I would like to group all similar domains, not by alphabet.
-
Hi, @mohammad-al-thobiti, @peterjones, @coises and All,
@mohammad-al-thobiti, you should use the @coises’s approach, which works much better than mine !!
In addition, in my previous post, I omitted to add the reverse regex to use, once your sort would be done :-((
While the @coise’s method avoids any additional S/R and correctly mentions the reverse regex to run after the sort operation
Note that I slightly Modified the first two @coises’s regexes to get more rigorous ones ( See, at the end of this post the reason for these changes )
Thus, I would propose this road map :
-
First, from the @coises’s post, I would use this alternate regex formulation :
-
SEARCH
(?x) ( [^.\r\n]+ ) \. ( [^!\r\n]+ )
-
REPLACE
\2!\1
-
Click
14th
times on theReplace All
button
-
-
Run the
Edit > Line Operations > Sort Lines Lexicographically Ascending
option ( No [rectangular] selection is needed as you just keep the addresses ) -
Thirdly, once the sort done, from the @coises’s post, use the alternate reverse regex S/R :
-
SEARCH
(?x) ( [^!\r\n]+ ) ! ( [^.\r\n]+ )
-
REPLACE
\2.\1
-
Click
14th
times on theReplace All
button
-
=> You should get all your addresses back, in the right order
Best Regards,
guy038
P.S. :
@coises uses the
\s
class of characters, which is equivalent to any of the25
characters, below, with the regex :(?x) \t | \n | \x{000B} | \x{000C} | \r | \x{0020} | \x{0085} | \x{00A0} | x{1680} | [\x{2000}-\x{200B}] |\x{2028} | \x{2029} | \x{202F} | \x{3000}
In the highly unlikely event that one of these characters is included in some addresses, I preferred to use the
[\r\n]
regex, which ONLY avoids these 2EOL
chars in addresses, instead of using the\s
regex ! -
-
Thank you for your efforts, my friends.
I would like to tell you that the result is excellent.
But an idea came to me: why not just delete the subdomain and keep only the main domain and then delete the similar ones?
Is there a way to delete long link extensions? And keep the main domain?Example:
-
-
Hi, @mohammad-al-thobiti and All,
May I rephrase your question ? Let’s see if we mean the same goal !
So, for example, from the INPUT text, below :
abc.def.ghi.jkl.example.com all.net abc.def.example.com abc.my_site.com abc.def.ghi.all.net my_site.com abc.def.all.net abc.def.ghi.jkl.mno.opq.my_site.com example.com
With the following regex S/R :
SEARCH
(?x) ^ (?: [\w-]+ \. )* ( [\w-]+ \. [\w-]+ ) $
REPLACE
\1
We would get that text :
example.com all.net example.com my_site.com all.net my_site.com all.net my_site.com example.com
Then, using the
Edit > Line Operations > Remove Duplicates Lines
option, we would end up with this OUTPUT :example.com all.net my_site.com
If this is exactly what you expect to, just go ahead !
BR
guy038
-
I would like to thank you for your useful information and those who contributed to this topic.
This article has become my reference. It works nicely. Yes, we mean the same goal !
Right now. If you can sort or collect them from the most similar domains, please let me know.There are too many lines, starting with the most similar domain.
Reason: To find the most “worried” domains because it takes many lines. I will delete them later, as you told us. However, the goal is to discover more domains with many characters or long URLs and I will block them in other programs.
How can this be done?
-
@Mohammad-Al-Thobiti said in I would like to group all similar domains, not by alphabet.:
If you can sort or collect them from the most similar domains, please let me know.
Here’s a way; enter:
Find what :
^(!*([^\r\n]+))\R(!*)\2$
Replace with :!\3\1
and Replace All repeatedly until there are no more changes.
Each line in the result will have an exclamation point at the beginning for each additional occurrence of the following text; so:
argh.com argh.com asdf.net asdf.net asdf.net asdf.net ef.org ef.org ef.org ef.org ef.org fasde.com fasde.com fasde.com fasde.com gorch.net gorch.net gorch.net
would become:
!argh.com !!!asdf.net !!!!ef.org !!!fasde.com !!gorch.net
You can then sort that to put them in order by the number of exclamation points at the beginning.
-
Thank you. I will clarify the issue.
-
@Mohammad-Al-Thobiti said in I would like to group all similar domains, not by alphabet.:
Thank you. I will clarify the issue.
