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    Perl language syntax highlighting troubles (bug or limitation ?)

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    • Gilles MaisonneuveG Offline
      Gilles Maisonneuve @Ekopalypse
      last edited by

      @Ekopalypse

      I don’t understand your regexp syntax. Perhaps too ‘pythonized’ for me.

      (?s) : what does it mean ? is it ‘s///’ ? or really a non capturing group of ‘s’ ???
      \3 \4 : are they $3 $4, I don’t think as I can’t see a 4th accumulator

      1 Reply Last reply Reply Quote 0
      • EkopalypseE Offline
        Ekopalypse
        last edited by Ekopalypse

        (?s) is a modifier telling the engine that the dot matches line endings
        and yes, the engine uses \1 and $1

        Here the link to the documentation - maybe easier for you.

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        • EkopalypseE Offline
          Ekopalypse
          last edited by

          ooppps

          (?s)((<<)\h+(["|'])(\w+?)\3\h*;.*?\3)

          :-D

          Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
          • Gilles MaisonneuveG Offline
            Gilles Maisonneuve @Ekopalypse
            last edited by

            This post is deleted!
            1 Reply Last reply Reply Quote 0
            • Gilles MaisonneuveG Offline
              Gilles Maisonneuve @Ekopalypse
              last edited by

              @Ekopalypse

              Ok
              another one: in Python you must say ["|'] instead of Perl ["'] (‘either one of the set’) ? Is that what it means ?

              EkopalypseE 1 Reply Last reply Reply Quote 0
              • EkopalypseE Offline
                Ekopalypse
                last edited by

                No, afaik non-capturing group is (?:pattern)
                This, (?s), just tells the engine that the dot . is matching
                EOLs like \r\n - if I’m right.

                1 Reply Last reply Reply Quote 1
                • EkopalypseE Offline
                  Ekopalypse
                  last edited by Ekopalypse

                  Just for clarification, the python script does NOT use the python regex engine instead
                  it uses the one notepad++ offers, the boost::regex.
                  Yes, you can use the enumeration without the pipe but makes it more visible for me with
                  the pipe sign. Or is there a difference if used with pipe sign or without?

                  1 Reply Last reply Reply Quote 1
                  • EkopalypseE Offline
                    Ekopalypse
                    last edited by Ekopalypse

                    or maybe this one might be even better
                    (?s)(<<)\h+(["'])(\w+?)\2\h*;.*?\3

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                    • Gilles MaisonneuveG Offline
                      Gilles Maisonneuve
                      last edited by

                      Can’t reply what I wanted, a robot says I’m spamming…

                      Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
                      • EkopalypseE Offline
                        Ekopalypse @Gilles Maisonneuve
                        last edited by

                        @Gilles-Maisonneuve

                        Can’t reply what I wanted, a robot says I’m spamming…

                        I have no idea why this happens sometimes.

                        By the way, now that you have installed pythonscript plugin would you mind
                        clicking Plugins->Python Script->Scripts->Samples->RegexTester ?

                        I know not everyone is recommending it but, personally, I love it.

                        1 Reply Last reply Reply Quote 1
                        • Gilles MaisonneuveG Offline
                          Gilles Maisonneuve @Gilles Maisonneuve
                          last edited by

                          AFAIK, at least in Perl, ["|'] means double-quote OR pipre OR simple-quote, everything between square brakets is literal. Also true in “awk” and C regexp I think.
                          I don’t know for Python.

                          Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                          • Gilles MaisonneuveG Offline
                            Gilles Maisonneuve @Gilles Maisonneuve
                            last edited by

                            @Ekopalypse

                            Now, if I say in Pyhton (attempt to transliterate from Perl) :

                            (r'(?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)', [2])
                            

                            does it mean :

                            1. form REGEXP
                            2. do not match NL with DOT
                            3. matches any horizontal blanks (0 or more), don’t make a group
                            4. matches ‘<<’ make it a group
                            5. matches any horizontal blanks (0 or more), don’t make a group
                            6. matches 0 or 1 text quote (either double or single), no group
                            7. matches a group of any chars not " nor ’ one or more time(s) (in perl it would be [^"'])
                            8. matches 0 or 1 text quote (either double or single), no group
                            9. possible blanks until semi-colon, semi-colon, then possible chars until NL

                            BUT THEN, what does mean ?\3. I’m lost there.

