How to replace a line, which has a specific text, with the content of a specific line?
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@Terry-R Yes, “name” “noname” appears only once in each file.
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I think I have it. I assume that given each line is prefixed by a number that you don’t want line 16 (as in your example) suddenly be changed to “06” just because the contents of line 06 are copied to line 16.
So my regex (which should also work in the “Find in Files” option is
Find What:(?-s)^(((.+)?\R){5})(\d+)(.+\R)(?s)(.+?)(?-s)^((\d+).+"name": "noname".+\R)(?s)(.+)
Replace With:\1\4\5\6\8\5\9
You will see I flip between (?-s) and (?s) several times. This allows the regex to traverse several lines simply in between line 06 and line we need to replace. I then continue to the end of the file, so in essence this regex will process the whole file, rewriting the entire contents back with the small change of line 06 written to where the original text needing replacement was.
It worked for me in your example in an open tab. I’d suggest make a backup copy of the 300 or so files before unleashing it on all of them, then randonly checking some against the original contents.
Terry
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@Terry-R Thank you Terry! I tested it here and it worked. Editing these files will be much easier now. But what would the regex look like if the lines didn’t have prefix numbers
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@Yudi_Kondo said in How to replace a line, which has a specific text, with the content of a specific line?:
But what would the regex look like if the lines didn’t have prefix numbers
The 2
(\d+)
get removed, however this would then change the number of groups being stored so in the replacement line there would be lots of changes. My head hurts from the number of groups I had to create in the solution so I’m all THUNKED out currently! Do you really need that as a solution as you’ve just said that my solution already provided did work?!Actually, here’s an opportunity for you to test it out yourself. See what each group (
\1, \2 etc)
in the Replace With field relates to in the Find What field. Then remove the 2(\d+)
as I stated. Then change the group numbers in the Replace With field and see if you can get the correct answer. test it on some dummy data. A big hint is. Start counting left brackets(
ONLY. This is what determines the group number. Don’t count the brackets for the ?-s and ?s.Terry
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@Terry-R I just asked out of curiosity in case I needed something similar in the future. Thanks again Terry!
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Here the regex without the 2 (\d+)
(?-s)^(((.+)?\R){5})(.+\R)(?s)(.+?)(?-s)^(.+“name”: “noname”.+\R)(?s)(.+)
\1\4\5\4\7
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You are right, however if you copy back what shows on your post it probably won’t work. I think the quotes have been nobbled by the markdown interpreter. We have all suffered from this issue and one way to resolve it is to put special characters around the code so the interpreter does NOT alter the characters at all.
In the same way as you provided your 2nd example and I provided my regex, these can prevent the problem. Just inserting the code as you would text (as you did above) has (according to my test) affected the code.
But good on you for trying it out. I got my code and removed the 2
(\d+)
bits as I stated and then used your\1\4\5\4\7
and got the answer for when your file does NOT include line numbers.Terry
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It can be like that?
^(((.+)\R){5})(\d+)(.+\R)(?s)(.+)(?-s)^(..)(.+“name”: “noname”.+\R)(?s)(.+)
\1\4\5\6\7\5\9Here I learn from the best.
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@Pan-Jan said in How to replace a line, which has a specific text, with the content of a specific line?:
It can be like that?
You are welcome to submit your proposed solution but I strongly suggest you need to insert those regexes within special codes so the markdown interpreter (the window you type the response in) does not adjust any characters that you type.
You will note that my regex was in red text. This can be achieved by using the ` (grave accent character) around the regex. This key is generally top left on a full US keyboard, on the same key as the tilde character (~).
The OP supplied their updated version without the (\d+) groups just as text, much like you and it was affected.Mine: (?-s)^(((.+)?\R){5})(\d+)(.+\R)(?s)(.+?)(?-s)^((\d+).+"name": "noname".+\R)(?s)(.+) Theirs: (?-s)^(((.+)?\R){5})(.+\R)(?s)(.+?)(?-s)^(.+“name”: “noname”.+\R)(?s)(.+)
Look closely at the quotes in each regex, notice any difference? This is one of many changes that can occur if you don’t add the codes around text you do NOT want altered.
Also, once typing a response in the window, you have other commands available. You should see a
</>
button above the window, select this first when entering code text, note this is what I did above rather than use the grave character. It is also useful for when inserting example text so that others may copy the data “unchanged”.Terry
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Nobody uses such quotation marks here
“name”: “noname”
`red`
red
Red doesn’t work everywhere -
It seems that you feel offended when someone gives you an well-intentioned advice.
