Regex: Find all between strings. Select everything that is extra after `html` on the same line

[Robin Cruise]

hi, I have this strange situation. I have a lots of line that contain links that ends with html But in some cases, I have some lines that contain more than a simple link.

the-book-is-here.html
yes-I-love-you.html
                 contact.html
                 continuation-of-the-last-harmony.html"><img src="frrr/flag_lsd_en.jpg" title="en" alt="en" width="28" height="19" /></a>&nbsp; create-a-beautiful-team.html
                 create-a-new-vision-of-the-art-down.html
                 the-cat-i-like-here.html
                 important-dates-here.html

The output should be

"><img src="frrr/flag_lsd_en.jpg" title="en" alt="en" width="28" height="19" /></a>&nbsp;

So I must select everything that is extra after html on the same line.

I try this regex, but are not good:

FIND: (html)(.*?)(html)$
REPLACE BY: \2

[guy038]

Hello, @robin-cruise and All,

Try this regex S/R :

SEARCH (?-s)\.html.+</a>&nbsp;\K.+html$

REPLACE Leave EMPTY

---

Or, may be, this more simple one :

SEARCH (?-s)\.html.+\K\x20.+html$

REPLACE Leave EMPTY

BR

guy038

[Robin Cruise]

This post is deleted!

[Robin Cruise]

thank you @guy038 but I wanted to select something else. The regex should select exactly this line, that is framed by html tag

"><img src="frrr/flag_lsd_en.jpg" title="en" alt="en" width="28" height="19" /></a>&nbsp;

[Robin Cruise]

SEARCH: (")(.*?;)(.*?)\s+
REPLACE BY: \1\r

OR

SEARCH: (")(.*?;)(.*?)\s+
REPLACE BY: \1\r\t\t\t\t\t