Find/Replace number with Increment Value

DJSpirosG

Hi to everyone, i am looking for some help here!!!

What i want to do is to Search and Replace incrementally the pattern below [#n+1].
As am aware this will require a python script probably.

[#0]
T=2
F=INITIALKEY
1=Gm
2=1A
3=0|0

[#1]
T=2
F=INITIALKEY
1=A\u266d m
2=1A
3=0|0

[#2]
T=2
F=INITIALKEY
1=D# m
2=2A
3=0|0```

PeterJones

@DJSpirosG ,

Yes, PythonScript is the way to go. There is even an example of a callback which does “add one” (search for add_1 in the PS “Editor Object” docs)

PeterJones

…

and here is a post where I show it in this Forum

addenda: regex would be something like (\\[\#\d+\\]) /addenda

DJSpirosG

@PeterJones thanks for the help!

I’am burned…
I don’t exactly understand how to succeed what i want to!
Sorry!

PeterJones

@DJSpirosG ,

Sorry, given that you knew PythonScript would be required, I thought you already knew how to use it.

if this is a one-off, just use the PythonScript, show console, and type the next 3 filled lines (plus a couple of extra returns between the function and the call, because the console requires an extra newline to end a function definition…)

def add_1(m):
    return m.group(1) + str(int(m.group(2)) + 1) + m.group(3)


editor.rereplace('(\[\#)(\d+)(\])', add_1);

Yes, after debugging, I changed the regex to make the replacement easier for me.

If this is going to be used more than once, do Python Script > New Script, and paste in those four lines, and use the PythonScript menus to run the script and/or assign it to the Run menu…

DJSpirosG

@PeterJones If i am right this adds one to the existed digit inside the brackets.
What i actually want is to add one to the next bracket so if bracket one is [#1] the next one to be [#2].

The example below is my actual problem.
i want the script to calculate the digit inside the previous bracket [#34] and replace the next one [#1] with [#35] the [#2] with [#36] and so on !

[#34]
T=2
F=INITIALKEY
1=E maj
2=12B
3=0|0

[#1]
T=2
F=INITIALKEY
1=Gm
2=1A
3=0|0

[#2]
T=2
F=INITIALKEY
1=A\u266dm
2=1A
3=0|0```

PeterJones

@DJSpirosG ,

I believe this does what you want:

prev = None
def renumber(m):
    global prev
    if prev == None:
        prev = int(m.group(2))
    else:
        prev = prev + 1

    return m.group(1) + str(prev) + m.group(3)

editor.rereplace(r'^(\[#)(\d+)(\])', renumber);

DJSpirosG

@PeterJones Thank you for your time appreciated!

It needs a small fix (adding some \ ) and it works flawlessly!

editor.rereplace(r'^(\[\#)(\d+)(\])', renumber);

PeterJones

@DJSpirosG ,

Sorry, even in ```, the forum strips \\[ to become [ under certain circumstances

DJSpirosG

@PeterJones
HaHa
i was so pissed of…
i was trying to post the correct one but i couldn’t…
i tried to edit my post about 100 times in the last minute!!!

Thanks once again!

guy038

Hello @peterjones, @DJSpirosG and All,

I suppose that the regex, in the Python script, is r'^(\\[#)(\d+)(\\])' and NOT r'^(\[#)(\d+)(\])' !!

If so, Peter, I can edit your post and make the corrections. Just tell me !

Remark : To explicitly write the literal strings \\[ and \\], in our forum, you need to write them as \\\[ and \\\]

Note also that, unfortunately, the Preview panel does not show the right layout :-(( Things are OK when you click on the Submit button, only !

BR

guy038

P.S. :

To write the text, of the Remark line, just above, I needed to write :

First, 2 consecutive \ before each square bracket !
Second, 3 consecutive \ before each square bracket !

prahladmifour

This post is deleted!