convert lower to upper and upper to lower aftert colon

[PeterJones]

FYI:

The official docs have a section on substitution regex, but the conditional replacements were not explained: https://npp-user-manual.org/docs/searching/#substitutions

The most recent update to the documentation github has more details on that; it will be in the next release to the doc website (whenever that occurs): https://github.com/notepad-plus-plus/npp-usermanual/blob/852b4ac8a2e667be027d3f7db0a04cfeb2d71eca/content/docs/searching.md#substitution-conditionals

[real_1bx]

@PeterJones said in convert lower to upper and upper to lower aftert colon:

If I am understanding the logic, you want colon-lowercase to become colon-uppercase, and colon-uppercase to become colon-lowercase, and everything after that to be made lowercase, right? If so, then I think this will work for you:

Thank you very much, i really do appropriate taking time to help me out.
the logic is i want colon-lowercase to become colon-uppercase, and colon-uppercase to become colon-lowercase but everything after that stay the same i don’t want change it.

[guy038]

Hello @real_1bx and All,

You need to distinguish an uppercase letter from a lowercase letter !

So, I think that the following regex S/R should work !

SEARCH (?-is):(([A-Z])|[a-z])(.+)

REPLACE :(?2\l:\u)\1\L\3

For instance, the text :

john:abC232
smith:SnLf1999

is changed into :

john:Abc232
smith:snlf1999

---

Notes :

• First, the in-line modifiers (?-is) means that :

  • The search will be carried on, in a non-insensitive way ( -i )

  • Any regex dot symbol matches a single standard character only ( and not line-break chars )

• Groups involved in the search regex are :

  • Group 1 = ([A-Z])|[a-z], so the first letter after the : char, which may be, either a lower-case or an upper-case letter

  • Group 2 = [A-Z], so the first upper-case letter after the :

  • Group 3 = .+, so all the remaining characters of current line, after the : and a first letter

• In the replacement regex :

  • : rewrites the colon, first

  • Then, the (?2\l:\u) syntax is a conditional structure which forces the next character to be written :

    • In lower case if group 2 exists, that is to say if an upper case letter has matched

    • In upper case if group 2 does not exist => a lower case letter has matched

  • \1 is the first letter whose case has been modified

  • Finally, \L\3 rewrites all the remaining characters, of current line, in lower-case

• Note that I do not use the look-behind structure (?<=:) which enable us to use the step by step replacement with repeated hits on the Replace button

Best Regards,

guy038

@peterjones said :

I am surprised @guy038 hadn’t chimed in already, since he was around a few minutes ago.

Well, I was chatting for a moment with my son who’s going back to Lyon ;-)

[PeterJones]

@real_1bx said in convert lower to upper and upper to lower aftert colon:

Thank you very much, i really do appropriate taking time to help me out.
the logic is i want colon-lowercase to become colon-uppercase, and colon-uppercase to become colon-lowercase but everything after that stay the same i don’t want change it.

Ahh, your \L confused me to thinking you wanted the rest lowercase.

Just get rid of the third group in find and replace should do it:

FIND = (?-is)(?<=:)(?:([a-z])|([A-Z]))
REPLACE = (?1\u$1)(?2\l$2)
MODE = regular expression

[guy038]

Hi, @real_1bx, @peterjones and All,

So, I did the same mistake as Peter !

Thus, my regex S/R should be modified as :

SEARCH (?-i):(([A-Z])|[a-z])

REPLACE :(?2\l:\u)\1

Cheers,

guy038

[guy038]

@real_1bx, @peterjones and All,

Last news : we don’t even need an outer group to capture the letter ! So, why not this attempt :

SEARCH (?-i)(:[A-Z])|:[a-z]

REPLACE (?1\L:\U)$0

---

So the following text :

john:abC232
smith:SnLf1999

becomes :

john:AbC232
smith:snLf1999

BR,

guy038

[real_1bx]

@guy038
Thank you very much , that’s saved me a LOT of time.

[guy038]

Hello @real_1bx,

I hope that you noticed why I use, this time, the (?1\L:\U)$0 syntax ( and not (?1\l:\u)$0 ), in replacement ?

Just because the string to convert in upper / lower case ( $0 ) is two chars long ( a colon : + a letter ) !

BR

guy038

[real_1bx]

@guy038 is it possible to delete whole line if there is number after the :
i mean the first character after colon not the whole word.
like

abc:fkls
john:13kkmsd
smith:kmskl
```
**to be**

```
abc:fkls
smith:kmskl
```

[guy038]

Hi, @real_1bx, and All,

This time, due to the simultaneous search of an entire line, with its line-break, when a digit follows the colon char, we need, again, two groups, leading up to that regex S/R :

SEARCH (?-is)^.+:\d.+\R|((:[A-Z])|:[a-z])

REPLACE ?1(?2\L:\U)\1

For instance, the input text, below :

john:abC232
john:13kkmsd
smith:SnLf1999

would be modified as :

john:AbC232
smith:snLf1999

Best regards,

guy038