Using the method I suggested, if you start with:
zindova.net zindova.net zinfandelreviews.net zinfandelreviews.net zingardi.net zingcoach.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net ziobaweek.net ziomik.net zioninfosystems.net zioninfosystems.net zip-archive.net
and do the repeated Replace Alls, then sort, you’ll get:
!!!!!!!!!!!!!!!!!!!!!!!!zinoiosijek031.net !zindova.net !zinfandelreviews.net !zioninfosystems.net zingardi.net zingcoach.net ziobaweek.net ziomik.net zip-archive.net
The first line represents 25 occurrences — there are 24 leading exclamation points. Each of the next three lines represent two occurrences (one leading exclamation point). The remaining lines occurred only once.
Is that not what you needed to accomplish?
-
Hello, @mohammad-al-thobiti, @peterjones, @coises and All,
Oh, @coises, your method of finding out how many times each address occurs, is very elegant and really clever ! I’d never have thought of such sophistication on my own :-((
So, @mohammad-al-thobiti, starting with this INPUT file :
zindova.net zindova.net zinfandelreviews.net zinfandelreviews.net zingardi.net zingcoach.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net zinoiosijek031.net ziobaweek.net ziomik.net zioninfosystems.net zioninfosystems.net zip-archive.net zip-archive.net zip.net zip.net zip.net zipaphoto.net zipbah.net zipexpose.net ziph.next ziph.next
I’m using the @coises’s regex, that I slightly modified :
SEARCH
(?x-s) ^ ( !* ( .+ ) ) \R ( !* ) \2 $
REPLACE
!\3\1
- Run it several times, in order tp get the message
Replace All: 0 occurrences were replaced
=> You should get this text :
!zindova.net !zinfandelreviews.net zingardi.net zingcoach.net !!!!!!!!!!!!!!!!!!!!!!!!zinoiosijek031.net ziobaweek.net ziomik.net !zioninfosystems.net !zip-archive.net !!zip.net zipaphoto.net zipbah.net zipexpose.net !ziph.next
Now, we just add one
!
character to get the exact number of occurrences of each addressSEARCH
(?x-s) ^ (?= . )
REPLACE
!
!!zindova.net !!zinfandelreviews.net !zingardi.net !zingcoach.net !!!!!!!!!!!!!!!!!!!!!!!!!zinoiosijek031.net !ziobaweek.net !ziomik.net !!zioninfosystems.net !!zip-archive.net !!!zip.net !zipaphoto.net !zipbah.net !zipexpose.net !!ziph.next
- Then, run the
Edit > Line Operations > Sort Lines Lexicographically Ascending
=> We get this sorted text :
!!!!!!!!!!!!!!!!!!!!!!!!!zinoiosijek031.net !!!zip.net !!zindova.net !!zinfandelreviews.net !!zioninfosystems.net !!zip-archive.net !!ziph.next !zingardi.net !zingcoach.net !ziobaweek.net !ziomik.net !zipaphoto.net !zipbah.net !zipexpose.net
Finally, runing the four regex S/R, below :
SEARCH (?x-s) ^ ! (?= [^!\r\n]+ ) REPLACE 1\t SEARCH (?x-s) ^ !! (?= [^!\r\n]+ ) REPLACE 2\t SEARCH (?x-s) ^ !!! (?= [^!\r\n]+ ) REPLACE 3\t SEARCH (?x-s) ^ !!!!!!!!!!!!!!!!!!!!!!!!! (?= [^!\r\n]+ ) REPLACE 25\t
=> You should end up with this OUTPUT text :
25 zinoiosijek031.net 3 zip.net 2 zindova.net 2 zinfandelreviews.net 2 zioninfosystems.net 2 zip-archive.net 2 ziph.next 1 zingardi.net 1 zingcoach.net 1 ziobaweek.net 1 ziomik.net 1 zipaphoto.net 1 zipbah.net 1 zipexpose.net
Which should be a practical document to exploit !
Best Regards,
guy038
- Run it several times, in order tp get the message
-
@ guy038 and All,
Thank you my friends for the amazing results.
We have received the correct information. The most commonly used domains cleverly.
In any case, as you can see in the picture, the outcome is wonderful.
How do I write the code like this that you mentioned:
SEARCH (?x-s) ^ ! (?= [^!\r\n]+ ) REPLACE 1\t SEARCH (?x-s) ^ !! (?= [^!\r\n]+ ) REPLACE 2\t SEARCH (?x-s) ^ !!! (?= [^!\r\n]+ ) REPLACE 3\t SEARCH (?x-s) ^ !!!!!!!!!!!!!!!!!!!!!!!!! (?= [^!\r\n]+ ) REPLACE 25\t
Did I write until I reached Col: 6,597? I think it is difficult and takes a lot of time. And I want to thank all of you for all your efforts on this fascinating topic.
