Replace all places of text that contain ips in brackets with nothing
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 Title! I need help and it would be appreciated! “max100:[216.36.165.77]naconnin” is one of the examples 
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 use regular expression checked, find what: \[\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\]replace with: []\d looks for any digit 
 {1,3} means digit must occur at least once and at most 3 times
 the dot needs to be escaped by backslash if it sholud be used literally, same applies to [ and ]Cheers 
 Claudia
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 @Claudia-Frank said: [] Hello Claudia, it doesn’t seem to work. It throws me that nothing was replaced. Is it possible that it would delete all of the stuff inside the brackets? 
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 Is you cursor set on first line? 
 Do you use wrap around setting with file dialog?Cheers 
 Claudia
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 Thank You, it worked! 
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 Wait, it doesn’t still seem to delete everything inside the brackets. Sorry for your time but is it possible to make that it will find the brackets and remove everything inside them? 
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 it would delete IP’s, is there anything else inside? 
 If so, what COULD be inside?Cheers 
 Claudia
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 or the other way, is only the text inside the brackets which should be deleted? If so, find \[.*\]and replace with []Cheers 
 Claudia
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 I could tell from the very first posting that things were going to go the way they have… 
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 Hi, @patrick-tamm, @claudia-frank and @scott-sumner, Claudia, regarding your last regex, it would better to use a lazy quantifier, just in case of lines, as below : This is [an example] of text with [some pairs] of square brackets, in the [same line] !So a correct regex S/R should be : SEARCH : \[.*?\]REPLACE : []OPTIONS : Regular expressionandWrap aroundand, maybe,. matches newlineif brackets pair are split on two different lines !ACTION : Click on the Replace AllbuttonCheers, guy038 


