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    • guy038G
      guy038
      last edited by guy038

      Hello @peterjones, @ekopalypse, @alan-kilborn, @daxliniere, and All,

      @peterjones, you said :

      remember we’re on boost 1.70 now, not 1.55. The updated boost docs are here.

      Where did you see that the N++ regex engine migrates from Boost v1.55.0 to Boost v1.70.0 ?!

      I’ve tried to see any mention of this, in change.log files of recent N++ versions, without any result !


      Anyway, I compared the HTML contents of :

      http://www.boost.org/doc/libs/1_55_0/libs/regex/doc/html/boost_regex/syntax/perl_syntax.html

      and

      http://www.boost.org/doc/libs/1_73_0/libs/regex/doc/html/boost_regex/syntax/perl_syntax.html

      The main difference concerns the addition of the Backtracking Control Verbs functionality which, due to lack of testing, does not seem to be of prime importance, but I’m probably wrong !

      Here are the list of changes / additions between our Boost version v1.55.0 and the last version v1.7.3 of the regex library :

      ----------------------------------------------------------------------------------------------------------------------------------------------------------------
      
      Right BEFORE "Wilcard" paragraph, ADDITION of the line :
      
      
      Other characters are special only in certain situations - for example ] is special only after an opening [.
      
      ----------------------------------------------------------------------------------------------------------------------------------------------------------------
      
      Right BEFORE the sentence "It is an error to use a repeat operator....", ADDITION of the line : 
      
      
      Note that the "{" and "}" characters will treated as ordinary literals when used in a context that is not a repeat: this matches Perl 5.x behavior. For example in the expressions "ab{1", "ab1}" and "a{b}c" the curly brackets are all treated as literals and no error will be raised.
      
      -----------------------------------------------------------------------------------------------------------------------------------------------------------------
      
      Right AFTER the FIRST sentence, in "Backreferences" paragraph, CHANGE of the REGEX :
      
      
      ^(a*)[^a]*\1$    ( instead of ^(a*).*\1$ )
      
      -----------------------------------------------------------------------------------------------------------------------------------------------------------------
      
      Right BEFORE the "Operator precedence" paragraph, ADDITION of the "Backtracking Control Verbs" paragraph :
      
      
      Backtracking Control Verbs
      
      This library has partial support for Perl's backtracking control verbs, in particular (*MARK) is not supported. There may also be detail differences in behaviour between this library and Perl, not least because Perl's behaviour is rather under-documented and often somewhat random in how it behaves in practice. The verbs supported are:
      
          (*PRUNE) Has no effect unless backtracked onto, in which case all the backtracking information prior to this point is discarded.
          (*SKIP) Behaves the same as (*PRUNE) except that it is assumed that no match can possibly occur prior to the current point in the string being searched. This can be used to optimize searches by skipping over chunks of text that have already been determined can not form a match.
          (*THEN) Has no effect unless backtracked onto, in which case all subsequent alternatives in a group of alternations are discarded.
          (*COMMIT) Has no effect unless backtracked onto, in which case all subsequent matching/searching attempts are abandoned.
          (*FAIL) Causes the match to fail unconditionally at this point, can be used to force the engine to backtrack.
          (*ACCEPT) Causes the pattern to be considered matched at the current point. Any half-open sub-expressions are closed at the current point.
      
      -----------------------------------------------------------------------------------------------------------------------------------------------------------------
      
      Inside the "Operator precedence" paragraph, CHANGE of the REGEX :
      
      
      2. Escaped characters \    ( instead of [^] )
      
      -----------------------------------------------------------------------------------------------------------------------------------------------------------------
      

      Best Regards,

      guy038

      Alan KilbornA 1 Reply Last reply Reply Quote 1
      • Alan KilbornA
        Alan Kilborn @guy038
        last edited by

        @guy038 said in Wildcard in replace field:

        Where did you see that the N++ regex engine migrates from Boost v1.55.0 to Boost v1.70.0 ?!

        Well, the build instructions for Notepad++ mention Boost 1.70…

        But I suppose that isn’t definitive.

        It would be nice if maybe the Debug Info for Notepad++ included both the Scintilla and Boost version numbers it uses?