-
@guy038 OK, I’ll take the bait… If you really want to count exclamation points:
Add the missing exclamation point, but also add a separator:
Find what :
^(!*)
Replace with :$1!/\t
Now, group by tens:
Find what :
(!{10})+
Replace with :$0/
followed by:
Find what :
!{10}
Replace with :!
Repeat the above two steps until the first step finds nothing.
Now, count the exclamation points in each digit and remove the forward slashes:
Find what :
(?:(!{9})|(!{8})|(!{7})|(!{6})|(!{5})|(!{4})|(!{3})|(!{2})|(!{1})|())/
Replace with :(?{1}9)(?{2}8)(?{3}7)(?{4}6)(?{5}5)(?{6}4)(?{7}3)(?{8}2)(?{9}1)(?{10}0)
This assumes there are no exclamation points or forward slashes elsewhere in the text. Of course, the forward slash (
/
) can be replaced with any character that is not in use. -
Hi, @mohammad-al-thobiti and All,
Let’s recapitulate from the very beginning !
If we start with this kind of INPUT text :
127.0.0.1 a.z.xy.dummy-hyphen.org 127.0.0.1 a.example.com 127.0.0.1 cdef.x.example.com 127.0.0.1 my_site.net 127.0.0.1 b.dummy-hyphen.org 127.0.0.1 b.cde.fgh.example.com 127.0.0.1 abc.defgji.kkkkk.my_site.net 127.0.0.1 cd.xyztuv.ab-cd.4567.example.com 127.0.0.1 dummy-hyphen.org 127.0.0.1 example.com
With the following regex S/R :
SEARCH
(?x) ^ \Q127.0.0.1 \E \h+ (?: [\w-]+ \. )* ( [\w-]+ \. [\w-]+ ) $
REPLACE
\1
=> We just keep the main domain ;
dummy-hyphen.org example.com example.com my_site.net dummy-hyphen.org example.com my_site.net example.com dummy-hyphen.org example.com
Of course, your present file deals with about
181,170
lines !So, instead of using the last @coises’s method to find out the different occurrences of each line ( again, a very clever method ! ), I will simplify the goal by using a
Python
script to get the job done more quickly !This script is an adaptation from a @alan-kilborn’s script. I named this script
Count_Strings_Occurences.py
# -*- coding: utf-8 -*- ''' Adapted from : https://community.notepad-plus-plus.org/topic/20598/show-a-list-of-same-word-before-replacement/2 and .../20 By DEFAULT, this script PASTES, in a NEW tab, a SORTED list of ALL the STRINGS of the CURRENT file, with their NUMBER of occurrences IF a NORMAL selection EXISTS, the script PASTES a SORTED list of ALL the STRINGS of the SELECTION, with their NUMBER of occurrences NOTES : - The CURRENT file processed DO NOT need to be SORTED, in any way ! - If you want a SORTED list of ALL the LINES with their NUMBER of occurrences, don't FORGET to INCLUDE all the POSSIBLE chars of the lines in the REGEX ! For example, if file may contain the line 'zip-archive.net', the REGEX, after editor.research, should be r'[\w.-]+', which includes the DOT and the DASH ! ''' from Npp import editor sel_start = 0 sel_end = editor.getLength() # Refer to : https://community.notepad-plus-plus.org/topic/22378/pythonscript-ops-on-selection-if-any-all-text-otherwise/3 sel_start, sel_end = editor.getUserCharSelection() word_matches = [] def match_found(m): word_matches.append(editor.getTextRange(m.span(0)[0], m.span(0)[1])) editor.research(r'[\w.-]+', match_found, 0 , sel_start, sel_end) histogram_dict = {} for word in word_matches: if word not in histogram_dict: histogram_dict[word] = 1 else: histogram_dict[word] += 1 output_list = [] for k in histogram_dict: output_list.append('{0:.<50} {1}'.format(k, histogram_dict[k])) #for k in histogram_dict: output_list.append('{}={}'.format(k, histogram_dict[k])) # INITIAl format of Alan Kilborn # For SPECIFICATIONS on the OUTPUT format, refer to : # https://doc.python.org/2.7/library/string.html#format-specification-mini-language # https://doc.python.org/2.7/library/string.html#format-examples output_list.sort() editor.copyText('\r\n'.join(output_list)) notepad.new() editor.paste() # console.clear() ; editor.research (r'\w+', lambda m: console.write (m.group(0) + '\n'))
- So, select the random list of
168
lines, below.
