reply Reply Quote 1
                • EkopalypseE
                  Ekopalypse
                  last edited by Ekopalypse

                  or maybe this one might be even better
                  (?s)(<<)\h+(["'])(\w+?)\2\h*;.*?\3

                  1 Reply Last reply Reply Quote 1
                  • Gilles MaisonneuveG
                    Gilles Maisonneuve
                    last edited by

                    Can’t reply what I wanted, a robot says I’m spamming…

                    Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
                    • EkopalypseE
                      Ekopalypse @Gilles Maisonneuve
                      last edited by

                      @Gilles-Maisonneuve

                      Can’t reply what I wanted, a robot says I’m spamming…

                      I have no idea why this happens sometimes.

                      By the way, now that you have installed pythonscript plugin would you mind
                      clicking Plugins->Python Script->Scripts->Samples->RegexTester ?

                      I know not everyone is recommending it but, personally, I love it.

                      1 Reply Last reply Reply Quote 1
                      • Gilles MaisonneuveG
                        Gilles Maisonneuve @Gilles Maisonneuve
                        last edited by

                        AFAIK, at least in Perl, ["|'] means double-quote OR pipre OR simple-quote, everything between square brakets is literal. Also true in “awk” and C regexp I think.
                        I don’t know for Python.

                        Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                        • Gilles MaisonneuveG
                          Gilles Maisonneuve @Gilles Maisonneuve
                          last edited by

                          @Ekopalypse

                          Now, if I say in Pyhton (attempt to transliterate from Perl) :

                          (r'(?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)', [2])
                          

                          does it mean :

                          1. form REGEXP
                          2. do not match NL with DOT
                          3. matches any horizontal blanks (0 or more), don’t make a group
                          4. matches ‘<<’ make it a group
                          5. matches any horizontal blanks (0 or more), don’t make a group
                          6. matches 0 or 1 text quote (either double or single), no group
                          7. matches a group of any chars not " nor ’ one or more time(s) (in perl it would be [^"'])
                          8. matches 0 or 1 text quote (either double or single), no group
                          9. possible blanks until semi-colon, semi-colon, then possible chars until NL

                          BUT THEN, what does mean ?\3. I’m lost there.

                          Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
                          • Gilles MaisonneuveG
                            Gilles Maisonneuve @Gilles Maisonneuve
                            last edited by

                            a slash m

                            EkopalypseE 1 Reply Last reply Reply Quote 0
                            • EkopalypseE
                              Ekopalypse
                              last edited by Ekopalypse

                              the r at the beginning just informs python that this is a raw string and
                              every char must be taken literally otherwise backslashes would be treated
                              as escapes under some circumstances.

                              The regex string is only this part

                              (?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)
                              

                              and I would say, but as said - not an regex expert at all,

                              (?s) means Dot matches newline characters
                              the first matching group is

                              (\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)
                              

                              the second

                              (<<)
                              

                              and the third must be

                              ([^"|^']+?)
                              

                              if I’m right.

                              \3 should be the same as $3 in perl

                              Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                              • Gilles MaisonneuveG
                                Gilles Maisonneuve @Ekopalypse
                                last edited by Gilles Maisonneuve

                                @Ekopalypse

                                still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’

                                and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks surrounded by parenthèses only.

                                EkopalypseE 1 Reply Last reply Reply Quote 0
                                • EkopalypseE
                                  Ekopalypse @Gilles Maisonneuve
                                  last edited by

                                  @Gilles-Maisonneuve

                                  maybe this picture makes it a little bit clearer

                                  1 Reply Last reply Reply Quote 2
                                  • EkopalypseE
                                    Ekopalypse @Gilles Maisonneuve
                                    last edited by Ekopalypse

                                    @Gilles-Maisonneuve

                                    still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’

                                    as less as possible - non-greedy

                                    and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in >subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks >surrounded by parenthèses only.

                                    placeholder for what was found in match group 3, to find the EOT at the end

                                    and there are 3 match groups or am I missing something??

                                    Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                                    • Gilles MaisonneuveG
                                      Gilles Maisonneuve @Ekopalypse
                                      last edited by

                                      @Ekopalypse

                                      2 sets of parenteses only, where is the third set ?
                                      so only 2 match groups

                                      can you make this work :

                                      no syntax error on the python console but absolutely no result, where is my bug ?

                                      regexes[(3, (255,255,255))] = (r'(?s)(\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)', [1])
                                      
                                      EkopalypseE 1 Reply Last reply Reply Quote 0
                                      • EkopalypseE
                                        Ekopalypse @Gilles Maisonneuve
                                        last edited by Ekopalypse

                                        @Gilles-Maisonneuve

                                        [1] informs the python script, that only the results from sub match group 1 should be colored in white (255,255,255)
                                        sub match group 1 is the result of (<<)

                                        In order to make it painting all you can use [0]

                                        I’m still confused about the 2 to 3 match groups.
                                        Am I incorrect when saying that
                                        (\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)
                                        (<<)
                                        ("{0,1}.+"{0,1})
                                        are three match groups?

                                        Maybe the confusion comes from the fact that references matches within a
                                        regular expression starts by 1 but python starts counting match results by 0.

                                        Sorry, but I have to stay up early tomorrow and it is already 1am but I’m really
                                        interested in solving our (mis)understanding today later (maybe in ~16-18hours)?

                                        1 Reply Last reply Reply Quote 1
                                        • Gilles MaisonneuveG
                                          Gilles Maisonneuve
                                          last edited by

                                          ok, tomorrow is another day
                                          ‘see’ you tomorrow.
                                          have a good night.
                                          g

                                          1 Reply Last reply Reply Quote 1
                                          • EkopalypseE
                                            Ekopalypse
                                            last edited by

                                            you too - see you

                                            Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
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