Why is that?
If I copy your regex solution, I get, for example“name”
instead of"name"
and thus your solution is corrupted.
If, as @TerryR recommends, you wrap your solution in ` or use a code tag, this will not happen.
What is the problem here? -
@Ekopalypse
Don’t overdo it.
I don’t feel offended at all.
This is due to the short texts, but it is best to translate them.Only such quotation marks are correct
"name": "noname"
If I copy
I’ll get
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@Pan-Jan said in How to replace a line, which has a specific text, with the content of a specific line?:
Only such quotation marks are correct
First, that’s false. It is perfectly reasonable for a question to include literal curly-quotes / smart-quotes in the question and/or answer.
But moving on to your general thought, which seems to be “people usually don’t have text with curly quotes, so everyone – whether the person asking the question or the person answering – should somehow know that they need to mentally convert curly quotes into ASCII quotes”:
let’s try out a couple scenarios. There will be three people in these scenarios: @QuestionAsker, @NoRedAnswer, and @YesRedAnswer.
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scenario 1, with @NoRedAnswer
@QuestionAsker says:
I have text, and want to strip out anything that’s inside quotes with no spaces:
This will remove quotes: "NoSpaces" This will keep quotes: "This has spaces"
After running search-and-replace, I want
This will remove quotes: NoSpaces This will keep quotes: "This has spaces"
@NoRedAnswer replies:
Use the search term “(\w*)” and replace with $1
@QuestionAsker says:
Sorry, that didn’t work. I tried both
(\w*)
like you said, and tried“(\w*)”
, but neither of them changed my text any.The @QuestionAsker didn’t understand the answer, because @NoRedAnswer didn’t format the answer using the forum’s formatting tools. This caused confusion and delay.
scenario 2: same circumstance, but @YesRedAnswer
@QuestionAsker says:
I have text, and want to strip out anything that’s inside quotes with no spaces:
This will remove quotes: "NoSpaces" This will keep quotes: "This has spaces"
After running search-and-replace, I want
This will remove quotes: NoSpaces This will keep quotes: "This has spaces"
@YesRedAnswer replies:
Use the search term
"(\w*)"
and replace with$1
, with Search Mode set to regular expression@QuestionAsker says:
Great, @YesRedAnswer! That worked on the first try! Thanks for your help. ++@YesRedAnswer
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As you should be able to see, the answer that did use
red text
for the regular expression was much more helpful, even though both people who answered came up with the same working regex.In the end, it’s your choice how to answer (or ask) questions in this forum. But you can choose to (1) make it easier for the others to understand you, or you can choose to (2) skip the red text and black text boxes, and make the person you’re helping (or the person you’re asking) try to figure out what you really meant, and probably get it wrong. We are just advising that you use style (1) rather than (2).
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Got it … don’t put patterns in quotation marks
Only such quotation marks are correct “”
If necessary, use only such quotation marks “”But there is something I don’t understand.
Maybe it’s the translation’s fault.“in quotation marks”
I get it this way … you should remove the quotes:
"ABC"
and will be:
""
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@Pan-Jan said in How to replace a line, which has a specific text, with the content of a specific line?:
Got it … don’t put patterns in quotation marks
Unfortunately, you completely misunderstood. It appears the language barrier is too big.
I will say it one more time. I will try to use short sentences. Hopefully your translator will understand.
- Put regex inside ` marks to make them red. This makes regex display as literal characters for the forum, without being edited.
- My example had quote marks as part of the regex, which is valid.
- Always use the quote marks you mean.
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@Yudi_Kondo said in How to replace a line, which has a specific text, with the content of a specific line?:
@Terry-R Ok. There are 300 files that need to be modified and lines with the text “name”: “noname”, always appear after line 6.
