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    Perl language syntax highlighting troubles (bug or limitation ?)

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    • EkopalypseE Offline
      Ekopalypse
      last edited by

      No, afaik non-capturing group is (?:pattern)
      This, (?s), just tells the engine that the dot . is matching
      EOLs like \r\n - if I’m right.

      1 Reply Last reply Reply Quote 1
      • EkopalypseE Offline
        Ekopalypse
        last edited by Ekopalypse

        Just for clarification, the python script does NOT use the python regex engine instead
        it uses the one notepad++ offers, the boost::regex.
        Yes, you can use the enumeration without the pipe but makes it more visible for me with
        the pipe sign. Or is there a difference if used with pipe sign or without?

        1 Reply Last reply Reply Quote 1
        • EkopalypseE Offline
          Ekopalypse
          last edited by Ekopalypse

          or maybe this one might be even better
          (?s)(<<)\h+(["'])(\w+?)\2\h*;.*?\3

          1 Reply Last reply Reply Quote 1
          • Gilles MaisonneuveG Offline
            Gilles Maisonneuve
            last edited by

            Can’t reply what I wanted, a robot says I’m spamming…

            Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
            • EkopalypseE Offline
              Ekopalypse @Gilles Maisonneuve
              last edited by

              @Gilles-Maisonneuve

              Can’t reply what I wanted, a robot says I’m spamming…

              I have no idea why this happens sometimes.

              By the way, now that you have installed pythonscript plugin would you mind
              clicking Plugins->Python Script->Scripts->Samples->RegexTester ?

              I know not everyone is recommending it but, personally, I love it.

              1 Reply Last reply Reply Quote 1
              • Gilles MaisonneuveG Offline
                Gilles Maisonneuve @Gilles Maisonneuve
                last edited by

                AFAIK, at least in Perl, ["|'] means double-quote OR pipre OR simple-quote, everything between square brakets is literal. Also true in “awk” and C regexp I think.
                I don’t know for Python.

                Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                • Gilles MaisonneuveG Offline
                  Gilles Maisonneuve @Gilles Maisonneuve
                  last edited by

                  @Ekopalypse

                  Now, if I say in Pyhton (attempt to transliterate from Perl) :

                  (r'(?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)', [2])
                  

                  does it mean :

                  1. form REGEXP
                  2. do not match NL with DOT
                  3. matches any horizontal blanks (0 or more), don’t make a group
                  4. matches ‘<<’ make it a group
                  5. matches any horizontal blanks (0 or more), don’t make a group
                  6. matches 0 or 1 text quote (either double or single), no group
                  7. matches a group of any chars not " nor ’ one or more time(s) (in perl it would be [^"'])
                  8. matches 0 or 1 text quote (either double or single), no group
                  9. possible blanks until semi-colon, semi-colon, then possible chars until NL

                  BUT THEN, what does mean ?\3. I’m lost there.

                  Gilles MaisonneuveG 1 Reply Last reply Reply Quote 0
                  • Gilles MaisonneuveG Offline
                    Gilles Maisonneuve @Gilles Maisonneuve
                    last edited by

                    a slash m

                    EkopalypseE 1 Reply Last reply Reply Quote 0
                    • EkopalypseE Offline
                      Ekopalypse
                      last edited by Ekopalypse

                      the r at the beginning just informs python that this is a raw string and
                      every char must be taken literally otherwise backslashes would be treated
                      as escapes under some circumstances.

                      The regex string is only this part

                      (?s)(\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)
                      

                      and I would say, but as said - not an regex expert at all,

                      (?s) means Dot matches newline characters
                      the first matching group is

                      (\h*(<<)\h*["|']?([^"|^']+?)["|']?\h*;.*?\3)
                      

                      the second

                      (<<)
                      

                      and the third must be

                      ([^"|^']+?)
                      

                      if I’m right.

                      \3 should be the same as $3 in perl

                      Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                      • Gilles MaisonneuveG Offline
                        Gilles Maisonneuve @Ekopalypse
                        last edited by Gilles Maisonneuve

                        @Ekopalypse

                        still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’

                        and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks surrounded by parenthèses only.

