Search for inconsistent line endings with a regex? (part 2)

guy038

I’ll study your last solution, on Monday 18 ( Again, I’m away on a three-day ski trip 😉 )

Best Regards,

guy038

guy038

Hello, @ekopalypse, @alan-kilborn, and All,

Like you proposed, @alan-kilborn, the enhanced script becomes :

check = True

false_EOL = {0:'$[^\r][^\n]',  # Miss the TWO chars \r\n at 'end of line' as editor.getEOLMode() = 0 ( Windows   EOL )
             1:'\n',           # Should be \r                             as editor.getEOLMode() = 1 ( Macintosh EOL )
             2:'\r',           # Should be \n                             as editor.getEOLMode() = 2 ( Unix      EOL )
            }

def check_eol(match):
    global check
    check = False
    line_of_first_mismatch = editor.lineFromPosition(match.span(0)[1])
    notepad.messageBox('Different EOLS detected -- the first inconsistency is on line ' + str(line_of_first_mismatch),'EOL Mismatch', 0)
    user_input = notepad.prompt('Convert all line-endings in file?\r\nIf so, enter 0 for CRLF, 1 for CR, 2 for LF',
        'INCONSISTENT LINE-ENDINGS DETECTED!', editor.getEOLMode())
    if user_input is not None:
        desired_eol_index = int(user_input)
        if 0 <= desired_eol_index <= 2:
            eol_cmd_list = [
                MENUCOMMAND.FORMAT_TODOS,
                MENUCOMMAND.FORMAT_TOMAC,
                MENUCOMMAND.FORMAT_TOUNIX,
            ]
            if desired_eol_index == editor.getEOLMode():
                notepad.menuCommand(eol_cmd_list[(desired_eol_index + 1) % 3])  # change to UNDESIRED line-endings
            notepad.menuCommand(eol_cmd_list[desired_eol_index])                # change to DESIRED   line-endings

editor.research(false_EOL[editor.getEOLMode()],     # regex to search for
                check_eol,                          # function to call if regex match
                0,                                  # re flags
                0,                                  # START of file
                editor.getLength(),                 # END   of file
                1)                                  # count ( at FIRST match )

if check == True:
    notepad.messageBox('All EOLS correct','EOL check', 0)

Now, given this simple text :

This
is
a
little
test
to   
try
if
OK

With Windows (CR LF) in the status bar
With line 4 ending with CR
line 6 ending with 3 spaces + LF
And all the other lines ending with CRLF

When running the script, it said :

Different EOLS detected -- The first inconsistency is on line 6, although it should be on line 4 ending with CR !

Still searching for other oddities :-)

Best Regards,

guy038

Alan Kilborn

@guy038 said :

Different EOLS detected – The first inconsistency is on line 6, although it should be on line 4 ending with CR !

Well… that seems to be because $[^\r][^\n] (when searching from top of file) misses line 4 and matches the LF at the end of line 6 and the t at the start of line 7.

The original regex of \r[^\n]|[^\r]\n seems to work better…

Alan Kilborn

I noticed that other odd things can happen.

Example:

I created a Unix (LF) file and put some lines in it, and then changed one of the line’s endings to CRLF:

The status bar said:

Running the script said:

but it should have said line 3.

Moving to the PS console window and checking the EOL mode, I discovered:

So I seem to have found a case where something is out of sync: Notepad++ 's status bar says LF for line-endings, but the Scintilla buffer says something different (CRLF).

EDIT: I seem to have figured out why: The editorconfig plugin seems to be interfering. I have it set for CRLF for the file in question. However, I’d have thought that this plugin only does things when I save a file, and in the above I’ve not saved the data. Oh, well, (non)problem solved.

Alan Kilborn

This time I’ve found a real bug in the script, and it is with the code I suggested:

Buggy code:

    line_of_first_mismatch = editor.lineFromPosition(match.span(0)[1])
    notepad.messageBox('Different EOLS detected -- the first inconsistency is on line ' + str(line_of_first_mismatch),'EOL Mismatch', 0)

Better code:

    line_of_first_mismatch = editor.lineFromPosition(match.span(0)[0])
    notepad.messageBox('Different EOLS detected -- the first inconsistency is on line ' + str(line_of_first_mismatch + 1),'EOL Mismatch', 0)

guy038

Hello, @ekopalypse, @alan-kilborn and All,

Ah…, OK. I see the problem ! Now, Alan, if you try this script on files with more than 500,000 lines, the regex \r[^\n]|[^\r]\n return an error whereas the regex $[^\r][^\n] works correctly and displays the expected message All EOLS correct

