RegEx: Split each number of a string inside curly brackets into a separate line, add a prefix to it & remove all unnecessary data
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Thank you for the reply, Sir! I am sorry for forgetting about the markup, will fix it soon after this!
However, I think you didn’t have to be rude-ish to me, especially because judging by your reply, it is merely because of overlooking one (though important) markup. This is the first time I am posting here, and this forum is new to me. Despite the effort I put into this, I couldn’t possibly remember everything at once, especially the specific markup preferred here and with my current exhaustion. This is why editing exist - so I can fix such blunders :)
You used a lot of markdown formatting in your post… but where it really mattered (using the
</>
toolbar button or the raw ``` markdown code to indicate the start and end of your example data), you didn’t use markdown, so we cannot be sure of the data you actually have. That makes it really hard to help you.I’m sorry for missing / forgetting about the markup - thank you for noting! It would indeed stand out better with that. I will fix it right away!
Please, let me know if there will still be something weird in the layout!As much as I like Notepad++, if this is database data, wouldn’t it be best to fix the data using the database routines which are optimized for editing the database data? Or fixing the report generator template to make the text output report the way you want it?
I am well aware of that route. However, due to certain reasons those cannot be altered, edited or otherwise in any way. It is that way for its own specific purposes, while my part is to convert all that data into a human-readable database. Technically, one could create a program in python or similar to do the parsing. However, I am not a programmer, so I don’t know how to do that… and I think it probably still requires RegEx.
Also, so far, Notepad++ and its powerful RegEx has served the purpose perfectly well.
Also, among dozens of RegEx edits on these files, as far as I know, this is the only step that I couldn’t overcome with RegEx on my own. Therefore, I thought it would be a waste not to try to solve it this way, or at least find out if it would be possible in the first place. Perhaps, I may have simply overlooked something simple that a RegEx guru would do right away? I don’t know. That’s why I thought I should ask here, where are many who know RegEx much better than I do.
Anyway, until you can mark your data better, and follow the advice that I will put below the horizontal line, I wouldn’t want to even take a stab at an answer yet.
…
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Apparently, I am only allowed to edit for three minutes after posting, so I cannot edit the original post… Let me know if I should start a new topic/thread and discard this one entirely. For now, below is the original post with fixed markup and some edits. Sorry for messing up the markup!
Hello everyone!
I need help with annoyingly tricky RegEx that I just can’t figure out! Maybe there is no solution after all? The nearly complete lack of any pattern is a huge problem for this RegEx. I have been racking my brain for hours on this, testing countless approaches but my skills simply aren’t enough for this… so I would really appreciate any help you can provide! In advance, many, many thanks for any help!
Anyway, I have a huge database of dozens of files, each containing typically millions of lines, and dozens of parameters with varying types of headers and values. Therefore, manual fixing is not viable. There is a specific set of parameters with either whole or decimal numbers enclosed with curly brackets. And only these enclosed numbers together with the parameter headers needs attention.
The following statements - mostly bad news - are true for these strings:
- May be found anywhere under the root
- The pattern is always header={ N N }, originally indented but this RegEx can be done after removing the tabs
- The are several headers and they are typically in lower case, though a few exceptions exist but case sensitivity is not necessary – RegEx
\w+
covers all of them - There may be any amount of these numbers: there is always at least one but may be up to several dozens
- Each number may be of varying length, typically anywhere between 1 and 1000000000 (1E+09)
- All numbers are positive
- Almost all of them are whole numbers but there are a couple cases where decimal numbers appear, typically in precision of 3 or 4 decimals… There is no pattern when and where they appear, so, ideally, our numbers should carry the structure of
(\d+.?\d+?)
in any case - Numbers are always separated with a regular space
- The equal sign = and curly brackets { } should account for possible spacing errors with
\h*
- Many other parameters have numbers but they are not enclosed with any brackets
The exact matter is classified so I have randomized a dummy example for you. All parameters with curly brackets must be fixed.
