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    regex: Match everything up to linebreak but not linebreak

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    • Neil SchipperN
      Neil Schipper @Hellena Crainicu
      last edited by

      @Hellena-Crainicu But you’re asking about a regex to feed into a call to re.findall(), correct? Or are you asking how to convert lines of text that look like your <title>..<\title> example that are in a text file loaded in the np++ editor?

      If it’s the latter, I have a solution but I’m confused.

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      • Hellena CrainicuH
        Hellena Crainicu
        last edited by

        @Neil-Schipper I am using \w+ as you can see. But I need to stop selecting on the linebreak |, othewise I will get my-name-is-peter-prince-justin.html instead of my-name-is-peter.html

        Neil SchipperN 1 Reply Last reply Reply Quote 0
        • Neil SchipperN
          Neil Schipper @Hellena Crainicu
          last edited by

          @Hellena-Crainicu I’m not getting the clarity I’m hoping for. Here are two very different things people do on computers:

          1. running a python program that processes an input file, and maybe changes it or produces an output file, etc.

          2. having a file loaded in an editor, and running a search and replace operation on it

          Which of these are you trying to do (that requires regex assistance as you described)?

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          • Hellena CrainicuH
            Hellena Crainicu
            last edited by

            it is just about the regex… maybe @guy038 will can help me. He is the master of regex.

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            • Neil SchipperN
              Neil Schipper
              last edited by

              For my own amusement, I solved the problem in the editor.

              I broke the problem into:

              1. consume from start line to first ‘>’
              2. capture everything up to and excluding (space followed by literal ‘|’) into group 1
              3. consume everything else up to and including EOL

              The search phrase ^.*?>(.+?)(?= \|).*?$ does this. Then replace with \1.html. Then a separate S&R can convert all spaces to ‘-’.

              But I still don’t know what you’re asking for, because you refuse to tell me!

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              • Neil SchipperN
                Neil Schipper
                last edited by

                Again, for my own amusement (since I’ve never used re.sub() before, only match & split):

                >>> t1 = re.sub(r"^.*?>(.+?)(?= \|).*?$", r"\1.html", "<title>My name is Peter | Prince Justin (en)</title>")
                >>> t2 = re.sub(r"\s", r"-", t1)
                >>> t2
                'My-name-is-Peter.html'
                >>>
                
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                • Hellena CrainicuH
                  Hellena Crainicu
                  last edited by

                  I must split all html files, not just one. I don’t think I can use the replacement…

                      new_filename = title.get_text() 
                      new_filename = new_filename.lower()
                      words = re.findall(r'\w+', new_filename)
                      new_filename = '-'.join(words)
                      new_filename = new_filename + '.html'
                      print(new_filename)
                  
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                  • Hellena CrainicuH
                    Hellena Crainicu
                    last edited by

                    I try now this regex: \w+.*(?= \|)

                    words = re.findall(r"\w+.*(?= \|)", new_filename)

                    almost works, but I get: my name is peter.html (but without little dash)

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                    • Alan KilbornA
                      Alan Kilborn
                      last edited by

                      You guys are OFF-TOPIC.
                      This is not an appropriate place to discuss Python’s regular expression engine.
                      Please find a more appropriate forum for that and confine discussions here to Notepad++ related topics.
                      Just because you write Python code in Notepad++ doesn’t make discussion of that code a Notepad++ topic.

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                      • Hellena CrainicuH
                        Hellena Crainicu
                        last edited by Hellena Crainicu

                        I find the regex which I needed: \b\w+\b(?=[\w\s]+\|)

                        and in Python should be:

                        words = re.findall(r'\b\w+\b(?=[\w\s]+\|)', new_filename)

                        thanks @Neil-Schipper You give me a good ideea ;)

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