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Marcel Lindig

I need to hide the comments, because I want to numbering only the code lines.
Or if somebody have an idea to numbering all the program lines only, please answer me.

It look like this:

;comment
;comment
;comment
N10 G1 X300
N20 G1 X0
;comment
;comment
N30 G0 Z200
N40 G1X400
…

Claudia Frank

@Marcel-Lindig

if semicolon is only once in every line and only within the comment line than
you can search for semicolon and count it, abstract from total number of lines and
you should get the number of code lines.

Cheers
Claudia

guy038

Hello, @marcel-lindig,

Even more simple ! From your post, I supposed that, in your language, your comment lines, begin with a semicolon symbol. Now :

Open the Find dialog ( Ctrl + F )
Type ^[^;\r\n], in the Find what: box
Choose the Regular expression search mode ( IMPORTANT )
Click on the Count button

=> You, automatically, get the number of NO-comment lines. ( I supposed that complete blank lines are considered as comment lines ! )

Et voilà !!

Now, if the Python script is installed , in your N++ configuration, you may use, on the other hand, the Claudia’s script, from the link, below :

https://notepad-plus-plus.org/community/topic/13754/replace-1-lines/12

Add the comment line ;^[^;\r\n], anywhere in your file
Select the part ^[^;\r\n], without the leading semicolon
Run the Claudia’s script

=> You, automatically, get, the number of NO-comment lines, again :-D

Best Regards,

guy038

Marcel Lindig

hm you don´t understand me correctly.

First I wrote this:

;comment
;comment
;comment
G1 X300
G1 X0
;comment
;comment
G0 Z200
G1X400

then I want automatically this:

;comment
;comment
;comment
N10 G1 X300
N20 G1 X0
;comment
;comment
N30 G0 Z200
N40 G1X400

Claudia Frank

@Marcel-Lindig

if you are williing to install python script plugin,
these script may do what you want

new_cnc_code = ''
counter = 10

def add_text(content, line, total):
    global new_cnc_code
    global counter
    if content.startswith(';'):
        new_cnc_code += content
    else:
        new_cnc_code += 'N{0} {1}'.format(counter, content)
        counter += 10

editor.forEachLine(add_text) # loop through existing text
editor.beginUndoAction() # set an undo start point
editor.clearAll() # delete the complete content
editor.appendText(new_cnc_code) # add the newly created code
editor.endUndoAction()  # set an undo end point

In case anything goes wrong you should be able to revert everything by pressing undo button.
Don’t know your python knowledge - if something is unclear, let us know.

Cheers
Claudia

guy038

Hello, @marcel-lindig,

Of course, the Clauda’s Python script is, certainly, the more simple method to achieve it. But, if you don’t want to use any plugin, here is a procedure, using native N++ commands, only. However, this method will need some steps for the user to do !!

It, mainly, uses :

Automatic column numbering, with the Column Editor
Search / Replace actions, with the Replace dialog
Ascending Lexical Sort

So, let’s start with the original text, below :

;comment 1
;comment 2
;comment 3
G1 X300
G1 X0
;comment 4
;comment 5
G0 Z200
G1X400
;comment 6
G2Y100
G3 H500
G2 K200
;comment 7
;comment 8
G0 F50
;comment 9
G3 F100
;comment 10
G1M100
G1P10
G2 V700
G5 D1000

Place the caret to the very beginning of your file, column 1, Line 1 ( Ctrl + Origin )
Then, move with the vertical scroll bar, on the right, exclusively, to the last line, column 1
Use the Alt + Maj + Left click shortcut to get a zero-length rectangular selection, at column 1
Hit, twice, on the space key, to add 2 space characters
Hit, once, on the Left Arrow key, to move back, line 1, column 2
Select the option Edit > Column Editor… ( Alt + C )
- Select the option Number to Insert
- Type 1 in the two fields Initial number and Increase by
- Check the Leading zeros box
- If necessary, select the Dec radio button
- Click on the OK button
- Delete, possibly, the last non-significant number

You should have the modified text, below :

 01 ;comment 1
 02 ;comment 2
 03 ;comment 3
 04 G1 X300
 05 G1 X0
 06 ;comment 4
 07 ;comment 5
 08 G0 Z200
 09 G1X400
 10 ;comment 6
 11 G2Y100
 12 G3 H500
 13 G2 K200
 14 ;comment 7
 15 ;comment 8
 16 G0 F50
 17 ;comment 9
 18 G3 F100
 19 ;comment 10
 20 G1M100
 21 G1P10
 22 G2 V700
 23 G5 D1000

Add TWO complete blank lines, at the end of file, WITHOUT leading spaces
Move back, to the very beginning of the file ( Ctrl + Origin )
Open the Replace dialog ( Ctrl + H )
- SEARCH (?-s)((?:^ \d+ [^;].+\R)++)(?s)(.+)
- REPLACE \2\1
- UN-check the Wrap around option
- Select the Regular expression search mode
- Click on the Replace All button, SEVERAL times, till the message Replace All: 0 occurrences were replaced occurs

Now, your text is changed into the one below :

