Find and Replace to include <cr><lf>?

EP Pack

I have a set of text that is in the format of “word1, word2, word3, word4, etc”, and I want to change them to individual lines by replacing the space after the comma with a CRLF so that it will look like this:
word1,
word2,
word3,
word4,
etc

The problem is that I’m not sure what to include in the replace part so that it actually will do that. I’d been using Ultraedit for many years at work, and it did this uneventfully, but alas! I’m retired now, so no longer have access to it.

By showing the symbols, I can SEE the CR LF at the end of a test line, but apparently I can’t simply copy and paste the comma, space and CRLF into the replace box–tried it but nothing changed, no actual CR occured. Gotta be a way to do this, but like many, I’m pretty new to ++.

TIA

Elaine

guy038

Hello, @ep-pack,

Really not difficult, indeed, with regular expressions !

Move to the very beginning of your text to change ( Ctrl + Origin )
Open the Replace dialog ( CTRL + H )
Type in the regex ,\x20 , in the Find what: box
Type in the regex \r\n , in the Replace with: box
UN-check the Wrap around box option, if necessary
Select the Regular expression search mode
Click on the Replace All button

Et voilà !

Notes :

The syntax \x20 stands for a single space character. You may write a normal space character, instead, in the search zone
In replacement, the syntax \r OR \x0D represents the control character Carriage Return ( CR )
In replacement, the syntax \n OR \x0A represents the control character Line Feed ( LF )

Best Regards,

guy038

EP Pack

I’ll give this a shot–I would NEVER have thought regex would work for a replace option in a text editor. Interesting :) Not a big regex user, but do know enough to be dangerous :)

Thanks!

elaine

EP Pack

@guy038, worked like a champ!! Thanks!

It initially didn’t because I hadn’t noticed the “use regex” radio button :) but once I did, hurray!

elaine