Please, note that in reality all these parameters are mixed and in any order, so they are not in separate sections like below. I just wanted to highlight them here so that it’s easier to see what needs to be done!82={ # This is the root, used for each main entry. All parameters are placed under it. In this case, these are safe to ignore. ### The section below has parameters which need our attention to be fixed with RegEx ### xx={ 16835961 } yyyy={ 16847062 67151971 74997 50388451 72836 83934207 50362874 16845543 81456 81771 67136455 33623075 16849442 100696613 82574 83286 83577 16852101 84199 33607712 } zzz={ 79199 16848761 83893799 70029 76217 16854401 16839 16853836 50370644 145057 79338 81773 16849133 83891875 } www={ 100693891 72513 16844226 33606062 16854968 16858108 33608429 16845608 67128408 33611952 50382602 67148972 67149505 50368894 78657 134238974 67119739 50362812 16833431 16852778 50353593 50378671 50383395 50386109 67120625 67126402 67136958 67145067 67145907 67151704 67158147 83897335 83898254 83921034 83921077 83927103 100681910 100691733 117474361 } pppp={ 50350929 168.36935 33589252 } rrrrr={ 322 482.865 } ### Other stuff in the file looks like this ### info_about_this=blah header=85095 Header=words_with_underlines date=1938.08.22 that=2437 dummy=funny }
Because of these irregularities, combined with certain similarities with other parameters, all RegEx should be ideally done in one go… unless there is a foolproof solution with multiple steps that will not alter other parameters.
TO DO
These strings of numbers must be parsed so that I can further process them. The following list explains the end result I need.- Separate line for each number
- Header captured to be included before each number, i.e. 01234 → header=01234
- Any in-line (white)spaces should be removed, including the ones before & after numbers and brackets
- The curly brackets are redundant so, ideally, they should be removed - I only need the headers and numbers
- Everything beyond these strings should be kept intact - any changes will cause errors!
The final product of the above dummy should look like the one below. Please, ignore the lines with “etc” - there are so many values that it’s best to abbreviate.
100={ xx=16835961 yyyy=16847062 yyyy=74997 yyyy=50388451 yyyy=728 yyyy=83934207 # etc... zzz= zzz=79199 zzz=16854401 zzz=16839 # etc... pppp= pppp=50350929 pppp=168.36935 pppp=33589252 # etc... info_about_this=blah header=85095 Header=words_with_underlines date=1938.08.22 that=2437 dummy=funny }
Thank you for your time and patience! Any help would be incredibly helpful!
Have a nice day! -
@Grimaldas-Grydas said in RegEx: Split each number of a string inside curly brackets into a separate line, add a prefix to it & remove all unnecessary data:
However, I think you didn’t have to be rude-ish to me, especially because judging by your reply, it is merely because of overlooking one (though important) markup.
Sorry, I was not intending to be rude. I cannot hazard a guess at a regex that might work, because your examples don’t show indenting, and your explanation implies there is indentation; if we cannot see where it is, our solutions will likely not work if our guess at indentation doesn’t match yours.
I see that while I was typing up this reply, you re-posted the data. Thank you.
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Thank you for your help this far, anyway! Any responses and comments are always welcome and valuable!
Concerning indentation, I had no idea it was of any importance in this case! So far, all RegEx I needed for these files could either safely ignore them entirely or could be simply marked with
\h*
or\h+
, occasionally augmented with^
when beginning was necessary for the code.The indentation here is really simple, however. The root entry (82={} in this case) is at level 0, on the margin. Most entries for this case are one TAB in, and a couple rare ones are two TABs in. I thought I could simply add these into the code myself after figuring out how to solve the main issue.
The end result should have no indentation, so most steps for these files involve methodical removal of any differing “layout”. The end result should be basically as plain as .csv, or .json or similar data typically is.
I feel it’s not necessary knowledge for this matter, and due to classified information, I cannot tell anything specific… but as mentioned before, I am further processing this into something human-readable. My methods vary from one case to another, but most can be done with a program like Excel, where information can be easily databased, modified with formulae etc.
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There are a couple more things worth mentioning
I have tested numerous ways, back and forth, including with tester like regex101. The problem appears to be that I’m terrible with lookups and conditionals, so I just cannot wrap my mind around a possible solution. I also have a feeling that the entire process may be impossible with Notepad++ RegEx but some parts could be done. This is why I sought for help in the first place - many of you are far more skilled and may actually know of a solution!