Here one of the files:
01{ 02 "id": "Abomasnow", 03 "spawnInfos": [ 04 { 05 "spec": { 06 "name": "Abomasnow", 07 "growth": 6 08 }, 09 "minLevel": 40, 10 "maxLevel": 45, 11 "typeID": "pokemon", 12 "rarity": 8.0 13 }, 14 { 15 "spec": { 16 "name": "noname", 17 "growth": 6 18 }, 19 "stringLocationTypes": [ 20 "Land" 21 ], 22 "minLevel": 50, 23 "maxLevel": 50, 24 "typeID": "pokemon", 25 "tags": [ 26 "safari" 27 ], 28 "rarity": 120.0 29 }
Here line 16 would become line 06
And as for the solution that switched the lines, I was wrong. I used a macro the last time I edited these files
you cannot add pokemon add according to these rules
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To replace a line, which has a specific text, with the content of a specific line:
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Open your document in Microsoft Word
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Select the paragraph that you want to replace with another text
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Under the Home tab, click on the Replace tab
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Type in the text that you want to replace, and then click on Search button
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Click on Replace All button to replace all occurrences of your text with the new one
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Hello, @yudi_kondo, @terry-r and All,
@yudi_kondo, I’m back to your initial question :
I need all lines that have the text : “name”: “noname”,
to be replaced by the contents of line 6
Then, assuming that exists only
1
string"noname"
per file and given the INPUT text below :01{ 02 "id": "Abomasnow", 03 "spawnInfos": [ 04 { 05 "spec": { 06 "name": "Abomasnow", 07 "growth": 6 08 }, 09 "minLevel": 40, 10 "maxLevel": 45, 11 "typeID": "pokemon", 12 "rarity": 8.0 13 }, 14 { 15 "spec": { 16 "name": "noname", 17 "growth": 6 18 }, 19 "stringLocationTypes": [ 20 "Land" 21 ], 22 "minLevel": 50, 23 "maxLevel": 50, 24 "typeID": "pokemon", 25 "tags": [ 26 "safari" 27 ], 28 "rarity": 120.0 29 }
I think that this more simple regex S/R is enough to perform the goal :
SEARCH
(?-is)\A((?:.+\R){5}\d+(.+\R))((?:.+\R)+\d+).+"noname".+\R
REPLACE
\1\3\2
You should be left with this OUTPUT text :
01{ 02 "id": "Abomasnow", 03 "spawnInfos": [ 04 { 05 "spec": { 06 "name": "Abomasnow", 07 "growth": 6 08 }, 09 "minLevel": 40, 10 "maxLevel": 45, 11 "typeID": "pokemon", 12 "rarity": 8.0 13 }, 14 { 15 "spec": { 16 "name": "Abomasnow", 17 "growth": 6 18 }, 19 "stringLocationTypes": [ 20 "Land" 21 ], 22 "minLevel": 50, 23 "maxLevel": 50, 24 "typeID": "pokemon", 25 "tags": [ 26 "safari" 27 ], 28 "rarity": 120.0 29 }
Where only the line
16
is changed from :16 "name": "noname",
to :
16 "name": "Abomasnow",
In order to fully understand my regex S/R, here is the free-spacing version, using the
(?x)
in-line modifier :(?x-is) # FREE-SPACING mode and DOT match STANDARD characters ONLY \A # From BEGINNING of CURRENT file ( # BEGINING of group 1 ( Lines 1 to 6 ) (?: .+ \R){5} # First NON-CAPTURING group ( Lines 1 to 5 ) \d+ # BEGINNING of line 06 ( Number ) ( .+\R ) # Group 2 ( REMAINDER of the line 06 with its LINE-BREAK ) ) # End of group 1 ( # BEGINNING of group 3 (?: .+\R )+ \d+ # Second NON-CAPTURING group ( ENTIRE Lines 07 to 15 + BEGINNING of line 16 or any OTHER line ) ) # END of group 3 .+ "noname" .+ \R # Remainder of line 16, containing the string "noname", with that CASE or any OTHER line
In case that there’s no leading numbers, my regex S/R becomes :
SEARCH
(?-is)\A((?:.+\R){5}(.+\R))((?:.+\R)+).+"noname".+\R
REPLACE
\1\3\2
or, in free-spacing mode :
(?x-is) # FREE-SPACING mode and DOT match STANDARD characters ONLY \A # From BEGINNING of CURRENT file ( # BEGINING of group 1 ( Lines 1 to 6 ) (?: .+ \R){5} # First NON-CAPTURING group ( Lines 1 to 5 ) ( .+\R ) # Group 2 ( Line 06 with its LINE-BREAK ) ) # End of group 1 ( # BEGINNING of group 3 (?: .+\R )+ # Second NON-CAPTURING group (ENTIRE Lines 07 to 15 ) ) # END of group 3 .+ "noname" .+ \R # line 16, containing the string "noname", with that CASE or any OTHER line
Best Regards,
guy038