I want to delete everything accept my ip and port on each line.

upperking

Delete multiple lines
I want to delete everything accept these numbers 76.247.131.161:57524<— this number changes and I want to keep on each line
I cant figure out how to do it correctly…

21 76.247.131.161:57524, Port:5524, 27012, RCON:27300, DIR:21, PID:45696, Name:
22 76.247.131.161:57544, Port:5544, 27022, RCON:27305, DIR:22, PID:23584, Name:
23 76.247.131.161:57564, Port:5564, 27032, RCON:27310, DIR:23, PID:26192, Name:
24 76.247.131.161:57584, Port:5584, 27042, RCON:27315, DIR:24, PID:51116, Name:

so it looks like this

76.247.131.161:57524
76.247.131.161:57544
76.247.131.161:57564
76.247.131.161:57584

guy038

Hello @upperking, and All,

@upperking, welcome to the Notepad++ Community !

Elementary, with a simple regex S/R :

Open the Replace dialog ( Ctrl + H )
Type in (?-is),\x20?Port.+ in the Find what : zone
Leave the Replace with: zone EMPTY
If necessary, tick the Wrap around option
Select the Regular expression search mode ( IMPORTANT )
Click once on the Replace All button or several times on the Replace button

Et voilà !

Notes :

The in-line modifiers (?-is) forces the search to be performed in a non-insensitive way and the dot . to match a single standard character only
Then, the part ,\x20?Port looks for a comma, followed with an optional space char and the string Port, in that exact case
Finally, the part .+ search for any non-null range of standard characters
As the Replacement zone is empty, the range , Port.........., ending any line is deleted

Best Regards,

guy038

upperking

holy crap that was amazing thank you…

One last issue how do I delete numbers on each line like example.
https://gyazo.com/1bc37153673f725c00bbae338937aa37

guy038

Hi @upperking,

Oupppss ! I should have read your post more carefully ! We must take the leading numbers in account ;-))

So, change the Find and Replace zones, as below :

SEARCH (?-is)^\d+\x20(76\.247\.131\.161:\d+).+

REPLACE \1

Notes :

Beware : if the IP address is not exactly the address 76.247.131.161, nothing is then replaced
The part ^\d+\x20 represents any number, beginning a line and followed with a space character
The dot meta character . is escaped with the \ to be considered as a literal
The group 1 is the string 76.247.131.161 followed with a colon, followed with the port number, which is rewritten, during the replacement phase

Cheers,

guy038