Thus, I decided that this behaviour is of higher importance compared to knowing which is the first mismatched line found ! I, then, changed this script as below :

check = True

false_EOL = {0:'$[^\r][^\n]',  # Miss the TWO chars \r\n at 'end of line' as editor.getEOLMode() = 0 ( Windows   EOL )
             1:'\n',           # Should be \r                             as editor.getEOLMode() = 1 ( Macintosh EOL )
             2:'\r',           # Should be \n                             as editor.getEOLMode() = 2 ( Unix      EOL )
            }

def check_eol(match):
    global check
    check = False
    user_input = notepad.prompt('Convert ALL line-endings of CURRENT file ( 0 for CRLF, 1 for CR, 2 for LF )',
        'INCONSISTENT line-endings DETECTED !', editor.getEOLMode())
    if user_input is not None:
        desired_eol_index = int(user_input)
        if 0 <= desired_eol_index <= 2:
            eol_cmd_list = [
                MENUCOMMAND.FORMAT_TODOS,
                MENUCOMMAND.FORMAT_TOMAC,
                MENUCOMMAND.FORMAT_TOUNIX,
            ]
            if desired_eol_index == editor.getEOLMode():
                notepad.menuCommand(eol_cmd_list[(desired_eol_index + 1) % 3])  # change to UNDESIRED line-endings
            notepad.menuCommand(eol_cmd_list[desired_eol_index])                # change to DESIRED   line-endings

editor.research(false_EOL[editor.getEOLMode()],     # regex to search for
                check_eol,                          # function to call if regex match
                0,                                  # re flags
                0,                                  # START of file
                editor.getLength(),                 # END   of file
                1)                                  # count ( at FIRST match )

if check == True:
    notepad.messageBox('All EOLS correct','EOL check', 0)

Do note that it’s my own preference, only !

Best Regards,

guy038

P.S. :

In the meantime, I saw that you"ve done testing a lot ! Thanks for your tests but, as you can see, I solved the problem definitively ;-))

Alan Kilborn

@guy038 said :

whereas the regex $[^\r][^\n] works correctly

Try it on a Windows (CR LF) file and this data:

That regex doesn’t hit anything in that text.

I solved the problem definitively

Hmm. :-)

guy038

Hi, @ekopalypse, @alan-kilborn and All,

I deeply apologize, because my regex to find out all wrong cases, in case of a Windows file, was itself bugged !

You were right about it, Alan. The correct regex is $\n|\r^ leading to the line :

false_EOL = {0:'$\n|\r^',  # Find \n AFTER end of line OR \r BEFORE beginning of line as editor.getEOLMode() = 0 ( Windows   EOL )

This time, results are coherent, even for large files !

BR

guy038

guy038

Hello, @ekopalypse, @alan-kilborn and All,

I did some additional tests, with your modifications, Alan :

    line_of_first_mismatch = editor.lineFromPosition(match.span(0)[0])
    notepad.messageBox('Different EOLS detected -- the first inconsistency is on line ' + str(line_of_first_mismatch + 1),'EOL Mismatch', 0)

and my own one :

false_EOL = {0:'$\n|\r^',  # Find \n AFTER end of line OR \r BEFORE beginning of line as editor.getEOLMode() = 0 ( Windows   EOL )

And everything seems to work as expected !

So the final version of this script is :

check = True

false_EOL = {0:'$\n|\r^',  # Find \n AFTER end of line OR \r BEFORE beginning of line as editor.getEOLMode() = 0 ( Windows   EOL )
             1:'\n',       # Find \n ( should be \r )                                 as editor.getEOLMode() = 1 ( Macintosh EOL )
             2:'\r',       # Find \r ( should be \n )                                 as editor.getEOLMode() = 2 ( Unix      EOL )
            }

def check_eol(match):
    global check
    check = False
    line_of_first_mismatch = editor.lineFromPosition(match.span(0)[0])
    notepad.messageBox('Different EOLS detected -- the first inconsistency is on line ' + str(line_of_first_mismatch + 1),'EOL Mismatch', 0)
    user_input = notepad.prompt('Convert ALL line-endings of CURRENT file ( 0 for CRLF, 1 for CR, 2 for LF )',
        'INCONSISTENT line-endings DETECTED !', editor.getEOLMode())
    if user_input is not None:
        desired_eol_index = int(user_input)
        if 0 <= desired_eol_index <= 2:
            eol_cmd_list = [
                MENUCOMMAND.FORMAT_TODOS,
                MENUCOMMAND.FORMAT_TOMAC,
                MENUCOMMAND.FORMAT_TOUNIX,
            ]
            if desired_eol_index == editor.getEOLMode():
                notepad.menuCommand(eol_cmd_list[(desired_eol_index + 1) % 3])  # change to UNDESIRED line-endings
            notepad.menuCommand(eol_cmd_list[desired_eol_index])                # change to DESIRED   line-endings

editor.research(false_EOL[editor.getEOLMode()],     # regex to search for
                check_eol,                          # function to call if regex match
                0,                                  # re flags
                0,                                  # START of file
                editor.getLength(),                 # END   of file
                1)                                  # count ( at FIRST match )

if check == True:
    notepad.messageBox('All EOLS correct','EOL check', 0)

To be rigorous, note that the first EOL inconsistency is always the first line with line-ending chars(s) different from the status bar indication !

Best Regards,

guy038