                            Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
                            • Gilles MaisonneuveG Offline
                              Gilles Maisonneuve @Gilles Maisonneuve
                              last edited by

                              a slash m

                              EkopalypseE 1 Reply Last reply Reply Quote 0
                              • EkopalypseE Offline
                                Ekopalypse
                                last edited by Ekopalypse

                                the r at the beginning just informs python that this is a raw string and
                                every char must be taken literally otherwise backslashes would be treated
                                as escapes under some circumstances.

                                The regex string is only this part

                                (?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)
                                

                                and I would say, but as said - not an regex expert at all,

                                (?s) means Dot matches newline characters
                                the first matching group is

                                (\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)
                                

                                the second

                                (<<)
                                

                                and the third must be

                                ([^"|^']+?)
                                

                                if I’m right.

                                \3 should be the same as $3 in perl

                                Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                                • Gilles MaisonneuveG Offline
                                  Gilles Maisonneuve @Ekopalypse
                                  last edited by Gilles Maisonneuve

                                  @Ekopalypse

                                  still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’

                                  and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks surrounded by parenthèses only.

                                  EkopalypseE 1 Reply Last reply Reply Quote 0
                                  • EkopalypseE Offline
                                    Ekopalypse @Gilles Maisonneuve
                                    last edited by

                                    @Gilles-Maisonneuve

                                    maybe this picture makes it a little bit clearer

                                    1 Reply Last reply Reply Quote 2
                                    • EkopalypseE Offline
                                      Ekopalypse @Gilles Maisonneuve
                                      last edited by Ekopalypse

                                      @Gilles-Maisonneuve

                                      still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’

                                      as less as possible - non-greedy

                                      and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in >subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks >surrounded by parenthèses only.

                                      placeholder for what was found in match group 3, to find the EOT at the end

                                      and there are 3 match groups or am I missing something??

                                      Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                                      • Gilles MaisonneuveG Offline
                                        Gilles Maisonneuve @Ekopalypse
                                        last edited by

                                        @Ekopalypse

                                        2 sets of parenteses only, where is the third set ?
                                        so only 2 match groups

                                        can you make this work :

                                        no syntax error on the python console but absolutely no result, where is my bug ?

                                        regexes[(3, (255,255,255))] = (r'(?s)(\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)', [1])
                                        
                                        EkopalypseE 1 Reply Last reply Reply Quote 0
                                        • EkopalypseE Offline
                                          Ekopalypse @Gilles Maisonneuve
                                          last edited by Ekopalypse

                                          @Gilles-Maisonneuve

                                          [1] informs the python script, that only the results from sub match group 1 should be colored in white (255,255,255)
                                          sub match group 1 is the result of (<<)

                                          In order to make it painting all you can use [0]

                                          I’m still confused about the 2 to 3 match groups.
                                          Am I incorrect when saying that
                                          (\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)
                                          (<<)
                                          ("{0,1}.+"{0,1})
                                          are three match groups?

                                          Maybe the confusion comes from the fact that references matches within a
                                          regular expression starts by 1 but python starts counting match results by 0.

                                          Sorry, but I have to stay up early tomorrow and it is already 1am but I’m really
                                          interested in solving our (mis)understanding today later (maybe in ~16-18hours)?

                                          1 Reply Last reply Reply Quote 1
                                          • Gilles MaisonneuveG Offline
                                            Gilles Maisonneuve
                                            last edited by

                                            ok, tomorrow is another day
                                            ‘see’ you tomorrow.
                                            have a good night.
                                            g

                                            1 Reply Last reply Reply Quote 1

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