Note that I suppose that the
IPV4
addresses and the sub-domains were previously deletedzioninfosystems.net zingcoach.net ziph.net zinoiosijek031.net zindova.net zip.net zinoiosijek031.net zip-archive.net zinfandelreviews.net zindova.net zip.net zinoiosijek031.net zioninfosystems.net zip-archive.net ziomik.net zioninfosystems.net zip.net zindova.net zindova.net ziph.net ziph.net zinfandelreviews.net zinoiosijek031.net zindova.net zioninfosystems.net zindova.net zip.net zindova.net ziph.net zinfandelreviews.net zinoiosijek031.net ziph.net zinfandelreviews.net zinoiosijek031.net zinfandelreviews.net zinfandelreviews.net ziobaweek.net zinoiosijek031.net zinfandelreviews.net zindova.net zindova.net zinoiosijek031.net zinoiosijek031.net zipaphoto.net zinfandelreviews.net zinfandelreviews.net zingardi.net zip.net zipexpose.net zindova.net zip-archive.net zip-archive.net zindova.net zioninfosystems.net zipexpose.net zipaphoto.net ziph.net zipbah.net zinoiosijek031.net zinfandelreviews.net zip.net zindova.net zip.net zindova.net zingcoach.net zinoiosijek031.net zip.net ziomik.net zindova.net zinoiosijek031.net zioninfosystems.net ziph.net zioninfosystems.net zinfandelreviews.net zingardi.net zinoiosijek031.net zingardi.net zingardi.net ziph.net zingardi.net zinoiosijek031.net zinoiosijek031.net zingcoach.net zindova.net zip.net zindova.net zip-archive.net ziph.net ziobaweek.net zinfandelreviews.net zip.net zinoiosijek031.net zip.net ziomik.net zingardi.net zindova.net zinfandelreviews.net ziph.net ziobaweek.net zinoiosijek031.net zindova.net zinfandelreviews.net zip.net zingcoach.net zip-archive.net zip-archive.net zindova.net zinfandelreviews.net zingardi.net zioninfosystems.net zinoiosijek031.net ziph.net zioninfosystems.net ziobaweek.net zingcoach.net ziph.net zinoiosijek031.net ziobaweek.net zinfandelreviews.net zip.net zinoiosijek031.net ziph.net zinfandelreviews.net zindova.net zindova.net zindova.net zip-archive.net zip.net ziph.net zindova.net zioninfosystems.net zinoiosijek031.net zinoiosijek031.net ziph.net zinfandelreviews.net zip.net zingcoach.net zinfandelreviews.net zinoiosijek031.net zingardi.net zip-archive.net zip.net zinfandelreviews.net zinoiosijek031.net zindova.net zinfandelreviews.net zip.net zioninfosystems.net zingardi.net zioninfosystems.net zip-archive.net zingcoach.net zinoiosijek031.net ziomik.net zip.net zingardi.net zinfandelreviews.net zip-archive.net zindova.net ziomik.net zinoiosijek031.net zindova.net zinoiosijek031.net zinfandelreviews.net zinfandelreviews.net ziph.net zinoiosijek031.net zingardi.net
- Run the
Plugins > Python Script > Scripts > Count_Strings_Occurrences.py
Python script
=> At once, a new tab will open with all the results :
zindova.net....................................... 26 zinfandelreviews.net.............................. 24 zingardi.net...................................... 11 zingcoach.net..................................... 7 zinoiosijek031.net................................ 28 ziobaweek.net..................................... 5 ziomik.net........................................ 5 zioninfosystems.net............................... 12 zip-archive.net................................... 11 zip.net........................................... 18 zipaphoto.net..................................... 2 zipbah.net........................................ 1 zipexpose.net..................................... 2 ziph.net.......................................... 16
Note that the entries are sorted by the line contents, to easily access any of these !
-
Thus, do a zero-length RECTANGULAR selection of all the numbers of this new tab, at column
52
-
Run the
Edit > Line Operations > Sort Lines As Integers Descending
option
=> You should get your expected OUTPUT :
zinoiosijek031.net................................ 28 zindova.net....................................... 26 zinfandelreviews.net.............................. 24 zip.net........................................... 18 ziph.net.......................................... 16 zioninfosystems.net............................... 12 zingardi.net...................................... 11 zip-archive.net................................... 11 zingcoach.net..................................... 7 ziobaweek.net..................................... 5 ziomik.net........................................ 5 zipaphoto.net..................................... 2 zipexpose.net..................................... 2 zipbah.net........................................ 1
Here you are !