        PeterJonesP 1 Reply Last reply Reply Quote 1
        • PeterJonesP
          PeterJones @Alan Kilborn
          last edited by

          @Alan-Kilborn said in Wildcard in replace field:

          @guy038 said in Wildcard in replace field:

          Where did you see that the N++ regex engine migrates from Boost v1.55.0 to Boost v1.70.0 ?!

          Well, the build instructions for Notepad++ mention Boost 1.70…

          It’s also mentioned in here:
          https://github.com/notepad-plus-plus/notepad-plus-plus/blob/master/scintilla/boostregex/BoostRegExSearch.cxx#L1-L10

          Ah, okay, @xylographe made https://github.com/notepad-plus-plus/npp-usermanual/issues/47, which came as a result of BUILD.md.

          It would be nice if maybe the Debug Info for Notepad++ included both the Scintilla and Boost version numbers it uses?

          That would be nice. But unfortunately, none of us can be the one to put in the issue, otherwise it is likely to be ignored.

          Alan KilbornA 1 Reply Last reply Reply Quote 2
          • Alan KilbornA
            Alan Kilborn @PeterJones
            last edited by

            @PeterJones said in Wildcard in replace field:

            That would be nice.

            It would probably also be something a dev would have to remember to do by hand when it changes, instead of being automated, so it might be a poor idea anyway (I don’t trust the hoomans to remember to update these types of things).

            1 Reply Last reply Reply Quote 1
            • guy038G
              guy038
              last edited by guy038

              Hi, @alan-kilborn, @peterjones, @ekopalypse, and All,

              Alan and Peter, thank you so much for these clarifications ;-)

              Although the last Boost regex 1.7.3 version is not used and that Notepad++ is build with Boost v1.7.0 since N++ v7.8.0, the differences between the search regex documentation of Boost versions v1.5.5 and v1.7.0, mentioned in my previous post, are identical and are still valid ;-))


              So, the good news is that our new regex library does support the Perl’s backtracking control verbs. Woooow !! I’m quite eager to investigate this new side of regular expressions:-)) I will keep you informed of the interest of these new functions and will try to provide you with relevant examples for a better understanding…

              As a result, I have also updated the FAQ contents !


              Now, while browsing the Boost C++ libraries website, I came across a thorny problem : when we speak of Boost v1.70.0, I think that it’s an abuse of language ! Because the strings 1.55.0 and 1.70.0 refer to a documentation version and NOT to a library version :-( Indeed :

              • Formerly, we were using the Boost-Regex library from the Boost-1.54.0 version of the Boost C++ libraries and we referred to its Boost 1.55.0 library documentation

              • Since Notepad v7.7, we’re using the Boost-Regex-5.1.3 library from the Boost-1.64.0 version of the Boost C++ libraries and we refer to its Boost 1.70.0 library documentation

              Refer to all these links, below. It’s a bit tricky !? Compare the different links, two by two

              https://www.boost.org/doc/libs/1_55_0/

              https://www.boost.org/doc/libs/1_70_0/

              https://www.boost.org/doc/libs/1_55_0/libs/regex/doc/html/index.html

              https://www.boost.org/doc/libs/1_70_0/libs/regex/doc/html/index.html

              https://www.boost.org/doc/libs/1_55_0/libs/regex/doc/html/boost_regex/background_information/history.html

              https://www.boost.org/doc/libs/1_70_0/libs/regex/doc/html/boost_regex/background/history.html


              Could you confirm my guesses ? TIA !

              Cheers,

              guy038

              P.S :

              The last version uses the Boost-Regex-5.1.4 library from the Boost-1.72.0 version of the Boost C++ libraries and refers to the Boost 1.73.0 library documentation

              See :

              https://www.boost.org/doc/libs/1_73_0/

              https://www.boost.org/doc/libs/1_73_0/libs/regex/doc/html/index.html

              https://www.boost.org/doc/libs/1_73_0/libs/regex/doc/html/boost_regex/background/history.html

              1 Reply Last reply Reply Quote 1
              • daxliniereD
                daxliniere
                last edited by

                A big thank you to everyone who replied to my question offering help. @Alan-Kilborn’s suggestion seems to work perfectly.