The original post is complex - I wanted to include all possible information there. However, what needs to be done, is really simple:
- We have a string, like header={ 01 0345 0647889 0887 }
- We need to capture the part header=
- Each number inside brackets (in this case: 01, 0345, 0647889 and 0887), needs to be split into a separate line
- End result should omit all brackets and spaces
- One of many lines of the end result should look like header=0345
So far, I have a partial solution. I can easily split numbers into separate lines with SEARCH
\h+(\d+\.*\d*)
& REPLACE\r\n$1
. However, this solution is vulnerable to errors because many other parameters have similar numbers as well. The original matter has spaces as well but I have done this at later stage so that only these have spaces. There are literally thousands of these parameters, and exponentially more with the numbers split, so doing this manually is prone to errors and practically not viable.However, this still ignores the brackets, which are the most crucial “identifier” of this case, and the numbers lack a header, which would be imperative to include as there are several parameters using similar numbers. This is why I am asking for help. I would like to know if it would be possible to do the whole process described. English is not my first language (it’s Finnish), so it’s a little difficult to explain this properly…
It would be piece of cake if the numbers were of regular length, there was a fixed amount of numbers or there was a clear pattern overall. The real difficulty is in this irregularity, as numerous variations must be taken into account… I tried solutions like SEARCH
\h+(?:(\w+)\h*=\h*{)\(?:\h+(\d+\.*\d*))
→ REPLACE$1=$2
but this only matches the first number out of many, instead of matching all numbers until the closing curly bracket.In any case, I am sorry for bothering you all.
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You may have to be patient. I’m pretty busy right now, so cannot look into it. But there are other regex experts who usually visit at least once per day. Hopefully, one of them will be able to look into it.
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@Grimaldas-Grydas said in RegEx: Split each number of a string inside curly brackets into a separate line, add a prefix to it & remove all unnecessary data:
Because of all these irregularities, combined with certain similarities with other parameters, all RegEx should be done preferably in one go… unless there is a foolproof solution with multiple steps that will not alter other parameters.
I can’t see how it’s possible to do it with 1 regex. The primary issue is when processing the numbers inside the
{}
you cannot look behind with a variable length to find thexxx=
to copy ahead for the next number found. So instead I think 2 regex will suffice. The first moves thexxx=
to the end of the line as the look ahead can be of variable length. The second regex then completes the transformation.So the first regex to move the header to end of line (and remove indentation?) is:
Find What:(?-s)^\h*(\w+=)(\{.+\})
Replace With:\2\1
The second regex will now copy the header by looking forward and capturing it for each number it encounters and rewrites that as a separate line. When it cannot find any more numbers on the line it will instead find the
}xxx=
sequence which it promptly deletes along with the line break. So we have
Find What:(?-s)(?:\{?\h*)?(\d+(?:\.\d+)?)(?=[^}\r\n]+}(\w+=))|\h*\}\w+=\R
Replace With:(?1\2\1\r\n)
Please note that although I included(?-s)
in the second regex it is in fact redundant as there are no.
references made. It is something I strive to do when starting to compile a solution and sometimes I just leave it there even if not needed.Now this definitely works (tested) with the small (non-indented) sample you provided in your 3rd posting, however since you made reference to possible indentation it is likely you may still need to change my regex. Note my first regex does attempt to remove the indentation, but I will leave it up to you if that’s successful before applying the second regex.
Given the complexity of your data and issues around other lines that
look similar
this may not be the final solution, but rather a work in progress. Please do come back to us with theedge cases
as @PeterJones mentions. His italicised text at the bottom of his first post here contains very important information.Terry
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@Grimaldas-Grydas said in RegEx: Split each number of a string inside curly brackets into a separate line, add a prefix to it & remove all unnecessary data:
I think you didn’t have to be rude-ish to me,
Hmm, I read it over and I didn’t see even a hint of rude-ish-ness in what Peter said. Maybe he was “direct” but certainly in no way “rude”.
