Regex help using find for the first 15 characters only.

Caner Ak

Is there a way to create an expression that will only look at the first 15 characters from the start of a line?
Example:

12345600000001U etc
12345600000002T etc
12345600000003U etc.
12345600000004T etc

In this case I only want the rows with “U” at the end of the first 15 characters of the string (because there could be “U” after the first 15 characters in the rows containing “T”'s).

PeterJones

@Caner-Ak ,

Yes, using single character matches, quantifiers/multiplying operators and anchors: For example, ^.{14}U will only match “start-of-line, then 14 of any character, then a U”.

Note: When using . to match any character, make sure you have the correct state of . Matches Newline or use the equivalent search modifier (?-s)/(?s) in the regex.

----

Regex help using find for the first 15 characters only.

Useful References