Help to replace signs

[serg oth]

Hello. I got a huge text doc and I can not replace signs in document, I tried only replace, but it replaces all document. I have a text

numric-:N1CK# deal OTHER!
SIGN-:J0HN# deal ADAM!
Zumric-:M1KE# deal TOGETHER!
numric-:SV3NN# deal KORY!
VOTE-:K!ND@# deal TOGETHER!
Zumric-:N4C# deal TOGETHER!
VOTE-:G@RR3TH# deal OTHER!

and I need

numric-:NICK# deal OTHER!
SIGN-:JOHN# deal ADAM!
Zumric-:MIKE# deal TOGETHER!
numric-:SVENN# deal KORY!
VOTE-:KINDA# deal TOGETHER!
Zumric-:NAC# deal together!
VOTE-:GARRETH# deal OTHER!

I need only replace text between (:) and (#) chars , want to replace 1-I, 0-O, 3-E, @-A etc.
Please help me to do that

[Alan Kilborn]

@serg-oth said in Help to replace signs:

want to replace 1-I, 0-O, 3-E, @-A etc.

You can do that using this technique:

Find: (0)|(1)|(2)|(3)|(4)
Replace: (?1O)(?2I)(?3Z)(?4E)(?5A)
Search mode: Regular expression
Note: I guessed about the 2 -> Z transformation!

For the “etc” part you just add more to the pattern.
Example, replace 5 with S:
Find: (0)|(1)|(2)|(3)|(4)|(5)
Replace: (?1O)(?2I)(?3Z)(?4E)(?5A)(?6S)

Note also that the number following the ?s in the Replace expression is one more than what you might think!

I need only replace text between (:) and (#) chars

For that part, we can apply the technique shown here:

https://community.notepad-plus-plus.org/post/62799

specifically:

SEARCH (?-i:BSR|(?!\A)\G)(?s:(?!ESR).)*?\K(?-i:FR)
REPLACE RR

where BSR = :, ESR = #, FR and RR are as I showed above.

Thus, completely, we have:

Find: (?-i::|(?!\A)\G)(?s:(?!#).)*?\K(?-i:(0)|(1)|(2)|(3)|(4))
Replace: (?1O)(?2I)(?3Z)(?4E)(?5A)
Search mode: Regular expression
Note: You must use Replace All to do the replacements

[serg oth]

@Alan-Kilborn could you,please write. how to convert it back as in begining?
from
numric-:NICK# deal OTHER!
SIGN-:JOHN# deal ADAM!
Zumric-:MIKE# deal TOGETHER!
numric-:SVENN# deal KORY!
VOTE-:KINDA# deal TOGETHER!
Zumric-:NAC# deal together!
VOTE-:GARRETH# deal OTHER!

to
numric-:N1CK# deal OTHER!
SIGN-:J0HN# deal ADAM!
Zumric-:M1KE# deal TOGETHER!
numric-:SV3NN# deal KORY!
VOTE-:K!ND@# deal TOGETHER!
Zumric-:N4C# deal TOGETHER!
VOTE-:G@RR3TH# deal OTHER!

only replace text between (:) and (#) chars

5 stars for you MAN! You are AWESOME)!!!

[Alan Kilborn]

@serg-oth said in Help to replace signs:

could you,please write. how to convert it back as in begining?

Hmm, I thought my explanation of the forward transform would have been enough to make something like that fairly obvious. Do you have any thoughts as to how you might do the reverse transform, other than asking me to do it?

[serg oth]

@Alan-Kilborn its only for me to know that kind of commands. Education only. Sorry for taking your time,man

[Alan Kilborn]

@Alan-Kilborn said in Help to replace signs:

Find: (0)|(1)|(2)|(3)|(4)
Replace: (?1O)(?2I)(?3Z)(?4E)(?5A)

So if we look back at that…

We are looking for 0 or 1 or 2 or 3 or 4 (from the “Find” expression)

When we find one of those, at replace time we look at what we found, and replace it with something else.

0 goes to O, 1 goes to I, etc.

So, how hard is it to go the other way?

You’d just swap the values in the find/replace specification.

So the first one might be:
F: (O)
R: (?10)

Get it?

[Alan Kilborn]

@Alan-Kilborn said in Help to replace signs:

R: (?10)

Actually, it is not that simple. :-(

?10 here is interpreted as a 10 not as a 1 followed by a 0.

@serg-oth

Ok, since that may not be easy to understand, I’ll give you the full solution to the reverse transform, rather than assisting you to think it through:

Find: (?-i::|(?!\A)\G)(?s:(?!#).)*?\K(?-i:(O)|(I)|(Z)|(E)|(A))
Replace: (?{1}0)(?{2}1)(?{3}2)(?{4}3)(?{5}4)
Search mode: Regular expression
Note: You must use Replace All to do the replacements

[serg oth]

@Alan-Kilborn I got it, bro. What about A-@, S-$, i-!
F(A)
R(?@)
right?

[Alan Kilborn]

@serg-oth

I got it bro

You are at least thinking about how to apply it! Which is good!

F(A)

R(?@)

Close.

OK, so here’s the formula:

In the Find expression, you look from left to right at the parentheses groupings, ( and ). The first pair is group 1, the second pair is group 2, etc.

Then, in Replace, you use the group number after the ?.

So, in this simpler case:

Find: (O)|(I)
Replace: (?{1}0)(?{2}1)

you want to replace group number 1 (the O match) with 0, so you use ?{1} before the 0 in the replace.
Similarly, the I is in group number 2 in the find, so you refer to it as ?{2} in the replace.

You can think of the ? as “is this group number matched?”.

[serg oth]

@Alan-Kilborn Thanks a lot. Everything is clear