                        EkopalypseE 1 Reply Last reply Reply Quote 0
                        • EkopalypseE Offline
                          Ekopalypse @Gilles Maisonneuve
                          last edited by

                          @Gilles-Maisonneuve

                          maybe this picture makes it a little bit clearer

                          1 Reply Last reply Reply Quote 2
                          • EkopalypseE Offline
                            Ekopalypse @Gilles Maisonneuve
                            last edited by Ekopalypse

                            @Gilles-Maisonneuve

                            still confused: ([^"|^']+?) why a ‘?’ after the ‘+’ what’s for this ‘?’

                            as less as possible - non-greedy

                            and then \3 would mean the 3rd matching group (third ‘()’) but in Perl is used only in >subsitutions. What is the use here ? There are only 2 groups in the regex (two blocks >surrounded by parenthèses only.

                            placeholder for what was found in match group 3, to find the EOT at the end

                            and there are 3 match groups or am I missing something??

                            Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                            • Gilles MaisonneuveG Offline
                              Gilles Maisonneuve @Ekopalypse
                              last edited by

                              @Ekopalypse

                              2 sets of parenteses only, where is the third set ?
                              so only 2 match groups

                              can you make this work :

                              no syntax error on the python console but absolutely no result, where is my bug ?

                              regexes[(3, (255,255,255))] = (r'(?s)(\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)', [1])
                              
                              EkopalypseE 1 Reply Last reply Reply Quote 0
                              • EkopalypseE Offline
                                Ekopalypse @Gilles Maisonneuve
                                last edited by Ekopalypse

                                @Gilles-Maisonneuve

                                [1] informs the python script, that only the results from sub match group 1 should be colored in white (255,255,255)
                                sub match group 1 is the result of (<<)

                                In order to make it painting all you can use [0]

                                I’m still confused about the 2 to 3 match groups.
                                Am I incorrect when saying that
                                (\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)
                                (<<)
                                ("{0,1}.+"{0,1})
                                are three match groups?

                                Maybe the confusion comes from the fact that references matches within a
                                regular expression starts by 1 but python starts counting match results by 0.

                                Sorry, but I have to stay up early tomorrow and it is already 1am but I’m really
                                interested in solving our (mis)understanding today later (maybe in ~16-18hours)?

                                1 Reply Last reply Reply Quote 1
                                • Gilles MaisonneuveG Offline
                                  Gilles Maisonneuve
                                  last edited by

                                  ok, tomorrow is another day
                                  ‘see’ you tomorrow.
                                  have a good night.
                                  g

                                  1 Reply Last reply Reply Quote 1
                                  • EkopalypseE Offline
                                    Ekopalypse
                                    last edited by

                                    you too - see you

                                    Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                                    • Gilles MaisonneuveG Offline
                                      Gilles Maisonneuve @Ekopalypse
                                      last edited by

                                      @Ekopalypse

                                      OK, so the

                                      (\s*(<<)\s*("{0,1}.+"{0,1})\s*;.*?\3)
                                      

                                      is a regex group, not a function call surrounded by parenthèses or a logical group provided by the ‘r’ keyword. My mistake.
                                      BUT THEN, it is possible in Python to enclose an instruction such as ?\3 which means (as far as I understood what you explained to me earlier) recursive reference to a regexp named ‘3’) ??? The ‘3’ name being given in the expression regexes[(3, (255,255,255))] is that correct ? SO you can reference an expression within itself while it has not be closed yet: the last parenthese of the expression 3 is after the \3). Is that what it means ?

                                      Python syntax is a bit complicated to me.

                                      Alan KilbornA 1 Reply Last reply Reply Quote 0
                                      • Alan KilbornA Offline
                                        Alan Kilborn @Gilles Maisonneuve
                                        last edited by

                                        @Gilles-Maisonneuve said:

                                        Python syntax is a bit complicated to me

                                        It’s not Python syntax, it’s regular expression syntax. It’s just not Perl regular expression syntax. :)

                                        And, BTW, nobody in the history of the world, especially someone coming from a Perl background, has ever uttered the phrase you typed.

                                        Gilles MaisonneuveG 1 Reply Last reply Reply Quote 1
                                        • guy038G Offline
                                          guy038
                                          last edited by guy038

                                          Hello @gilles-maisonneuve, @eko-palypse and All,

                                          Gilles, could you verify that the two lines, below, work, with yours Red, Green and Blue colors ?

