I need to delete two characters in two continuous lines
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Well, if all your data is really that simple, this seems to match it:
FInd
,\R0\R(?=\])
Search mode: Regular expressionYou can replace it with “nothing”.
I’d be careful using it, though. There might be more to the story that you haven’t told us.
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Thanks Alan, I’ve tried that expression but it says that cannot find the text.
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I copied the original text you gave out of the forum and into Notepad++. Then I used the Find expression I provided. It matched for me.
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Just tried it the same as Alan, it worked for me and reported that two occurrences were found/deleted.
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your original text is:
[ -90.67575919025678, 14.12140539076991, 0 ], [ -90.67691295444409, 14.11436171657998, 0 ], ... The thing is that I need to delete the last two characters in the square brackets the "," and the "0", so it must seem like: [ -90.67575919025678, 14.12140539076991 ], [ -90.67691295444409, 14.11436171657998 ],you have to embed it between two lines of
```(tripple backticks) otherwise your code gets stripped.best regards.
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Hi… Thanks… I’ve tried that in a new document and worked either. But in the original files the strings starts after three tab spaces… how can I add them into the search expression to match the string? is there any tab char I can add or how to add the 15 blank spaces between?
[ -90.89344601114183, 14.26720713414475, 0 ], [ -90.89410910416692, 14.2672050050027, 0 ], [ -90.89397902924168, 14.26244600987243, 0 ] -
I believe you should be able to update your find to:
,\R\h*0\R(?=\h*\]). The\h*adds a match of 0 or more horizontal spaces (space or tab).Actually, given your original spec, saying the closing
]should be on a separate line, I would actually say,\R\h*0(?=\R\h*\])
(which moves the newline after the 0 to not be deleted)
For me, this converts
[ -90.89344601114183, 14.26720713414475, 0 ], [ -90.89410910416692, 14.2672050050027, 0 ], [ -90.89397902924168, 14.26244600987243, 0 ]to
[ -90.89344601114183, 14.26720713414475 ], [ -90.89410910416692, 14.2672050050027 ], [ -90.89397902924168, 14.26244600987243 ] -
Hello @billy-martin, @peterjones and All,
Ah ! Nice, Peter, I was about to post a solution, but you beat me to it ;-))
And, of course, our solutions are identical
SEARCH
,\R\h*0(?=\R\h*\],)REPLACE
Leave EMPTYSo, I just give some explanations to Billy, on this regex S/R :
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The
\Rsyntax represents any form of line-break (\r\nfor Windows files,\nfor Unix files and\rfor Mac files ) -
The
\h*part matches any range, even null, of horizontal blank characters, i.e. space, tabulation and no-breaking space character, of respective Unicode values\x{0020},\x{0009}and\x{00A0) -
The character
[, being a regex meta-character, must be escaped with the\character, to be interpreted as a literal -
So, the search regex looks for a comma, followed with a line-break, then some possible blank chars and, finally, a zero
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But ONLY IF the look-ahead structure
(?=\R\h*\],)is true i. e. if the zero digit is immediately followed with a line-break, then possible blank characters and, finally, the string], -
As the replace zone is empty, the search match
,\R\h*0, described above, is simply deleted
Best Regards
guy038
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This has nothing to do with the main topic. Sorry for the tangent, but I’m curious:
@Meta-Chuh said:
@Billy-Martin,
your original text is:Meta, how do you see what the original text was? In some other forums, I am able to view the source of the post, and that shows the pre-edited version… but I when I view the source in the Notepad++ Community forum, I don’t see anything with the spaces. Where did you get the original from?
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Thank you guys… it worked as expected and as desired.
Thanks a lot… it really helps me a lot and makes my life easier.
Best regards,
Billy
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@PeterJones said:
Meta, how do you see what the original text was?
@Meta-Chuh YEA! How about it Meta??
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