Macro for Open, Find and Replace and Save

[José Luis Montero Castellanos]

@Lycan-Thrope :
I will take your comments into account.
Greetings :-)

[Jaguar Asad]

@guy038 said in Macro for Open, Find and Replace and Save:

Hello, @josé-luis-montero-castellanos, @aln-kilborn and all,

@josé-luis-montero-castellanos, regarding your regex S/R :

• SEARCH (?s)(<St)(.)(/S)(.)(<Xt)(.)(/X)|(<Xt)(.)(/X)(.)(<St)(.)(/S)

• REPLACE ?1\5\2\7\4\1\6\3:${12}${9}${14}${11}${8}${13}${10}

Why do you need the leading in-line modifier (?s), in the search part ? Do you mean that the single char . in group 2, 4, 6, 9, 11 and 13 may also represent a line-break char ( \r or \n ) ?

I suppose not ! Then, your correct search regex is rather :

(?-s)(<St)(.)(/S)(.)(<Xt)(.)(/X)|(<Xt)(.)(/X)(.)(<St)(.)(/S)

where any . single char will represent a non-break char, only !

---

Now, I noticed that the groups used, in replacement, for each alternative of the search regex, are in the same order ! Then, you can use, preferably, a specific feature of the Boost Regex engine, called Branch Reset

For instance, in your regex, the numbers of each group are :

(?-s)(<St)(.)(/S)(.)(<Xt)(.)(/X)|(<Xt)(.)(/X)(.)(<St)(.)(/S)
Gr : 1    2  3   4  5    6  7   |8    9  10  11 12   13 14  

If we use the Branch Reset feature the search regex becomes :

(?-s)(?|(<St)(.)(/S)(.)(<Xt)(.)(/X)|(<Xt)(.)(/X)(.)(<St)(.)(/S))
Gr:     1    2  3   4  5    6  7   |1    2  3   4  5    6  7

Thus, your entire regex S/R can be simplified as below :

• SEARCH (?-s)(?|(<St)(.)(/S)(.)(<Xt)(.)(/X)|(<Xt)(.)(/X)(.)(<St)(.)(/S))

• REPLACE \5\2\7\4\1\6\3

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For instance, given this INPUT text :

<St2/S4<Xt6/X
<Xt9/XB<StD/S

You would get the OUTPUT text, below :

<Xt2/X4<St6/S
<St9/SB<XtD/X

Notes :

• The Regular expression option must be selected

• Preferably, tick the [Wrap around](https://www.ahijoy.com/) option

Best Regards,

guy038

I tried it but didn’t work