Perl language syntax highlighting troubles (bug or limitation ?)
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I don’t understand your regexp syntax. Perhaps too ‘pythonized’ for me.
(?s) : what does it mean ? is it ‘s///’ ? or really a non capturing group of ‘s’ ???
\3 \4 : are they $3 $4, I don’t think as I can’t see a 4th accumulator -
(?s) is a modifier telling the engine that the dot matches line endings
and yes, the engine uses \1 and $1Here the link to the documentation - maybe easier for you.
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ooppps
(?s)((<<)\h+(["|'])(\w+?)\3\h*;.*?\3):-D
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This post is deleted! -
Ok
another one: in Python you must say["|']instead of Perl["'](‘either one of the set’) ? Is that what it means ? -
No, afaik non-capturing group is (?:pattern)
This, (?s), just tells the engine that the dot.is matching
EOLs like\r\n- if I’m right. -
Just for clarification, the python script does NOT use the python regex engine instead
it uses the one notepad++ offers, the boost::regex.
Yes, you can use the enumeration without the pipe but makes it more visible for me with
the pipe sign. Or is there a difference if used with pipe sign or without? -
or maybe this one might be even better
(?s)(<<)\h+(["'])(\w+?)\2\h*;.*?\3 -
Can’t reply what I wanted, a robot says I’m spamming…
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Can’t reply what I wanted, a robot says I’m spamming…
I have no idea why this happens sometimes.
By the way, now that you have installed pythonscript plugin would you mind
clicking Plugins->Python Script->Scripts->Samples->RegexTester ?I know not everyone is recommending it but, personally, I love it.
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AFAIK, at least in Perl, ["|'] means double-quote OR pipre OR simple-quote, everything between square brakets is literal. Also true in “awk” and C regexp I think.
I don’t know for Python. -
Now, if I say in Pyhton (attempt to transliterate from Perl) :
(r'(?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)', [2])does it mean :
- form REGEXP
- do not match NL with DOT
- matches any horizontal blanks (0 or more), don’t make a group
- matches ‘<<’ make it a group
- matches any horizontal blanks (0 or more), don’t make a group
- matches 0 or 1 text quote (either double or single), no group
- matches a group of any chars not " nor ’ one or more time(s) (in perl it would be [^"'])
- matches 0 or 1 text quote (either double or single), no group
- possible blanks until semi-colon, semi-colon, then possible chars until NL
BUT THEN, what does mean
?\3. I’m lost there. -
a
slash m -
the
rat the beginning just informs python that this is a raw string and
every char must be taken literally otherwise backslashes would be treated
as escapes under some circumstances.The regex string is only this part
(?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)and I would say, but as said - not an regex expert at all,
(?s) means Dot matches newline characters
the first matching group is(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)the second
(<<)and the third must be
([^"|^']+?)if I’m right.
\3 should be the same as $3 in perl
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still confused:
([^"|^']+?)why a ‘?’ after the ‘+’ what’s for this ‘?’and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks surrounded by parenthèses only.
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still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’
as less as possible - non-greedy
and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in >subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks >surrounded by parenthèses only.
placeholder for what was found in match group 3, to find the EOT at the end
and there are 3 match groups or am I missing something??
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2 sets of parenteses only, where is the third set ?
so only 2 match groupscan you make this work :
no syntax error on the python console but absolutely no result, where is my bug ?
regexes[(3, (255,255,255))] = (r'(?s)(\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)', [1]) -
[1]informs the python script, that only the results from sub match group 1 should be colored in white (255,255,255)
sub match group 1 is the result of (<<)In order to make it painting all you can use [0]
I’m still confused about the 2 to 3 match groups.
Am I incorrect when saying that
(\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)
(<<)
("{0,1}.+"{0,1})
are three match groups?Maybe the confusion comes from the fact that references matches within a
regular expression starts by 1 but python starts counting match results by 0.Sorry, but I have to stay up early tomorrow and it is already 1am but I’m really
interested in solving our (mis)understanding today later (maybe in ~16-18hours)? -
ok, tomorrow is another day
‘see’ you tomorrow.
have a good night.
g