                                          regexes[(3, (R,G,B))] = (r'(?s-i)(<<)(['"]?)(\w+?)\2\h*;.*?\3', [1])
                                          regexes[(4, (R,G,B))] = (r'(?s-i)(<<)\h+('|")(\w+?)\2\h*;.*?\3', [1,3])
                                          

                                          For these two regexes :

                                          • Group 1 = << = double inferior than sign

                                          • Group 2 = ['"]? = an optional single or double quote, for regex id 3

                                          • Group 2 = '|" = a mandatory single or double quote ,separated from the << characters with blank characters, for regex id 4

                                          • Group 3 = \w+? = the shortest area of word characters, after the << sign, between possible quotes
                                            and before a semicolon character ;, with possible blank characters, before and/or after the quote characters

                                          Notes :

                                          • In regex id 3, only the << string is highlighted ( Group 1 )

                                          • In regex id 4, the << and the text between quotes are highlighted ( Groups 1 and 3 )

                                          • I added the -i in-line modifier ( => (?s-i) leading syntax ) to be sure that the ending boundary of the block corresponds exactly with the text, between quotes ( search is sensitive to case ! )


                                          So my regex (?s-i)(<<)(['"]?)(\w+?)\2\h*;.*?\3 ( id 3 ) matches any of these six cases, below :

                                          $x=<<TEXT;
                                          Plain text here
                                          TEXT
                                          
                                          $x=<<'TEXT';
                                          Plain text here
                                          TEXT
                                          
                                          $x=<<"TEXT";
                                          Plain text here
                                          TEXT
                                          
                                          $x=<<TEXT ;
                                          Plain text here
                                          TEXT
                                          
                                          $x=<<'TEXT' ;
                                          Plain text here
                                          TEXT
                                          
                                          $x=<<"TEXT" ;
                                          Plain text here
                                          TEXT
                                          

                                          And my regex (?s-i)(<<)\h+('|")(\w+?)\2\h*;.*?\3 ( id 4 ) matches these 4 cases, below :

                                          $x=<< 'TEXT';
                                          Plain text here
                                          TEXT
                                          
                                          $x=<< "TEXT";
                                          Plain text here
                                          TEXT
                                          
                                          $x=<< 'TEXT' ;
                                          Plain text here
                                          TEXT
                                          
                                          $x=<< "TEXT" ;
                                          Plain text here
                                          TEXT
                                          

                                          Best Regards,

                                          guy038

                                          Gilles MaisonneuveG 2 Replies Last reply Reply Quote 3
                                          • Gilles MaisonneuveG Offline
                                            Gilles Maisonneuve @guy038
                                            last edited by

                                            @guy038

                                            Hello Guy,

                                            Could not make it work, sorry.

                                            I mean:

                                            • added (replaced original ones) in the EnhancePerlLexer.py from Ekopalypse the following lines (according to what you gave me:

                                              regexes[(3, (224,0,0))] = (r’(?s-i)(<<)([‘"]?)(\w+?)\2\h*;.?\3’, [1])
                                              regexes[(4, (0,0,224))] = (r’(?s-i)(<<)\h+('|")(\w+?)\2\h
                                              ;.*?\3’, [1,3])

                                            • saved it and restarted npp

                                            • list itemstill have the same coloring, not working.

                                            BUT, good news:

                                            python console:
                                            Traceback (most recent call last):
                                            File "C:\Users\gm\AppData\Roaming\Notepad++\plugins\Config\PythonScript\scripts\startup.py", line 1, in <module>
                                                import EnhancePerlLexer
                                            File "C:\Users\gm\AppData\Roaming\Notepad++\plugins\Config\PythonScript\scripts\EnhancePerlLexer.py", line 36
                                                regexes[(3, (224,0,0))] = (r'(?s-i)(<<)(['"]?)(\w+?)\2\h*;.*?\3', [1])
                                                                                                                    ^
                                            SyntaxError: EOL while scanning string literal
                                            Python 2.7.15 (v2.7.15:ca079a3ea3, Apr 30 2018, 16:30:26) [MSC v.1500 64 bit (AMD64)]
                                            Initialisation took 110ms
                                            Ready.
                                            

                                            Can you tell me what did I did wrong ?
                                            (When I comment out the two lines I get back a valid coloring for the ‘q*’ syntaxes (yes, forgot to tell you, this had vanished too…)

                                            1 Reply Last reply Reply Quote 1

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