 01 ;comment 1
 02 ;comment 2
 03 ;comment 3
 06 ;comment 4
 07 ;comment 5
 10 ;comment 6
 14 ;comment 7
 15 ;comment 8
 17 ;comment 9
 19 ;comment 10


 04 G1 X300
 05 G1 X0
 08 G0 Z200
 09 G1X400
 11 G2Y100
 12 G3 H500
 13 G2 K200
 16 G0 F50
 18 G3 F100
 20 G1M100
 21 G1P10
 22 G2 V700
 23 G5 D1000

Move to the first NO-comment line, column 1
Locate the caret, right after the digits and the space character, located after
Select, again, the option Edit > Column Editor… ( Alt + C )
- Select the option Number to Insert
- Type, this time, 10 in the two fields Initial number and Increase by
- Use the same options as above, and click on the OK button
- Delete, possibly, the last non-significant number
Move, again, to the first NO-comment line, at column 1
Then, open the Replace dialog ( Ctrl + H )
- SEARCH ^( \d+ )(\d+)
- REPLACE \1N\2\x20
- Use the same options as above and click, ONCE, on the Replace All button

After the numbering and S/R actions, you should get the text :

 01 ;comment 1
 02 ;comment 2
 03 ;comment 3
 06 ;comment 4
 07 ;comment 5
 10 ;comment 6
 14 ;comment 7
 15 ;comment 8
 17 ;comment 9
 19 ;comment 10


 04 N010 G1 X300
 05 N020 G1 X0
 08 N030 G0 Z200
 09 N040 G1X400
 11 N050 G2Y100
 12 N060 G3 H500
 13 N070 G2 K200
 16 N080 G0 F50
 18 N090 G3 F100
 20 N100 G1M100
 21 N110 G1P10
 22 N120 G2 V700
 23 N130 G5 D1000

Now, move back at the first line of your file, column 1 ( Ctrl + Origin )
Perform a sort, with the menu option Edit > Line Operations > Sort Lines Lexicographically Ascending
Move, once more, at the very beginning of your file ( Ctrl + Origin )
Delete, if necessary, the pure blank lines, at beginning of the file
Finally, open the Replace dialog ( Ctrl + H )
- SEARCH ^\x20\d+\x20
- REPLACE Leave EMPTY
- Use the same options as above and click, ONCE, on the Replace All button

Et voilà ! You should obtain the expected text, below :

;comment 1
;comment 2
;comment 3
N010 G1 X300
N020 G1 X0
;comment 4
;comment 5
N030 G0 Z200
N040 G1X400
;comment 6
N050 G2Y100
N060 G3 H500
N070 G2 K200
;comment 7
;comment 8
N080 G0 F50
;comment 9
N090 G3 F100
;comment 10
N100 G1M100
N110 G1P10
N120 G2 V700
N130 G5 D1000

BTW, from my first S/R above, here is the general way to separate file contents, in TWO parts, according to a criterion ( or more ! ) , with the INITIAL order KEPT. The generic regex is :

SEARCH (?-s)((?:^Regex.*\R)++)(?s)(.+)

REPLACE \2\1

For instance, let’s suppose that you want to separate a text in two parts, each of them keeping the initial order, with the simple condition : a digit, at column 7. Thus, the regex, to include into the generic one, is the regex .{6}\d , giving the final S/R :

SEARCH (?-s)((?:^.{6}\d.*\R)++)(?s)(.+)

REPLACE \2\1

After the replacement :

The first part will contain all the lines, which do NOT have a digit, at column 7
The second part will contain all the lines, which DO have a digit, at column 7

So, from the example text, with a line break, after the last line, below :

Val : 7 this is a
Val : 3 simple text
Val : A THIS IS A
Val : 4 which should
Val : Z SIMPLE TEXT
Val : L WHICH SHOULD
Val : 9 be readable
Val : F BE READABLE
Val : C AFTER THE
Val : 0 after the
Val : 4 search/replacement
Val : X SEARCH/REPLACEMENT

After SEVERAL clicks on the Replace All button, till the message Replace All: 0 occurrences were replaced occurs, you should get the modified text, below :

Val : A THIS IS A
Val : Z SIMPLE TEXT
Val : L WHICH SHOULD
Val : F BE READABLE
Val : C AFTER THE
Val : X SEARCH/REPLACEMENT
Val : 7 this is a
Val : 3 simple text
Val : 4 which should
Val : 9 be readable
Val : 0 after the
Val : 4 search/replacement

Important :

In the generic search regex, (?-s)((?:^Regex.*\R)++)(?s)(.+), just note that I use a possessive quantifier, which does NOT allow any backtracking phase.

So, when, after some permutations, it remains, only, lines with a digit at column 7, at the end of file, the regex, after catching all these lines, cannot match, , with the second part (?s)(.+), any additional character and fails immediately ! So, the S/R process ends, as expected, with the normal message Replace All: O occurrences were replaced

If you would use the regex (?-s)((?:^.{6}\d.*\R)+)(?s)(.+), with, instead, a greedy quantifier, the S/R process would NEVER end !

Best regards,

guy038

Marcel Lindig

Thanks a lot.
It works fine.
I will modify it for some other functions.