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Hello, @grimaldas-grydas, @peterjones, @terry-r, @alan-kilborn and All,
Here is my solution : A single regex S/R will be enough, but you’ll need to click twice on the
Replace All
button !I also had to use a temporary character, absent in all your data ! I chose the
¤
character, present on my French keyboard. But you may adopt any simple character which is not present in your current file, as for instance,@
,&
,%
,§
, … :-)So if we consider your INPUT text :
82={ # This is the root, used for each main entry. All parameters are placed under it. In this case, these are safe to ignore. ### The section below has parameters which need our attention to be fixed with RegEx ### xx={ 16835961 } yyyy={ 16847062 67151971 74997 50388451 72836 83934207 50362874 16845543 81456 81771 67136455 33623075 16849442 100696613 82574 83286 83577 16852101 84199 33607712 } zzz={ 79199 16848761 83893799 70029 76217 16854401 16839 16853836 50370644 145057 79338 81773 16849133 83891875 } www={ 100693891 72513 16844226 33606062 16854968 16858108 33608429 16845608 67128408 33611952 50382602 67148972 67149505 50368894 78657 134238974 67119739 50362812 16833431 16852778 50353593 50378671 50383395 50386109 67120625 67126402 67136958 67145067 67145907 67151704 67158147 83897335 83898254 83921034 83921077 83927103 100681910 100691733 117474361 } pppp={ 50350929 168.36935 33589252 } rrrrr={ 322 482.865 } ### Other stuff in the file looks like this ### info_about_this=blah header=85095 Header=words_with_underlines date=1938.08.22 that=2437 dummy=funny }
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Now, open the
Replace
dialog (Ctrl + H
)-
SEARCH
(?-s)^(\w+)={(.+)\h+}$|(^)?\h+(\d+(?:\.\d+)?)(?=.+¤(\w+))|¤.+
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REPLACE
(?2\2¤\1)?4(?3:\r\n)\5=\4
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Tick the
Wrap around
option -
Un-tick all other options
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Click ONCE, only, on the
Replace All
button
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=> You should get this intermediate text:
82={ # This is the root, used for each main entry. All parameters are placed under it. In this case, these are safe to ignore. ### The section below has parameters which need our attention to be fixed with RegEx ### 16835961¤xx 16847062 67151971 74997 50388451 72836 83934207 50362874 16845543 81456 81771 67136455 33623075 16849442 100696613 82574 83286 83577 16852101 84199 33607712¤yyyy 79199 16848761 83893799 70029 76217 16854401 16839 16853836 50370644 145057 79338 81773 16849133 83891875¤zzz 100693891 72513 16844226 33606062 16854968 16858108 33608429 16845608 67128408 33611952 50382602 67148972 67149505 50368894 78657 134238974 67119739 50362812 16833431 16852778 50353593 50378671 50383395 50386109 67120625 67126402 67136958 67145067 67145907 67151704 67158147 83897335 83898254 83921034 83921077 83927103 100681910 100691733 117474361¤www 50350929 168.36935 33589252¤pppp 322 482.865¤rrrrr ### Other stuff in the file looks like this ### info_about_this=blah header=85095 Header=words_with_underlines date=1938.08.22 that=2437 dummy=funny }
Now, click a SECOND time on the
Replace All
button=> And here is your expected OUTPUT text :
82={ # This is the root, used for each main entry. All parameters are placed under it. In this case, these are safe to ignore. ### The section below has parameters which need our attention to be fixed with RegEx ### xx=16835961 yyyy=16847062 yyyy=67151971 yyyy=74997 yyyy=50388451 yyyy=72836 yyyy=83934207 yyyy=50362874 yyyy=16845543 yyyy=81456 yyyy=81771 yyyy=67136455 yyyy=33623075 yyyy=16849442 yyyy=100696613 yyyy=82574 yyyy=83286 yyyy=83577 yyyy=16852101 yyyy=84199 yyyy=33607712 zzz=79199 zzz=16848761 zzz=83893799 zzz=70029 zzz=76217 zzz=16854401 zzz=16839 zzz=16853836 zzz=50370644 zzz=145057 zzz=79338 zzz=81773 zzz=16849133 zzz=83891875 www=100693891 www=72513 www=16844226 www=33606062 www=16854968 www=16858108 www=33608429 www=16845608 www=67128408 www=33611952 www=50382602 www=67148972 www=67149505 www=50368894 www=78657 www=134238974 www=67119739 www=50362812 www=16833431 www=16852778 www=50353593 www=50378671 www=50383395 www=50386109 www=67120625 www=67126402 www=67136958 www=67145067 www=67145907 www=67151704 www=67158147 www=83897335 www=83898254 www=83921034 www=83921077 www=83927103 www=100681910 www=100691733 www=117474361 pppp=50350929 pppp=168.36935 pppp=33589252 rrrrr=322 rrrrr=482.865 ### Other stuff in the file looks like this ### info_about_this=blah header=85095 Header=words_with_underlines date=1938.08.22 that=2437 dummy=funny }
The nice thing is that is you try to click a THIRD time, on the Replace All button, nothing else occurs ;-))
I must be out a couple of hours ! See you later for possible modifications and explanations on this regex S/R !