                All the best to this great community!
                -Dax.

                1 Reply Last reply Reply Quote 2
                • daxliniereD
                  daxliniere
                  last edited by

                  Hey all!
                  I have no idea why, but for some reason, this solution has stopped working…
                  Seriosuly, I have no idea what’s going on, but (\d\d:\d\d):(?=\d\d) no longer finds a string of text that looks like 0:10:02 using RegEx.

                  Is it possible a recent update to NPP might have broken this or changed syntax??
                  I’m so confused.

                  Thanks in advance!
                  -Dax.

                  astrosofistaA 1 Reply Last reply Reply Quote 0
                  • astrosofistaA
                    astrosofista @daxliniere
                    last edited by

                    Hi @daxliniere

                    The quoted regex matches strings with two leading numbers, as “00:12:12”.
                    In order to match strings with only one leading number, just remove a “\d” from the expression, as (\d:\d\d):(?=\d\d).

                    Have fun!

                    daxliniereD 1 Reply Last reply Reply Quote 2
                    • daxliniereD
                      daxliniere @astrosofista
                      last edited by

                      @astrosofista Thank you so very much!! It works exactly as before.
                      I have no clue what could have changed, but this has solved the problem.

                      I really appreciate your time on this. I was in the middle of a job and got stuck on this. Was comtemplating manual correction of ~400 lines!

                      Have a great weekend. :)
                      -Dax.

                      1 Reply Last reply Reply Quote 1
                      • daxliniereD
                        daxliniere
                        last edited by

                        AHHH!!! I understand it now!

                        The data I had been receiving previously had trailing zeros so every line had xx:xx:xx formatting. It seems whoever was typing this started dropping the trailing zeros.
                        Is there a more robust form of (\d:\d\d):(?=\d\d) needed?

                        PeterJonesP 1 Reply Last reply Reply Quote 1
                        • PeterJonesP
                          PeterJones @daxliniere
                          last edited by

                          @daxliniere ,

                          You say “trailing”, but the regex shown (as modified by @astrosofista) has removed the requirement for leading zeros. To make it match both, I’d do (\d{1,2}:\d\d):(?=\d\d), which will match whether there is one digit or two.

                          But if you give an example of “with” or “without” “trailing zeros”, we can be more confident of what you’re really asking for.

                          Thomas 2020T 1 Reply Last reply Reply Quote 2
                          • Thomas 2020T
                            Thomas 2020 @PeterJones
                            last edited by

                            @PeterJones
                            instead:
                            (\d{1,2}:\d\d):(?=\d\d)

                            maybe that’s better?
                            (:\d{1,2}):

                            the shorter the pattern, the better

                            PeterJonesP 1 Reply Last reply Reply Quote 0
                            • PeterJonesP
                              PeterJones @Thomas 2020
                              last edited by

                              @Pan-Jan ,

                              Your regex does not provide all the same groups (and thus features) of the regex developed through this thread, and thus likely misses some of the functionality needed

                              1 Reply Last reply Reply Quote 0
                              • Thomas 2020T
                                Thomas 2020
                                last edited by Thomas 2020

                                @PeterJones said in Wildcard in replace field:

                                and thus likely misses some of the functionality needed

                                show on the example in this thread that it doesn’t work

                                (\d{1,2}:\d\d):(?=\d\d)
                                but this one has disadvantages, and he will also mark it here
                                126:23:45
                                126:23:450
                                12:23:45:67

                                it will be correct

                                (^| )(\d{1,2}:\d\d):(?=\d\d( |$))

                                1 Reply Last reply Reply Quote 0
                                • Thomas 2020T
                                  Thomas 2020
                                  last edited by Thomas 2020

                                  This post is deleted!
                                  1 Reply Last reply Reply Quote 0
                                  • Thomas 2020T
                                    Thomas 2020
                                    last edited by Thomas 2020

                                    (^| )(\d{1,2}:\d\d):(?=\d\d([ ,'!\.\?"”\)]|$))

                                    1 Reply Last reply Reply Quote 0
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