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    Remove one character before a character

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    • יואב פתאלי
      יואב פתאל
      last edited by

      Hi, so I have a long list separated by one character, and I need them to be separated by only one space.

      So for example, I have this:
      Test | Word
      And I want this:
      Test Word

      I can’t just replace | with blank because it will leave two spaces instead of one.
      Help?

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      • Jon CompsJ
        Jon Comps
        last edited by Jon Comps

        If the | is always surrounded by two spaces you can replace " | " with " " (remove the speech marks they were just to highlight the use of spaces)

        Jon

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        • Terry RT
          Terry R
          last edited by

          Bear in mind that the replacement string can be empty, which effectively means destroy/delete what i want to find.

          In your case however that would leave 2 spaces together. Try this:
          Find:\h|\h
          Replace:\h
          The \h looks for a space (Horizontal spacing. This only matches space, tab and line feed). So we have look for a space followed by the character I want, then another space and replace with only 1 space.

          Terry

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          • mkupperM
            mkupper
            last edited by

            If you had Test | Word and replaced the | with a space then you would have three spaces, not two.

            If your list uses | as a separator and that sometimes there are one or more spaces before and/or after the | then use regular expression mode.
            Search for: \x20*\|\x20*
            Replace with: \x20

            • The first \x20* looks for zero or more leading spaces. I used \x20 rather than a space self as it’s easier to see on the screen.
            • \| looks for the |. In regular expression mode a | is special and so use \| to search for a | itself.
            • The second \x20* looks for zero or more trailing spaces.

            If your data has either one or zero spaces before and after the | and never had two or more spaces before/after the | then you can use
            Search for: \x20?\|\x20?
            Replace with: \x20

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