-
Proceed, in the same way, with your present file
-
Switch to your file tab ( selection and sort are not required )
-
Run again the
Plugins > Python Script > Scripts > Count_Strings_Occurrences.py
Python script -
In the opened new tab, do a zero-length RECTANGULAR selection of all the numbers, at column
52
-
Run the
Edit > Line Operations > Sort Lines As Integers Descending
option
Bingo !
Best Regards,
guy038
- So, select the random list of
-
Hello @ guy038 & All
Thank you. everything is ok, I need to add more than one domine to the Find what:
as you can see
this is the code:\.real-news-online.com, myvnc.com, 1example.com, 2example.com\s
is this the correct method?
How can I do this? -
-
.example.com|.example2.com|.example3.com\s
OK
-
-
-
@Mohammad-Al-Thobiti said in I would like to group all similar domains, not by alphabet.:
How can I do this?
At some point, you need to take the lessons you’ve been taught through the dozens of regexes that people have handed you throughout this discussion, and try to figure it out yourself.
----
Useful References
- Please Read Before Posting
- Template for Search/Replace Questions
- Formatting Forum Posts
- Notepad++ Online User Manual: Searching/Regex
- FAQ: Where to find other regular expressions (regex) documentation
----
Please note: This Community Forum is not a data transformation service; you should not expect to be able to always say “I have data like X and want it to look like Y” and have us do all the work for you. If you are new to the Forum, and new to regular expressions, we will often give help on the first one or two data-transformation questions, especially if they are well-asked and you show a willingness to learn; and we will point you to the documentation where you can learn how to do the data transformations for yourself in the future. But if you repeatedly ask us to do your work for you, you will find that the patience of usually-helpful Community members wears thin. The best way to learn regular expressions is by experimenting with them yourself, and getting a feel for how they work; having us spoon-feed you the answers without you putting in the effort doesn’t help you in the long term and is uninteresting and annoying for us.
-
@ PeterJones
Ok, Thank you -
Hi, @mohammad-al-thobiti and All,
Again, I’m going to simplify the problem, using a
Python
script, calledReplacements_Lists.py
, listed below :''' Refer to : https://community.notepad-plus-plus.org/topic/19889/ - Given TWO files : - A MAIN one, located in the MAIN view, containing a LIST of strings or lines - A SECOND one, located in the SECONDARY view, containing : - A LIST of strings to REPLACE, EACH followed with a TABULATION and its CORRESPONDING replacement string This script replaces EACH expression of the MAIN file by the CORRESPONDING replacement string, found in the SECONDARY file NOTES : - The REPLACEMENT strings may be ABSENT IF you do NOT write anything AFTER the TABULATION separator. Thus, these SPECIFIC searched strings will be DELETED - The strings of the MAIN file, NOT found in the SECONDARY file, are simply REWRITTEN - The LEADING strings of the SECONDARY file, NOT found in the MAIN file, are simply NOT used - The list of the DIFFeRENT ranges < SEARCHED string > \t < REPLACEMENT string > must END with a FINAL line-break or NOTHING else ( \z ) ''' from Npp import editor1, editor2 replacements = dict(line.split('\t') for line in editor2.getText().splitlines() if line) def replace_with(m): try: r = replacements[m.group()] except KeyError: r = m.group() return r editor1.rereplace('(?-s).+', replace_with)
So, just follow this road map :
-
Open your entire file containing all your records ( about
181,170
) in the main view -
Open your file containing the
1.027
lines, whose all the occurrences must be deleted in the main file -
Move this file in the secondary view ( IMPORTANT )
I suppose that these two files ONLY contains main domain names, one per line
Run the
Edit > Blank operations > Trim Leading and Trailing Space
option for the two files-
Now, in the secondary view, use this regex S/R :
-
SEARCH
(?<=.)$
-
REPLACE
\t
-
in order to produce a correct replacement list for some domain’s names by nothing
-
Move back to your file in the main view
-
Run the
Plugins > Python Script > Scripts > Replacements_List.py
option
=> Immediately, all the lines, of the
main
view, which match one of the lines of thesecondary
view, have been replaced with an empty line-
Run the
Edit > Line Operations > Remove Empty Lines
-
Finally save your uptaded file, in the main view
Voilà !
Best Regards,
guy038
P.S. :
If you need to install the
Python Script
plugin, follow this FAQ -