Replace sets of numbers in a given position with 0

Fernando Bernabeu

Hello!
I’ve been trying to look for a solution to this problem I have by using Regular Expressions, but I’ve come up empty.
I have a pose file for a 3D model and the line I want to modify looks like this:

Hips: 5.5 5.5 2.8 -0.0248 -0.0071 -0.0215 1 1 1

The first three sets of numbers between spaces are rotation, the next three are position and the last three are size. The position sets of numbers can have up to 4 decimal numbers.
What I want to do is replace the position sets of numbers with 0, so I could end up with a line like this:

Hips: 5.5 5.5 2.8 0 0 0 1 1 1

Would there be a way to specifically replace the 4th, 5th and 6th set of numbers between spaces with 0?
Big TIA

Neil Schipper

@fernando-bernabeu

Here’s a solution with a very loose spec. It doesn’t care what the contents of the first 4+3=7 fields are, only that they are chunks of text separated by a single space.

Ctl-h
Fi: ^(?:(?:.*? ){4})\K((?:.*? ){3})
Re: 0 0 0 <=== trailing space needed!
Mode=regex; option box unchecked

Then: Replace All

What I want to do is replace the position sets of numbers with 0

You don’t actually state that you want to do this for every occurrence in a file but that’s what I’ve assumed.

Neil Schipper

Here’s an expression with a somewhat tighter spec, in case file contains lines with different starting text you wish to ignore: ^Hips: (?:(?:.*? ){3})\K((?:.*? ){3})

We can make it even tighter, such as validating that the other pieces consist of digits, maybe with decimal points, etc.

Fernando Bernabeu

@neil-schipper
Thank you very much! That worked wonderfully!