Best regards,
guy038
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@guy038
Thank you so, so much for this! Your RegEx is doing exactly what I needed! I only did a small modification to it to permit matches with indents. I have yet to check how foolproof it is in the long run and whether it would be suitable for other, similar cases in other files I’m working on, but so far it is working perfectly!To be exact, it works perfectly when it is done at a specific stage among a couple dozen other RegEx steps needed for this file, at the point when all other, less problematic cases of “xxx={yyyy}” strings have been fixed, leaving only those behind which need this specific step. However, that is not a problem at all - RegEx works in a way which requires specific order of steps sometimes, and even more so when there is higher complexity involved. In my projects it happens frequently, so I have to do a lot of trial and error to figure out the correct order of replaces. Moreover, these sorts of projects are incredibly interesting for me!
In case anyone needs the version I used with indent included - I simply added
\h*
after^
:
(?-s)^\h*(\w+)={(.+)\h+}$|(^)?\h+(\d+(?:\.\d+)?)(?=.+¤(\w+))|¤.+
@Terry-R
Thank you so much for your version as well! It seems to be working as well, though it is less stable and higher maintenance than the one by @guy038. However, it is still very useful as it has given me ideas and solutions for several other RegEx I am using for these files, so thank you!@Alan-Kilborn
I think there is no need to dwell on that matter. There was no harm done whatsoever. How we perceive things is highly individual and biased, depending on the culture, personality and so on. In this case ‘rude’ is a bit extreme wording, hence I added “-ish” there. That comment of mine referred chiefly to the last phrase “I wouldn’t want to even take a stab at an answer yet.”, and the clearly annoyed ‘tone’ because of merely forgetting to add specific markup. Although incredibly helpful for readers, one could phrase such issues more politely. -
@guy038
Sorry for multiple replies (again)! I forgot to ask, if it is not trouble, could you please explain your RegEx? These kinds of cases are beyond my current understanding and I’m really interested in learning and improving my skills! Also, this is an unusual and complex case, so someone else could find this useful as well!Thank you again, for your help, time and patience! :-)
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Also, there’s no rush, take your time, everyone! I’m sorry if I sounded rushing. I was just trying to write down all while I remembered.
Thank you for your help, everyone!
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Hi, @grimaldas-grydas and All,
To begin with, let’s me explain the general method used. we’re going to use a short line, from your INPUT text, which must be processed :
pppp={ 50350929 168.36935 33589252 }
The goal is to write the three numbers
50350929
,168.36935
and33589252
, each one on a different line, and prefixed with the stringpppp
, located before the=
sign, in order to get :pppp=50350929 pppp=168.36935 pppp=33589252
The problem is that when the regex engine catches, successively, each number, it does not know anymore the
pppp
string, located at the beginning of current line !So my idea was to swap the list of numbers and the string
pppp
before the equal sign and separate these two ranges with a temporary char, not present in your data !So, after a first regex S/R, we get the temporary text, below :
50350929 168.36935 33589252¤pppp
With this new layout, when the regex engine matches a number ( integer / decimal ) it is fairly easy, with a look-head structure, to store, at each time, the string after the temporary
¤
char, ending the current line !Then, with a second regex S/R, we finally get our expected text :
pppp=50350929 pppp=168.36935 pppp=33589252
Before we get into the details, it is IMPORTANT to point out that I found out a case where my previous regex S/R did not work ! So, you’ll have to use the second version, below !
The complete regex S/R, where I added the
\h*
part that you mentioned and where I fixed the bug, is :-
SEARCH
(?-s)^\h*(\w+)={(.+)\h+}$|(^)?\h+(\d+(?:\.\d+)?)(?=.*¤(\w+))|¤.+
-
REPLACE
(?2\2¤\1)?4(?3:\r\n)\5=\4
can be split into
2
consecutive regex S/R, which are completely independent :-
The Search/Replacement
A
, which creates the intermediate text :-
SEARCH
(?-s)^\h*(\w+)={(.+)\h+}$
-
REPLACE
?2\2¤\1
-
-
The Search/Replacement
B
, which gets the expected and final text-
SEARCH
(?-s)(^)?\h+(\d+(?:\.\d+)?)(?=.*¤(\w+))|¤.+
-
REPLACE
?4(?3:\r\n)\5=\4
-
The groups, defined by the
A
andB
search regexes are :(?x-s) ^ \h* (\w+) = { (.+) \h+ } $ ¯¯¯ ¯¯ Gr 1 Gr 2 (?x-s) (^)? \h+ ( \d+(?: \. \d+ )? ) (?= .* ¤ (\w+) ) | ¤ .+ ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯¯¯ Gr 3 Gr 4 Gr 5
Note, that I use the free-spacing mode
(?x)
for a better readability and each regex contains the(?-s)
in-line modifier which means that any regex.
