Find&replace, RegEx, \10
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I want to find&replace using regular expression.
If I put (something) in find and then \number to replace then the text in the bracket won’t be changed. I have 14 brackets in a single command. And when I write \10 to the replace, it return the first bracket and a zero, rather than the stuff in the 10th bracket. -
If I correctly understood your question, just enclose it in brackets, as in
\{10}.Take care and have fun!
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@astrosofista said in Find&replace, RegEx, \10:
\{10}I don’t think that syntax works??
But this syntax ALWAYS works, in replace:
${1}<-- for group 1
${2}<-- for group 2
…
${N}<-- for group NThus for OP’s specific problem and example -->
${10}in replace field should work. -
I neglected to mention the “group 0” match, which has the same syntax format as the ones I DID mention:
If you happen to need to refer to ALL of the matched text, you can use
${0}to refer to it. -
Yes, my bad, ${10} is the thing.
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The answers you have received are good.
If you would like more documentation on this, the official Notepad++ docs talk about the substitution expressions here.
Notepad++ uses what’s known as the “Boost engine” (currently v1.70) for handling the regular expressions, and that has its substitution documentation here