char will match a single standard character ( not EOL ones )-
In search regex
A
:-
The part
^\h*(\w+)=
matches the word string, stored as group1
, after possible leading blank chars, till an=
character -
The part
{(.+)\h+}$
matches a literal{
char, then any non-null range of chars, each number preceded with space(s), which is stored as group2
, till space char(s) and a closing}
char, ending the current line
-
-
In replacement regex
A
:?2\2¤\1
, which should be exactly expressed as(?2\2¤\1)
, is a conditional replacement syntax, which means that IF group2
exists, it must rewrite the group2
first,\2
( i.e. the numbers only ), then the literal char¤
and finally group1
( the stringpppp
)
-
Now, the search regex
B
contains two alternatives :-
The first alternative
(?-s)(^)?\h+(\d+(?:\.\d+)?)(?=.*¤(\w+))
-
The middle part
(\d+(?:\.\d+)?)
matches any integer or decimal number, which is stored as group4
. Note the optional non-capturing group(?:\.\d+)?
in the case of a decimal number -
The first part
(^)?\h+
matches matches the blank char(s), preceding a number. Remark that, if the leading blank char(s) begins current line, the optional group3
,(^)?
, is then defined -
The final part
(?=.*¤(\w+))
, is a look-ahead structure, not included in the final match, but which must be true in order to get an effective match. So current matched number must be followed by a range, possibly null, of characters till the temporary char¤
and the ending stringpppp
-
-
The second alternative
¤.+
, which is used when current parsing position of the regex engine is at the¤
location, after the processed numbers. This second alternative, without any group, simply matches the temporary¤
char and all subsequent chars of current line, and should be deleted in replacement !
-
-
In replacement regex
B
:-
?4(?3:\r\n)\5=\4
, which should be exactly expressed as(?4(?3:\r\n)\5=\4)
, means that, IF group4
exists ( the numbers ), it must :-
Execute, first, the
(?3:\r\n)
conditional replacement. This replacement does not include a THEN part and, only, the regex\r\n
as an ELSE part, after the:
char. So, this means that if group3
does not exist ( number not at beginning of current line ) , it must insert a leading line-break ! -
Write the group
5
,\5
, followed with a literal=
sign -
Finally, write the group
4
( current number matched by the first alternative of search regexB
)
-
-
Note that, when matching the second alternative
¤.+
of the search regexB
, at end of current line, group4
is not defined. So, no action occurs in replacement. Thus, concretely, this means that the string¤pppp
is deleted !
-
Remarks :
-
The S/R
A
andB
are independent. As a demonstration :-
When executing, first, the search regex
A
, as no¤
character already exists, each alternative of the search regexB
cannot match -
When executing, in a second time, the search regex
B
, as the intermediate text ( after runningA
) does not contain any{
nor}
characters, obviously, the search regexA
cannot match, too !
-
Thus, we can merge these two successive S/R in one regex S/R only ! You’ll note that :
-
The redundant part
(?-s)
, at beginning of regex S/RB
, is omitted -
The replacement of S/R
A
,?2\2¤\1
, must be enclosed between parentheses,(?2\2¤\1)
, in order to not include the replacement section of S/RB
As a conclusion, the complete regex S/R, with the free-spacing mode in the search part, is :
-
SEARCH
(?x-s) ^ \h* ( \w+ ) = { ( .+ ) \h+ } $ | (^)? \h+ ( \d+ (?:\.\d+)? ) (?= .* ¤ ( \w+ ) ) | ¤ .+
-
REPLACE
(?2\2¤\1)?4(?3:\r\n)\5=\4
And outputs the expected text, after two consecutive clicks on the
Replace All
button !
As mentioned in my last post, if we try to click a third time on the
Replace All
button, luckily, nothing else occurs ! Why ? Easy : as brace{
or}
characters nor¤
character exists in our final text, any alternative of the overall regex cannot match. Logical ;-))I just hope, @grimaldas-grydas, that these explanations help you a bit !
guy038
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